cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A130665 a(n) = Sum_{k=0..n} 3^wt(k), where wt() = A000120().

Original entry on oeis.org

1, 4, 7, 16, 19, 28, 37, 64, 67, 76, 85, 112, 121, 148, 175, 256, 259, 268, 277, 304, 313, 340, 367, 448, 457, 484, 511, 592, 619, 700, 781, 1024, 1027, 1036, 1045, 1072, 1081, 1108, 1135, 1216, 1225, 1252, 1279, 1360, 1387, 1468, 1549, 1792, 1801, 1828, 1855
Offset: 0

Views

Author

N. J. A. Sloane, based on a message from Don Knuth, Jun 23 2007

Keywords

Comments

Partial sums of A048883. - David Applegate, Jun 11 2009
From Gary W. Adamson, Aug 26 2016: (Start)
The formula of Mar 26 2010 is equivalent to the left-shifted vector of matrix powers (lim_{k->infinity} M^k), of the production matrix M:
1, 0, 0, 0, 0, 0, ...
4, 0, 0, 0, 0, 0, ...
3, 1, 0, 0, 0, 0, ...
0, 4, 0, 0, 0, 0, ...
0, 3, 1, 0, 0, 0, ...
0, 0, 4, 0, 0, 0, ...
0, 0, 3, 1, 0, 0, ...
...
The sequence divided by its aerated variant is (1, 4, 3, 0, 0, 0, ...). (End)

Crossrefs

Programs

  • Haskell
    a130665 = sum . map (3 ^) . (`take` a000120_list) . (+ 1)
    -- Reinhard Zumkeller, Apr 18 2012
    
  • Maple
    u:=3; a[1]:=1; M:=30; for n from 1 to M do a[2*n] := (u+1)*a[n]; a[2*n+1] := u*a[n] + a[n+1]; od; t1:=[seq( a[n], n=1..2*M )]; # Gives sequence with a different offset
  • Mathematica
    f[n_] := Sum[3^Count[ IntegerDigits[k, 2], 1], {k, 0, n}]; Array[f, 51, 0] (* Robert G. Wilson v, Jun 28 2010 *)
  • Python
    def a(n):  # formula version, n=10^10000 takes ~1 second
        if n == 0:
            return 1
        msb = 1 << (n.bit_length() - 1)
        return msb**2 + 3 * a(n-msb) # Stefan Pochmann, Mar 15 2023
    
  • Python
    def a(n):  # optimized, n=10^50000 takes ~1 second
        n += 1
        total = 0
        power3 = 1
        while n:
            log = n.bit_length() - 1
            total += power3 << (2*log)
            n -= 1 << log
            power3 *= 3
        return total # Stefan Pochmann, Mar 15 2023

Formula

With a different offset: a(1) = 1; a(n) = max { 3*a(k)+a(n-k) | 1 <= k <= n/2 }, for n>1.
a(2n+1) = 4*a(n) and a(2n) = 3*a(n-1) + a(n).
a(n) = (A147562(n+1) - 1)*3/4 + 1. - Omar E. Pol, Nov 08 2009
a(n) = A160410(n+1)/4. - Omar E. Pol, Nov 12 2009
Let r(x) = (1 + 4x + 3x^2), then (1 + 4x + 7x^2 + 16x^3 + ...) =
r(x)* r(x^2) * r(x^4) * r(x^8) * ... - Gary W. Adamson, Mar 26 2010
For asymptotics see the discussion in the comments in A006046. - N. J. A. Sloane, Mar 11 2021
a(n) = Sum_{k=0..floor(log_2(n+1))} 3^k * A360189(n,k). - Alois P. Heinz, Mar 06 2023
a(n) = msb^2 + 3*a(n-msb), where msb = A053644(n). - Stefan Pochmann, Mar 15 2023

Extensions

Simpler definition (and new offset) from David Applegate, Jun 11 2009
Lower limit of sum in definition changed from 1 to 0 by Robert G. Wilson v, Jun 28 2010

A194459 Number of entries in the n-th row of Pascal's triangle not divisible by 5.

