A202689 a(n) = (2n)! * (n+1)! / 2^(2n).
1, 1, 9, 270, 18900, 2551500, 589396500, 214540326000, 115851776040000, 88626608670600000, 92614806060777000000, 128364121200236922000000, 230285233433225038068000000, 523898906060586961604700000000, 1485253398681764036149324500000000
Offset: 0
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..100
- T. Piezas, Notes and conjectures on properties of polynomials, arising in "Construction Of Binomial Sums For π And Polylogarithmic Constants Inspired by BBP Formulas" (by Boris Gourévitch, Jesús Guillera Goyanes) and also relevant to further unpublished follow-up work by J. Cullen, T. Piezas, J. Guillera, and B. Gourevitch.
- Index to divisibility sequences
Crossrefs
Cf. A002414.
Programs
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Magma
[Factorial(2*n)*Factorial(n+1)/2^(2*n): n in [0..15]]; // Vincenzo Librandi, Feb 09 2012
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Mathematica
Table[(2n)!(n+1)!/2^(2n),{n,0,20}] (* Vincenzo Librandi, Feb 09 2012 *)
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PARI
a(n)=(2*n)!*(n+1)!>>(2*n) \\ Charles R Greathouse IV, Dec 23 2011
Formula
a(n) = (2n)!(n+1)! / 2^(2n).
a(n+1) = a(n)*(n^3 + 7/2*n^2 + 7/2*n + 1).
a(n+1) = a(n)*A002414(n+1) for n >= 0.
Comments