cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A215466 Expansion of x*(1-4*x+x^2) / ( (x^2-7*x+1)*(x^2-3*x+1) ).

Original entry on oeis.org

0, 1, 6, 38, 252, 1705, 11628, 79547, 544824, 3733234, 25585230, 175356611, 1201893336, 8237850373, 56462937882, 387002396990, 2652553009008, 18180866487757, 124613506702404, 854113665498719, 5854182112700460
Offset: 0

Views

Author

R. J. Mathar, Aug 11 2012

Keywords

Comments

From Peter Bala, Aug 05 2019: (Start)
Let U(n;P,Q), where P and Q are integer parameters, denote the Lucas sequence of the first kind. Then, excluding the case P = -1, the sequence ( U(n;P,1) + U(2*n;P,1) )/(P + 1) is a fourth-order linear divisibility sequence with o.g.f. x*(1 - 2*(P - 1)*x + x^2)/((1 - P*x + x^2)*(1 - (P^2 - 2)*x + x^2)). This is the case P = 3. See A000027 (P = 2), A165998 (P = -2) and A238536 (P = -3).
More generally, the sequence U(n;P,1) + U(2*n;P,1) + ... + U(k*n;P,1) is a linear divisibility sequence of order 2*k. As an example, see A273625 (P = 3, k = 3 and then sequence normalized with initial term 1). (End)

Crossrefs

Programs

  • Magma
    I:=[0,1,6,38]; [n le 4 select I[n] else 10*Self(n-1)-23*Self(n-2)+10*Self(n-3)-Self(n-4): n in [1..30]]; // Vincenzo Librandi, Dec 23 2012
    
  • Magma
    /* By definition: */ m:=20; R:=PowerSeriesRing(Integers(), m); [0] cat Coefficients(R!((1-4*x+x^2)/((x^2-7*x+1)*(x^2-3*x+1)))); // Bruno Berselli, Dec 24 2012
    
  • Maple
    A215466 := proc(n)
        if type(n,'even') then
            A000032(n)*combinat[fibonacci](3*n)/4 ;
        else
            combinat[fibonacci](n)*A000032(3*n)/4 ;
        end if;
    end proc:
  • Mathematica
    CoefficientList[Series[x*(1 - 4*x + x^2)/((x^2 - 7*x + 1)*(x^2 - 3*x + 1)), {x, 0, 40}], x] (* Vincenzo Librandi, Dec 23 2012 *)
    LinearRecurrence[{10,-23,10,-1},{0,1,6,38},30] (* Harvey P. Dale, Nov 02 2015 *)
  • PARI
    a(n)=([0,1,0,0; 0,0,1,0; 0,0,0,1; -1,10,-23,10]^n*[0;1;6;38])[1,1] \\ Charles R Greathouse IV, Nov 13 2015
    
  • PARI
    {a(n) = my(w=quadgen(5)^(2*n)); imag(w^2+w)/4}; /* Michael Somos, Dec 29 2022 */

Formula

a(n) = L(n)*F(3n)/4 if n even, = F(n)*L(3n)/4 if n odd, where L=A000032, F=A000045.
a(n) = 3*A004187(n)/4 + A001906(n)/4.
a(n) = 10*a(n-1) - 23*a(n-2) + 10*a(n-3) - a(n-4), a(0)=0, a(1)=1, a(2)=6, a(3)=38. - Harvey P. Dale, Nov 02 2015
a(n) = (1/4)*(Fibonacci(2*n) + Fibonacci(4*n)) = (1/4)*(A001906(n) + A033888(n)). - Peter Bala, Aug 05 2019
E.g.f.: exp(5*x/2)*(cosh(x)+exp(x)*cosh(sqrt(5)*x))*sinh(sqrt(5)*x/2)/sqrt(5). - Stefano Spezia, Aug 17 2019
a(n) = -a(-n) for all n in Z. - Michael Somos, Dec 29 2022

A273622 a(n) = (1/3)*(Lucas(3*n) - Lucas(n)).

Original entry on oeis.org

1, 5, 24, 105, 451, 1920, 8149, 34545, 146376, 620125, 2626999, 11128320, 47140601, 199691245, 845906424, 3583318305, 15179181851, 64300049280, 272379384749, 1153817597625, 4887649790376, 20704416783605, 87705316964399, 371525684705280, 1573808055889201, 6666757908429845
Offset: 1

Views

Author

Peter Bala, May 27 2016

Keywords

Comments

This is a divisibility sequence, that is, a(n) divides a(m) whenever n divides m. The sequence satisfies a linear recurrence of order 4. Cf. A273623.
More generally, for distinct integers r and s with r == s (mod 2), the sequence Lucas(r*n) - Lucas(s*n) is a fourth-order divisibility sequence. When r is even (resp. odd) the normalized sequence (Lucas(r*n) - Lucas(s*n))/(Lucas(r) - Lucas(s)), with initial term equal to 1, has the o.g.f. x*(1 - x^2)/( (1 - Lucas(r)*x + x^2)*(1 - Lucas(s)*x + x^2) ) (resp. x*(1 + x^2)/( (1 - Lucas(r)*x - x^2)*(1 - Lucas(s)*x - x^2) )) and belongs to the 3-parameter family of fourth-order divisibility sequences found by Williams and Guy, with parameter values P1 = (Lucas(r) + Lucas(s)), P2 = Lucas(r)*Lucas(s) and Q = 1 (resp. Q = -1). For particular cases see A004146 (r = 2, s = 0), A049684 (r = 4, s = 0), A215465 (r = 4, s = 2), A049683 (r = 6, s = 0), A049682 (r = 8, s = 0) and A037451 (r = 3, s = -1).