Original entry on oeis.org

1, 2, 3, 4, 5, 2, 4, 6, 8, 10, 3, 6, 9, 12, 15, 4, 8, 12, 16, 20, 5, 10, 15, 20, 25, 2, 4, 6, 8, 10, 4, 8, 12, 16, 20, 6, 12, 18, 24, 30, 8, 16, 24, 32, 40, 10, 20, 30, 40, 50, 3, 6, 9, 12, 15, 6, 12, 18, 24, 30, 9, 18, 27, 36, 45, 12, 24, 36, 48, 60, 15, 30
Offset: 0

Views

Author

Paul Weisenhorn, Aug 24 2011

Keywords

Comments

Pascal triangles modulo p with p prime have the dimension D = log(p*(p+1)/2)/log(p). [Corrected by Connor Lane, Nov 28 2022]
Also number of ones in row n of triangle A254609. - Reinhard Zumkeller, Feb 04 2015

Examples

			n = 32 = 112|_5: b(32,1) = 2, b(32,2) = 1, thus a(32) = 2^2 * 3^1 = 12.
		

Crossrefs

Cf. A006046, A001316 (for p=2).
Cf. A006048, A006047 (for p=3).
Cf. A194458 (for p=5).

Programs

  • Haskell
    a194459 = sum . map (signum . flip mod 5) . a007318_row
    -- Reinhard Zumkeller, Feb 04 2015
    
  • Maple
    a:= proc(n) local l, m, t;
          m:= n;
          l:= [0$5];
          while m>0 do t:= irem(m, 5, 'm')+1; l[t]:=l[t]+1 od;
          mul(r^l[r], r=2..5)
        end:
    seq(a(n), n=0..100);
  • Mathematica
    Nest[Join[#, 2#, 3#, 4#, 5#]&, {1}, 4] (* Jean-François Alcover, Apr 12 2017, after code by Robert G. Wilson v in A006047 *)
  • Python
    from math import prod
    from sympy.ntheory import digits
    def A194459(n):
        s = digits(n,5)[1:]
        return prod((d+1)**s.count(d) for d in range(1,5)) # Chai Wah Wu, Jul 23 2025

Formula

a(n) = Product_{d=1..4} (d+1)^b(n,d) with b(n,d) = number of digits d in base 5 expansion of n. The formula generalizes to other prime bases p.
a(n) = A194458(n) - A194458(n-1).

Extensions

Edited by Alois P. Heinz, Sep 06 2011

A116520 a(0) = 0, a(1) = 1; a(n) = max { 4*a(k) + a(n-k) | 1 <= k <= n/2 }, for n > 1.

Original entry on oeis.org

0, 1, 5, 9, 25, 29, 45, 61, 125, 129, 145, 161, 225, 241, 305, 369, 625, 629, 645, 661, 725, 741, 805, 869, 1125, 1141, 1205, 1269, 1525, 1589, 1845, 2101, 3125, 3129, 3145, 3161, 3225, 3241, 3305, 3369, 3625, 3641, 3705, 3769, 4025, 4089, 4345, 4601, 5625
Offset: 0

Views

Author

Roger L. Bagula, Mar 15 2006

Keywords

Comments

Equivalently, a(n) = r*a(ceiling(n/2)) + s*a(floor(n/2)), a(0)=0, a(1)=1, for (r,s) = (1,4). - N. J. A. Sloane, Feb 16 2016
A 5-divide version of A084230.
Zero together with the partial sums of A102376. - Omar E. Pol, May 05 2010
Also, total number of cubic ON cells after n generations in a three-dimensional cellular automaton in which A102376(n-1) gives the number of cubic ON cells in the n-th level of the structure starting from the top. An ON cell remains ON forever. The structure looks like an irregular stepped pyramid, with n >= 1. - Omar E. Pol, Feb 13 2015
From Gary W. Adamson, Aug 27 2016: (Start)
The formula of Mar 26 2010 is equivalent to lim_{k->infinity} M^k of the following production matrix M:
1, 0, 0, 0, 0, 0, ...
5, 0, 0, 0, 0, 0, ...
4, 1, 0, 0, 0, 0, ...
0, 5, 0, 0, 0, 0, ...
0, 4, 1, 0, 0, 0, ...
0, 0, 5, 0, 0, 0, ...
0, 0, 4, 1, 0, 0, ...
0, 0, 0, 5, 0, 0, ...
...
The sequence with offset 1 divided by its aerated variant is (1, 5, 4, 0, 0, 0, ...). (End)

