cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 18 results. Next

A262544 Records in A261422.

Original entry on oeis.org

1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 63, 72, 79, 84, 87, 88, 117, 126, 135, 142, 147, 150, 151, 153, 156, 159, 162, 168, 177, 198, 207, 213, 216, 219, 222, 226, 231, 261, 264, 270, 279, 297, 318, 342, 369, 375, 426, 429, 465, 513, 567, 591, 660, 663, 678, 681, 729, 820, 870, 963, 982, 1005
Offset: 1

Views

Author

N. J. A. Sloane, Oct 06 2015

Keywords

Crossrefs

A262545 Where records occur in A261422.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 110, 143, 154, 165, 176, 187, 198, 253, 283, 290, 293, 301, 314, 323, 334, 374, 383, 384, 391, 393, 404, 413, 424, 435, 454, 464, 474, 484, 494, 504, 514, 544, 575, 585, 595, 605, 615, 625, 635, 645, 686, 696, 706, 716, 726, 736, 746, 797, 807, 817
Offset: 1

Views

Author

N. J. A. Sloane, Oct 06 2015

Keywords

Crossrefs

A002113 Palindromes in base 10.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, 212, 222, 232, 242, 252, 262, 272, 282, 292, 303, 313, 323, 333, 343, 353, 363, 373, 383, 393, 404, 414, 424, 434, 444, 454, 464, 474, 484, 494, 505, 515
Offset: 1

Views

Author

Keywords

Comments

n is a palindrome (i.e., a(k) = n for some k) if and only if n = A004086(n). - Reinhard Zumkeller, Mar 10 2002
It seems that if n*reversal(n) is in the sequence then n = 3 or all digits of n are less than 3. - Farideh Firoozbakht, Nov 02 2014
The position of a palindrome within the sequence can be determined almost without calculation: If the palindrome has an even number of digits, prepend a 1 to the front half of the palindrome's digits. If the number of digits is odd, prepend the value of front digit + 1 to the digits from position 2 ... central digit. Examples: 98766789 = a(19876), 515 = a(61), 8206028 = a(9206), 9230329 = a(10230). - Hugo Pfoertner, Aug 14 2015
This sequence is an additive basis of order at most 49, see Banks link. - Charles R Greathouse IV, Aug 23 2015
The order has been reduced from 49 to 3; see the Cilleruelo-Luca and Cilleruelo-Luca-Baxter links. - Jonathan Sondow, Nov 27 2017
See A262038 for the "next palindrome" and A261423 for the "preceding palindrome" functions. - M. F. Hasler, Sep 09 2015
The number of palindromes with d digits is 10 if d = 1, and otherwise it is 9 * 10^(floor((d - 1)/2)). - N. J. A. Sloane, Dec 06 2015
Sequence A033665 tells how many iterations of the Reverse-then-add function A056964 are needed to reach a palindrome; numbers for which this will never happen are Lychrel numbers (A088753) or rather Kin numbers (A023108). - M. F. Hasler, Apr 13 2019
This sequence is an additive basis of order 3, see Cilleruelo, Luca, & Baxter and Sigg. - Charles R Greathouse IV, Apr 08 2025

References

  • Karl G. Kröber, "Palindrome, Perioden und Chaoten: 66 Streifzüge durch die palindromischen Gefilde" (1997, Deutsch-Taschenbücher; Bd. 99) ISBN 3-8171-1522-9.
  • Clifford A. Pickover, A Passion for Mathematics, Wiley, 2005; see p. 71.
  • Alfred S. Posamentier, Math Charmers, Tantalizing Tidbits for the Mind, Prometheus Books, NY, 2003, pages 50-52.
  • Paulo Ribenboim, The Little Book of Bigger Primes, Springer-Verlag NY 2004. See p. 120.
  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Subsequence of A061917 and A221221.
A110745 is a subsequence.
Union of A056524 and A056525.
Palindromes in bases 2 through 11: A006995 and A057148, A014190 and A118594, A014192 and A118595, A029952 and A118596, A029953 and A118597, A029954 and A118598, A029803 and A118599, A029955 and A118600, this sequence, A029956. Also A262065 (base 60), A262069 (subsequence).
Palindromic primes: A002385. Palindromic nonprimes: A032350.
Palindromic-pi: A136687.
Cf. A029742 (complement), A086862 (first differences).
Palindromic floor function: A261423, also A261424. Palindromic ceiling: A262038.
Cf. A004086 (read n backwards), A064834, A118031, A136522 (characteristic function), A178788.
Ways to write n as a sum of three palindromes: A261132, A261422.
Minimal number of palindromes that add to n using greedy algorithm: A088601.
Minimal number of palindromes that add to n: A261675.

