A129952 Binomial transform of A124625.
1, 1, 2, 6, 16, 40, 96, 224, 512, 1152, 2560, 5632, 12288, 26624, 57344, 122880, 262144, 557056, 1179648, 2490368, 5242880, 11010048, 23068672, 48234496, 100663296, 209715200, 436207616, 905969664, 1879048192, 3892314112
Offset: 0
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..1000
- Alice L. L. Gao and Sergey Kitaev, On partially ordered patterns of length 4 and 5 in permutations, arXiv:1903.08946 [math.CO], 2019.
- Alice L. L. Gao and Sergey Kitaev, On partially ordered patterns of length 4 and 5 in permutations, The Electronic Journal of Combinatorics 26(3) (2019), P3.26.
- Index entries for linear recurrences with constant coefficients, signature (4,-4).
Crossrefs
Programs
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Magma
m:=15; S:=&cat[ [ 1, 2*i ]: i in [0..m] ]; [ &+[ Binomial(j-1, k-1)*S[k]: k in [1..j] ]: j in [1..2*m] ]; // Klaus Brockhaus, Jun 17 2007
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Mathematica
LinearRecurrence[{4, -4}, {1, 1, 2, 6}, 30] (* G. C. Greubel, Jun 08 2016; corrected by Georg Fischer, Apr 02 2019 *)
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PARI
{m=29; print1(1, ",", 1, ","); for(n=2, m, print1(n*2^(n-2), ","))} \\ Klaus Brockhaus, Jun 17 2007
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Python
def A129952(n): return n<
1 else 1 # Chai Wah Wu, Oct 03 2024
Formula
a(0) = 1, a(1) = 1; for n > 1, a(n) = n*2^(n-2).
G.f.: (1-3*x+2*x^2+2*x^3)/(1-2*x)^2.
E.g.f.: (1/2)*(x*exp(2*x) + x + 2). - G. C. Greubel, Jun 08 2016
Extensions
Edited and extended by Klaus Brockhaus, Jun 17 2007
Comments