Crossrefs

Sequences of the form a(n) = r*a(ceiling(n/2)) + s*a(floor(n/2)), a(1)=1, for (r,s) = (1,1), (1,2), (2,1), (1,3), (2,2), (3,1), (1,4), (2,3), (3,2), (4,1): A000027, A006046, A064194, A130665, A073121, A268524, A116520, A268525, A268526, A268527.

Programs

  • Haskell
    import Data.List (transpose)
    a116520 n = a116520_list !! n
    a116520_list = 0 : zs where
       zs = 1 : (concat $ transpose
                          [zipWith (+) vs zs, zipWith (+) vs $ tail zs])
          where vs = map (* 4) zs
    -- Reinhard Zumkeller, Apr 18 2012
  • Maple
    a:=proc(n) if n=0 then 0 elif n=1 then 1 elif n mod 2 = 0 then 5*a(n/2) else 4*a((n-1)/2)+a((n+1)/2) fi end: seq(a(n),n=0..52);
  • Mathematica
    b[0] := 0 b[1] := 1 b[n_?EvenQ] := b[n] = 5*b[n/2] b[n_?OddQ] := b[n] = 4*b[(n - 1)/2] + b[(n + 1)/2] a = Table[b[n], {n, 1, 25}]

Formula

a(0) = 1, a(1) = 1; thereafter a(2n) = 5a(n) and a(2n+1) = 4a(n) + a(n+1).
Let r(x) = (1 + 5x + 4x^2). Then (1 + 5x + 9x^2 + 25x^3 + ...) = r(x) * r(x^2) * r(x^4) * r(x^8) * ... . - Gary W. Adamson, Mar 26 2010
a(n) = Sum_{k=0..n-1} 4^wt(k), where wt = A000120. - Mike Warburton, Mar 14 2019
a(n) = Sum_{k=0..floor(log_2(n))} 4^k*A360189(n-1,k). - Alois P. Heinz, Mar 06 2023

Extensions

Edited by N. J. A. Sloane, Apr 16 2006, Jul 02 2008

A267610 Total number of OFF (white) cells after n iterations of the "Rule 182" elementary cellular automaton starting with a single ON (black) cell.

Original entry on oeis.org

0, 0, 2, 2, 4, 6, 12, 12, 14, 16, 22, 24, 30, 36, 50, 50, 52, 54, 60, 62, 68, 74, 88, 90, 96, 102, 116, 122, 136, 150, 180, 180, 182, 184, 190, 192, 198, 204, 218, 220, 226, 232, 246, 252, 266, 280, 310, 312, 318, 324, 338, 344, 358, 372, 402, 408, 422, 436
Offset: 0

Views

Author

Robert Price, Jan 18 2016

Keywords

Comments

From Gus Wiseman, Mar 30 2019: (Start)
It appears that a(n) is also the number of increasing binary-containment pairs of distinct positive integers up to n + 1. A pair of positive integers is a binary containment if the positions of 1's in the reversed binary expansion of the first are a subset of the positions of 1's in the reversed binary expansion of the second. For example, the a(2) = 2 through a(8) = 14 pairs are:
{1,3} {1,3} {1,3} {1,3} {1,3} {1,3} {1,3}
{2,3} {2,3} {1,5} {1,5} {1,5} {1,5} {1,5}
{2,3} {2,3} {1,7} {1,7} {1,7}
{4,5} {2,6} {2,3} {2,3} {1,9}
{4,5} {2,6} {2,6} {2,3}
{4,6} {2,7} {2,7} {2,6}
{3,7} {3,7} {2,7}
{4,5} {4,5} {3,7}
{4,6} {4,6} {4,5}
{4,7} {4,7} {4,6}
{5,7} {5,7} {4,7}
{6,7} {6,7} {5,7}
{6,7}
{8,9}
(End)

References

  • S. Wolfram, A New Kind of Science, Wolfram Media, 2002; p. 55.