Programs

  • GAP
    Filtered([0..550],n->ListOfDigits(n)=Reversed(ListOfDigits(n))); # Muniru A Asiru, Mar 08 2019
    
  • Haskell
    a002113 n = a002113_list !! (n-1)
      a002113_list = filter ((== 1) . a136522) [1..] -- Reinhard Zumkeller, Oct 09 2011
    
  • Haskell
    import Data.List.Ordered (union)
      a002113_list = union a056524_list a056525_list -- Reinhard Zumkeller, Jul 29 2015, Dec 28 2011
    
  • Magma
    [n: n in [0..600] | Intseq(n, 10) eq Reverse(Intseq(n, 10))]; // Vincenzo Librandi, Nov 03 2014
    
  • Maple
    read transforms; t0:=[]; for n from 0 to 2000 do if digrev(n) = n then t0:=[op(t0),n]; fi; od: t0;
    # Alternatively, to get all palindromes with <= N digits in the list "Res":
    N:=5;
    Res:= $0..9:
    for d from 2 to N do
      if d::even then
        m:= d/2;
        Res:= Res, seq(n*10^m + digrev(n),n=10^(m-1)..10^m-1);
      else
        m:= (d-1)/2;
        Res:= Res, seq(seq(n*10^(m+1)+y*10^m+digrev(n),y=0..9),n=10^(m-1)..10^m-1);
      fi
    od: Res:=[Res]: # Robert Israel, Aug 10 2014
    # A variant: Gets all base-10 palindromes with exactly d digits, in the list "Res"
    d:=4:
    if d=1 then Res:= [$0..9]:
    elif d::even then
        m:= d/2:
        Res:= [seq(n*10^m + digrev(n), n=10^(m-1)..10^m-1)]:
    else
        m:= (d-1)/2:
        Res:= [seq(seq(n*10^(m+1)+y*10^m+digrev(n), y=0..9), n=10^(m-1)..10^m-1)]:
    fi:
    Res; # N. J. A. Sloane, Oct 18 2015
    isA002113 := proc(n)
        simplify(digrev(n) = n) ;
    end proc: # R. J. Mathar, Sep 09 2015
  • Mathematica
    palQ[n_Integer, base_Integer] := Module[{idn = IntegerDigits[n, base]}, idn == Reverse[idn]]; (* then to generate any base-b sequence for 1 < b < 37, replace the 10 in the following instruction with b: *) Select[Range[0, 1000], palQ[#, 10] &]
    base10Pals = {0}; r = 2; Do[Do[AppendTo[base10Pals, n * 10^(IntegerLength[n] - 1) + FromDigits@Rest@Reverse@IntegerDigits[n]], {n, 10^(e - 1), 10^e - 1}]; Do[AppendTo[base10Pals, n * 10^IntegerLength[n] + FromDigits@Reverse@IntegerDigits[n]], {n, 10^(e - 1), 10^e - 1}], {e, r}]; base10Pals (* Arkadiusz Wesolowski, May 04 2012 *)
    nthPalindromeBase[n_, b_] := Block[{q = n + 1 - b^Floor[Log[b, n + 1 - b^Floor[Log[b, n/b]]]], c = Sum[Floor[Floor[n/((b + 1) b^(k - 1) - 1)]/(Floor[n/((b + 1) b^(k - 1) - 1)] - 1/b)] - Floor[Floor[n/(2 b^k - 1)]/(Floor[n/(2 b^k - 1)] - 1/ b)], {k, Floor[Log[b, n]]}]}, Mod[q, b] (b + 1)^c * b^Floor[Log[b, q]] + Sum[Floor[Mod[q, b^(k + 1)]/b^k] b^(Floor[Log[b, q]] - k) (b^(2 k + c) + 1), {k, Floor[Log[b, q]]}]] (* after the work of Eric A. Schmidt, works for all integer bases b > 2 *)
    Array[nthPalindromeBase[#, 10] &, 61, 0] (* please note that Schmidt uses a different, a more natural and intuitive offset, that of a(1) = 1. - Robert G. Wilson v, Sep 22 2014 and modified Nov 28 2014 *)
    Select[Range[10^3], PalindromeQ] (* Michael De Vlieger, Nov 27 2017 *)
    nLP[cn_Integer]:=Module[{s,len,half,left,pal,fdpal},s=IntegerDigits[cn]; len=Length[s]; half=Ceiling[len/2]; left=Take[s,half]; pal=Join[left,Reverse[ Take[left,Floor[len/2]]]]; fdpal=FromDigits[pal]; Which[cn==9,11,fdpal>cn,fdpal,True,left=IntegerDigits[ FromDigits[left]+1]; pal=Join[left,Reverse[Take[left,Floor[len/2]]]]; FromDigits[pal]]]; NestList[nLP,0,100] (* Harvey P. Dale, Dec 10 2024 *)
  • PARI
    is_A002113(n)=Vecrev(n=digits(n))==n \\ M. F. Hasler, Nov 17 2008, updated Apr 26 2014, Jun 19 2018
    