Crossrefs

Programs

  • Magma
    [1/3*(Lucas(3*n) - Lucas(n)): n in [1..25]]; // Vincenzo Librandi, Jun 02 2016
    
  • Maple
    #A273622
    with(combinat):
    Lucas := n->fibonacci(n+1) + fibonacci(n-1):
    seq(1/3*(Lucas(3*n) - Lucas(n)), n = 1..24);
  • Mathematica
    LinearRecurrence[{5,-2,-5,-1}, {1, 5, 24, 105}, 100] (* G. C. Greubel, Jun 02 2016 *)
    Table[1/3 (LucasL[3 n] - LucasL[n]), {n, 1, 30}] (* Vincenzo Librandi, Jun 02 2016 *)
  • PARI
    a(n)=([0,1,0,0; 0,0,1,0; 0,0,0,1; -1,-5,-2,5]^(n-1)*[1;5;24;105])[1,1] \\ Charles R Greathouse IV, Jun 07 2016

Formula

a(n) = (1/3)*( (2 + sqrt(5))^n + (2 - sqrt(5))^n - ((1 + sqrt(5))/2)^n - ((1 - sqrt(5))/2)^n ).
a(n) = -a(-n).
a(n) = 5*a(n-1) - 2*a(n-2) - 5*a(n-3) - a(n-4).
O.g.f.: x*(1 + x^2)/((1 - x - x^2 )*(1 - 4*x - x^2)).
a(n) = (A014448(n) - A000032(n))/3. - R. J. Mathar, Jun 07 2016
a(n) = Fibonacci(n) + Sum_{k=1..n} Fibonacci(n-k)*Lucas(3*k). - Yomna Bakr and Greg Dresden, Jun 16 2024
E.g.f.: (2*exp(2*x)*cosh(sqrt(5)*x) - 2*exp(x/2)*cosh(sqrt(5)*x/2))/3. - Stefano Spezia, Jun 17 2024

A085695 a(n) = Fibonacci(n)*Fibonacci(3n)/2.

Original entry on oeis.org

0, 1, 4, 34, 216, 1525, 10336, 71149, 486864, 3339106, 22881100, 156843721, 1074985344, 7368157369, 50501844796, 346145466850, 2372514562656, 16261461342589, 111457702083424, 763942486626661, 5236139616899400
Offset: 0

Views

Author

Emanuele Munarini, Jul 18 2003

Keywords

Comments

This is a divisibility sequence, that is, if n | m then a(n) | a(m). However, it is not a strong divisibility sequence. It is the case k = -3 of a 1-parameter family of 4th-order linear divisibility sequences with o.g.f. x*(1 - x^2)/( (1 - k*x + x^2)*(1 - (k^2 - 2)*x + x^2) ). Compare with A000290 (case k = 2) and A215465 (case k = 3). - Peter Bala, Jan 17 2014
a(n) + a(n+1) is the numerator of the continued fraction [1,...,1,4,...,4] with n 1's followed by n 4's. - Greg Dresden and Hexuan Wang, Aug 16 2021

Examples

			G.f. = x + 4*x^2 + 34*x^3 + 216*x^4 + 1525*x^5 + 10336*x^6 + ... - _Michael Somos_, Apr 23 2022
		

Crossrefs

Programs

  • Mathematica
    Array[Times @@ MapIndexed[Fibonacci[#]/First@ #2 &, {#, 3 #}] &, 21, 0] (* or *) LinearRecurrence[{4, 19, 4, -1}, {0, 1, 4, 34}, 21] (* or *)
    CoefficientList[Series[(x - x^3)/(1 - 4 x - 19 x^2 - 4 x^3 + x^4), {x, 0, 20}], x] (* Michael De Vlieger, Dec 17 2017 *)
  • MuPAD
    numlib::fibonacci(3*n)*numlib::fibonacci(n)/2 $ n = 0..35; // Zerinvary Lajos, May 13 2008
    
  • PARI
    a(n) = fibonacci(n)*fibonacci(3*n)/2 \\ Andrew Howroyd, Dec 17 2017

Formula

G.f.: ( x - x^3 )/( 1 - 4 x - 19 x^2 - 4 x^3 + x^4 ).
Recurrence: a(n+4) = 4*a(n+3) + 19*a(n+2) + 4*a(n+1) - a(n).
a(n) = a(-n) and A153173(n) = 1 + 10*a(n) for all n in Z. - Michael Somos, Apr 23 2022
Showing 1-3 of 3 results.