Crossrefs

Programs

  • Mathematica
    rule=182; rows=20; ca=CellularAutomaton[rule,{{1},0},rows-1,{All,All}]; (* Start with single black cell *) catri=Table[Take[ca[[k]],{rows-k+1,rows+k-1}],{k,1,rows}]; (* Truncated list of each row *) nbc=Table[Total[catri[[k]]],{k,1,rows}]; (* Number of Black cells in stage n *) nwc=Table[Length[catri[[k]]]-nbc[[k]],{k,1,rows}]; (* Number of White cells in stage n *) Table[Total[Take[nwc,k]],{k,1,rows}] (* Number of White cells through stage n *)

Formula

Conjecture: a(n) = A267700(n) - n. - Gus Wiseman, Mar 30 2019
G.f.: (1/x)*(A(x)/x - (x+1)/(1-x)^2) where A(x) is the g.f. for A006046 (conjectured). - John Tyler Rascoe, Jul 08 2024

A116528 a(0)=0, a(1)=1, and for n>=2, a(2*n) = a(n), a(2*n+1) = 2*a(n) + a(n+1).

Original entry on oeis.org

0, 1, 1, 3, 1, 5, 3, 7, 1, 7, 5, 13, 3, 13, 7, 15, 1, 9, 7, 19, 5, 23, 13, 29, 3, 19, 13, 33, 7, 29, 15, 31, 1, 11, 9, 25, 7, 33, 19, 43, 5, 33, 23, 59, 13, 55, 29, 61, 3, 25, 19, 51, 13, 59, 33, 73, 7, 43, 29, 73, 15, 61, 31, 63, 1, 13
Offset: 0

Views

Author

Roger L. Bagula, Mar 15 2006

Keywords

Comments

Equals row 2 of the array in A178239, an infinite set of sequences of the form a(n) = a(2n), a(2n+1) = r*a(n) + a(n+1). - Gary W. Adamson, May 23 2010
Given an infinite lower triangular matrix M with (1, 1, 2, 0, 0, 0, ...) in every column, shifted down twice for columns k>1; lim_{n->infinity} M^n = A116528, the left-shifted vector considered as a sequence with offset 1. - Gary W. Adamson, May 05 2010

Crossrefs

Programs

  • Magma
    a:=func< n | n lt 2 select n else ((n mod 2) eq 0) select Self(Round((n+1)/2)) else (2*Self(Round(n/2)) + Self(Round((n+2)/2))) >;
    [a(n): n in [0..70]]; // G. C. Greubel, Jul 07 2019
    
  • Maple
    A116528 := proc(n)
       option remember;
       if n <= 1 then
          n;
       elif type(n,'even') then
          procname(n/2) ;
       else
          2* procname((n-1)/2)+procname((n+1)/2) ;
       end if;
    end proc:
    seq(A116528(n),n=0..70) ; # R. J. Mathar, Nov 16 2011
  • Mathematica
    b[0]:= 0; b[1]:= 1; b[n_?EvenQ]:= b[n] = b[n/2]; b[n_?OddQ]:= b[n] = 2*b[(n-1)/2] + b[(n+1)/2]; a = Table[b[n], {n, 1, 70}]
  • PARI
    a(n) = if(n<2, n, if(n%2==0, a(n/2), 2*a((n-1)/2) + a((n+1)/2))); \\ G. C. Greubel, Jul 07 2019
    
  • Sage
    def a(n):
        if (n<2): return n
        elif (mod(n,2)==0): return a(n/2)
        else: return 2*a((n-1)/2) + a((n+1)/2)
    [a(n) for n in (0..70)] # G. C. Greubel, Jul 07 2019

Formula

G.f.: x * Product_{k>=0} (1 + x^(2^k) + 2*x^(2^(k+1))). - Ilya Gutkovskiy, Jul 07 2019

Extensions

Edited by G. C. Greubel, Oct 30 2016

A295989 Irregular triangle T(n, k), read by rows, n >= 0 and 0 <= k < A001316(n): T(n, k) is the (k+1)-th nonnegative number m such that n AND m = m (where AND denotes the bitwise AND operator).