  • PARI
    is(n)=n=digits(n);for(i=1,#n\2,if(n[i]!=n[#n+1-i],return(0))); 1 \\ Charles R Greathouse IV, Jan 04 2013
    
  • PARI
    a(n)={my(d,i,r);r=vector(#digits(n-10^(#digits(n\11)))+#digits(n\11));n=n-10^(#digits(n\11));d=digits(n);for(i=1,#d,r[i]=d[i];r[#r+1-i]=d[i]);sum(i=1,#r,10^(#r-i)*r[i])} \\ David A. Corneth, Jun 06 2014
    
  • PARI
    \\ recursive--feed an element a(n) and it gives a(n+1)
    nxt(n)=my(d=digits(n));i=(#d+1)\2;while(i&&d[i]==9,d[i]=0;d[#d+1-i]=0;i--);if(i,d[i]++;d[#d+1-i]=d[i],d=vector(#d+1);d[1]=d[#d]=1);sum(i=1,#d,10^(#d-i)*d[i]) \\ David A. Corneth, Jun 06 2014
    
  • PARI
    \\ feed a(n), returns n.
    inv(n)={my(d=digits(n));q=ceil(#d/2);sum(i=1,q,10^(q-i)*d[i])+10^floor(#d/2)} \\ David A. Corneth, Jun 18 2014
    
  • PARI
    inv_A002113(P)={P\(P=10^(logint(P+!P,10)\/2))+P} \\ index n of palindrome P = a(n), much faster than above: no sum is needed. - M. F. Hasler, Sep 09 2018
    
  • PARI
    A002113(n,L=logint(n,10))=(n-=L=10^max(L-(n<11*10^(L-1)),0))*L+fromdigits(Vecrev(digits(if(nM. F. Hasler, Sep 11 2018
    
  • Python
    # edited by M. F. Hasler, Jun 19 2018
    def A002113_list(nMax):
      mlist=[]
      for n in range(nMax+1):
         mstr=str(n)
         if mstr==mstr[::-1]:
            mlist.append(n)
      return mlist # Bill McEachen, Dec 17 2010
    
  • Python
    from itertools import chain
    A002113 = sorted(chain(map(lambda x:int(str(x)+str(x)[::-1]),range(1,10**3)),map(lambda x:int(str(x)+str(x)[-2::-1]), range(10**3)))) # Chai Wah Wu, Aug 09 2014
    
  • Python
    from itertools import chain, count
    A002113 = chain(k for k in count(0) if str(k) == str(k)[::-1])
    print([next(A002113) for k in range(60)]) # Jan P. Hartkopf, Apr 10 2021
    
  • Python
    is_A002113 = lambda n: (s:=str(n))[::-1]==s # M. F. Hasler, May 23 2024
    
  • Python
    from math import log10, floor
    def A002113(n):
      if n < 2: return 0
      P = 10**floor(log10(n//2)); M = 11*P
      s = str(n - (P if n < M else M-P))
      return int(s + s[-2 if n < M else -1::-1]) # M. F. Hasler, Jun 06 2024
    
  • SageMath
    [n for n in (0..515) if Word(n.digits()).is_palindrome()] # Peter Luschny, Sep 13 2018
    
  • Scala
    def palQ(n: Int, b: Int = 10): Boolean = n - Integer.parseInt(n.toString.reverse) == 0
    (0 to 999).filter(palQ()) // _Alonso del Arte, Nov 10 2019

Formula

A136522(a(n)) = 1.
A178788(a(n)) = 0 for n > 9. - Reinhard Zumkeller, Jun 30 2010
A064834(a(n)) = 0. - Reinhard Zumkeller, Sep 18 2013
a(n+1) = A262038(a(n)+1). - M. F. Hasler, Sep 09 2015
Sum_{n>=2} 1/a(n) = A118031. - Amiram Eldar, Oct 17 2020
a(n) = (floor(d(n)/(c(n)*9 + 1)))*10^A055642(d(n)) + A004086(d(n)) where b(n, k) = ceiling(log((n + 1)/k)/log(10)), c(n) = b(n, 2) - b(n, 11) and d(n) = (n - A086573(b(n*(2 - c(n)), 2) - 1)/2 - 1). - Alan Michael Gómez Calderón, Mar 11 2025

A261132 Number of ways to write n as the sum u+v+w of three palindromes (from A002113) with 0 <= u <= v <= w.

Original entry on oeis.org

1, 1, 2, 3, 4, 5, 7, 8, 10, 12, 13, 15, 16, 17, 17, 18, 17, 17, 16, 15, 13, 12, 11, 10, 9, 8, 7, 7, 6, 6, 6, 6, 5, 7, 6, 6, 6, 6, 6, 6, 6, 6, 6, 5, 8, 7, 7, 7, 7, 7, 7, 7, 7, 7, 5, 9, 7, 7, 7, 7, 7, 7, 7, 7, 7, 5, 11, 8, 8, 8, 8, 8, 8, 8, 8, 8, 5, 12, 8, 8, 8
Offset: 0

Views

Author

Giovanni Resta, Aug 10 2015

Keywords

Comments

It is known that a(n) > 0 for every n, i.e., every number can be written as the sum of 3 palindromes.
The graph has a kind of self-similarity: looking at the first 100 values, there is a Gaussian-shaped peak centered at the first local maximum a(15) = 18. Looking at the first 10000 values, one sees just one Gaussian-shaped peak centered around the record and local maximum a(1453) = 766, but to both sides of this value there are smaller peaks, roughly at distances which are multiples of 10. In the range [1..10^6], one sees a Gaussian-shaped peak centered around the record a(164445) = 57714. In the range [1..3*10^7], there is a similar peak of height ~ 4.3*10^6 at 1.65*10^7, with smaller neighbor peaks at distances which are multiples of 10^6, etc. - M. F. Hasler, Sep 09 2018

Examples

			a(0)=1 because 0 = 0+0+0;
a(1)=1 because 1 = 0+0+1;
a(2)=2 because 2 = 0+1+1 = 0+0+2;
a(3)=3 because 3 = 1+1+1 = 0+1+2 = 0+0+3.
a(28) = 6 since 28 can be expressed in 6 ways as the sum of 3 palindromes, namely, 28 = 0+6+22 = 1+5+22 = 2+4+22 = 3+3+22 = 6+11+11 = 8+9+11.
		

Crossrefs

See A261422 for another version.

Programs

  • Maple
    A261132 := proc(n)
        local xi,yi,x,y,z,a ;
        a := 0 ;
        for xi from 1 do
            x := A002113(xi) ;
            if 3*x > n then
                return a;
            end if;
            for yi from xi do
                y := A002113(yi) ;
                if x+2*y > n then
                    break;
                else
                    z := n-x-y ;
                    if z >= y and isA002113(z) then
                        a := a+1 ;
                    end if;
                end if;
            end do:
        end do:
        return a;
    end proc:
    seq(A261132(n),n=0..80) ; # R. J. Mathar, Sep 09 2015
  • Mathematica
    pal=Select[Range[0, 1000], (d = IntegerDigits@ #; d == Reverse@ d)&]; a[n_] := Length@ IntegerPartitions[n, {3}, pal]; a /@ Range[0, 1000]
  • PARI
    A261132(n)=n||return(1); my(c=0, i=inv_A002113(n)); A2113[i] > n && i--; until( A2113[i--]*3 < n, j = inv_A002113(D = n-A2113[i]); if( j>i, j=i, A2113[j] > D && j--); while( j >= k = inv_A002113(D - A2113[j]), A2113[k] == D - A2113[j] && c++; j--||break));c \\ For efficiency, this uses an array A2113 precomputed at least up to n. - M. F. Hasler, Sep 10 2018

Formula

a(n) = Sum_{k=0..3} A319453(n,k). - Alois P. Heinz, Sep 19 2018

Extensions

Examples revised and plots for large n added by Hugo Pfoertner, Aug 11 2015

A261675 Minimal number of palindromes in base 10 that add to n.

Original entry on oeis.org

1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 1, 2, 2, 2, 2
Offset: 0

Views

Author

N. J. A. Sloane, Sep 02 2015

Keywords

Comments

This sequence coincides with A088601 for n <= 301, but differs at n=302.
Although A088601 and this sequence agree for a large number of terms, because of their importance they warrant separate entries.
Cilleruelo and Luca prove that a(n) <= 3 (in fact they prove this for any fixed base g>=5). - Danny Rorabaugh, Feb 26 2016

Crossrefs

Programs

  • PARI
    ispal(n)=my(d=digits(n)); d==Vecrev(d);
    a(n)=my(L=n\2,d,e); if(ispal(n), return(1)); d=[1]; while((e=fromdigits(d))<=L, if(ispal(n-e), return(2)); my(k=#d,i=(k+1)\2); while(i&&d[i]==9, d[i]=0; d[k+1-i]=0; i--); if(i, d[i]++; d[k+1-i]=d[i], d=vector(#d+1); d[1]=d[#d]=1)); 3; \\ Charles R Greathouse IV, Nov 12 2018

A341156 Number of partitions of n into 3 distinct nonzero decimal palindromes.

Original entry on oeis.org

1, 1, 2, 3, 4, 5, 7, 7, 9, 9, 10, 9, 10, 8, 8, 7, 6, 4, 4, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 6, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 4, 5, 6, 6, 6, 6, 6, 6, 6, 6, 7, 4, 6, 6, 6, 6, 6, 6, 6, 6
Offset: 6

Views

Author

Ilya Gutkovskiy, Feb 06 2021

Keywords

Crossrefs

A088601 Number of steps to reach 0 when iterating A261424(x) = x - (the largest palindrome less than x), starting at n.

Original entry on oeis.org

1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 1, 2, 1, 2, 2, 2, 2
Offset: 1

Views

Author

Amarnath Murthy, Oct 13 2003

Keywords

Comments

The sequence "minimum number of palindromes that sum up to n", A261675, coincides with this sequence up to a(301). But then a(302) = 3 since 302 = 292 + 9 + 1, whereas 302 = 111 + 191.
While it has been conjectured [proved by Cilleruelo & Luca, 2016 -Ed.] that every number can be represented as a sum of at most 3 palindromes, the terms of this sequence, which correspond to a greedy representation, can be larger than 3 (see A109326). For example, 1022 can be represented as 33 + 989, but a(1022) = 4, because the greedy decomposition gives 1022 = 1001 + 11 + 9 + 1. - Giovanni Resta, Aug 20 2015
Presumably this sequence is unbounded (compare A109326). - N. J. A. Sloane, Sep 02 2015
This sequence is unbounded. Let n(1) := 1. To construct n(j+1), take a natural number m with 10^m > n(j) and set n(j+1) := 10^(2m) + 1 + n(j). Then a(n(j)) = j. - Markus Sigg, Oct 26 2015
In A109326 an explicit formula for a smaller (conjectured sharp) upper bound was already given earlier. - M. F. Hasler, Sep 09 2018

Examples

			a(10) = 2: f(10) = 10-9 = 1, f(1) = 1-1 = 0, two steps.
		

Crossrefs

Cf. A109326 gives index of first occurrence of n in this sequence ("greedy inverse").

Programs

  • Maple
    # From N. J. A. Sloane, Aug 28 2015
    # P has list of palindromes
    palfloor:=proc(n) global P; local i;
    for i from 1 to nops(P) do
       if P[i]=n then return(n); fi;
       if P[i]>n then return(P[i-1]); fi;
    od:
    end;
    GA:=proc(n) global P,palfloor; local a,i,k;
    a:=1; k:=n;
    for i from 1 to 30 do
      if k-palfloor(k)=0 then return(a);
      else k:=k-palfloor(k); a:=a+1; fi;
    od; end;
    [seq(GA(n),n=0..200)];
  • Mathematica
    Length@ NestWhileList[f, #, # > 0 &] & /@ Range@ 105 - 1 (* Michael De Vlieger, Oct 26 2015 *)
  • PARI
    ispal(n) = my(d=digits(n)); Vecrev(d)==d;
    fp(n) = {while(!ispal(n), n--); n;}
    a(n) = {nb = 0; while (n, n -= fp(n); nb++); nb;} \\ Michel Marcus, Aug 20 2015
    /* The above fp() is extremely inefficient already for mid-sized numbers. The PARI function A261423 should be preferred.*/
    
  • PARI
    A088601(n)=for(i=1,oo,(n-=A261423(n))||return(i)) \\ M. F. Hasler, Sep 09 2018
    
  • Python
    def P(n):
        s = str(n); h = s[:(len(s)+1)//2]; return int(h + h[-1-len(s)%2::-1])
    def A261423(n):
        s = str(n)
        if s == '1'+'0'*(len(s)-1) and n > 1: return n - 1
        Pn = P(n)
        return Pn if Pn <= n else P(n - 10**(len(s)//2))
    def A088601(n): return 0 if n == 0 else 1 + A088601(n - A261423(n))
    print([A088601(n) for n in range(1, 106)]) # Michael S. Branicky, Jul 12 2021

Formula

a(n) < log_2(log_10(n)) + 3. - M. F. Hasler, Sep 09 2018

Extensions

More terms from David Wasserman, Aug 11 2005

A341192 Number of ways to write n as an ordered sum of 3 nonzero decimal palindromes.

Original entry on oeis.org

1, 3, 6, 10, 15, 21, 28, 36, 45, 52, 60, 66, 70, 72, 72, 70, 66, 60, 55, 45, 39, 34, 30, 27, 25, 24, 24, 24, 27, 27, 25, 27, 27, 27, 27, 27, 27, 27, 27, 30, 27, 27, 30, 30, 30, 30, 30, 30, 30, 30, 33, 27, 30, 33, 33, 33, 33, 33, 33, 33, 33, 36, 27, 34, 36, 36, 36, 36
Offset: 3

Views

Author

Ilya Gutkovskiy, Feb 06 2021

Keywords

Crossrefs

Programs

  • Mathematica
    nmax = 70; CoefficientList[Series[Sum[Boole[PalindromeQ[k]] x^k, {k, 1, nmax}]^3, {x, 0, nmax}], x] // Drop[#, 3] &

A262524 Numbers that can be represented as the sum of three base-10 palindromes in more ways than any smaller number. Position of records in A261132.

Original entry on oeis.org

2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 15, 110, 143, 165, 187, 303, 323, 345, 373, 383, 393, 413, 446, 454, 464, 474, 484, 494, 504, 514, 544, 565, 575, 585, 595, 605, 615, 635, 686, 696, 706, 716, 726, 736, 746, 797, 807, 817, 827, 837, 898, 908, 918, 928, 938, 948, 999, 1009
Offset: 1

Views

Author

Hugo Pfoertner, Sep 24 2015

Keywords

Comments

The corresponding representation counts A261132(a(n)) are provided in A262525.

Crossrefs

See A261422, A262544, A262545 for another approach.

A262525 Records in the number of ways to represent a number as the sum of three base-10 palindromes, A261132.

Original entry on oeis.org

1, 2, 3, 4, 5, 7, 8, 10, 12, 13, 15, 16, 17, 18, 22, 25, 28, 29, 30, 36, 37, 38, 40, 42, 47, 48, 49, 53, 56, 61, 65, 66, 74, 75, 76, 83, 92, 101, 104, 116, 119, 128, 143, 151, 166, 170, 173, 174, 197, 210, 231, 237, 243, 257, 278, 304, 315, 322, 323, 330, 363, 389, 402, 411, 434, 474, 490, 501, 524, 575
Offset: 1

Views

Author

Hugo Pfoertner, Sep 24 2015

Keywords

Comments

The positions of the records are provided in A262524.

Crossrefs

See A261422, A262544, A262545 for another approach.
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