Original entry on oeis.org

0, 0, 1, 0, 2, 0, 1, 2, 3, 0, 4, 0, 1, 4, 5, 0, 2, 4, 6, 0, 1, 2, 3, 4, 5, 6, 7, 0, 8, 0, 1, 8, 9, 0, 2, 8, 10, 0, 1, 2, 3, 8, 9, 10, 11, 0, 4, 8, 12, 0, 1, 4, 5, 8, 9, 12, 13, 0, 2, 4, 6, 8, 10, 12, 14, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 0
Offset: 0

Views

Author

Rémy Sigrist, Dec 02 2017

Keywords

Comments

The (n+1)-th row has A001316(n) terms and sums to n * A001316(n) / 2.
For any n >= 0 and k such that 0 <= k < A001316(n):
- if A000120(n) > 0 then T(n, 1) = A006519(n),
- if A000120(n) > 1 then T(n, 2) = 2^A285099(n),
- if A000120(n) > 0 then T(n, A001316(n)/2 - 1) = A053645(n),
- if A000120(n) > 0 then T(n, A001316(n)/2) = 2^A000523(n),
- if A000120(n) > 0 then T(n, A001316(n) - 2) = A129760(n),
- T(n, A001316(n) - 1) = n,
- the six previous relations correspond respectively (when applicable) to the second term, the third term, the pair of central terms, the penultimate term and the last term of a row,
- T(n, k) AND T(n, A001316(n) - k - 1) = 0,
- T(n, k) + T(n, A001316(n) - k - 1) = n,
- T(n, k) = k for any k < A006519(n+1),
- A000120(T(n, k)) = A000120(k).
If we plot (n, T(n,k)) then we obtain a skewed Sierpinski triangle (see Links section).
If interpreted as a flat sequence a(n) for n >= 0:
- a(n) = 0 iff n = A006046(k) for some k >= 0,
- a(n) = 1 iff n = A006046(2*k + 1) + 1 for some k >= 0,
- a(A006046(k) - 1) = k - 1 for any k > 0.

Examples

			Triangle begins:
  0:   [0]
  1:   [0, 1]
  2:   [0, 2]
  3:   [0, 1, 2, 3]
  4:   [0, 4]
  5:   [0, 1, 4, 5]
  6:   [0, 2, 4, 6]
  7:   [0, 1, 2, 3, 4, 5, 6, 7]
  8:   [0, 8]
  9:   [0, 1, 8, 9]
  10:  [0, 2, 8, 10]
  11:  [0, 1, 2, 3, 8, 9, 10, 11]
  12:  [0, 4, 8, 12]
  13:  [0, 1, 4, 5, 8, 9, 12, 13]
  14:  [0, 2, 4, 6, 8, 10, 12, 14]
  15:  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
		

Crossrefs

First column of array in A352909.

Programs

  • Mathematica
    A295989row[n_] := Select[Range[0, n], BitAnd[#, n-#] == 0 &];
    Array[A295989row, 25, 0] (* Paolo Xausa, Feb 24 2024 *)
  • PARI
    T(n,k) = if (k==0, 0, n%2==0, 2*T(n\2,k), k%2==0, 2*T(n\2, k\2), 2*T(n\2, k\2)+1)

Formula

For any n >= 0 and k such that 0 <= k < A001316(n):
- T(n, 0) = 0,
- T(2*n, k) = 2*T(n, k),
- T(2*n+1, 2*k) = 2*T(n, k),
- T(2*n+1, 2*k+1) = 2*T(n, k) + 1.

A360189 Triangle T(n,k), n>=0, 0<=k<=floor(log_2(n+1)), read by rows: T(n,k) = number of nonnegative integers <= n having binary weight k.

Original entry on oeis.org

1, 1, 1, 1, 2, 1, 2, 1, 1, 3, 1, 1, 3, 2, 1, 3, 3, 1, 3, 3, 1, 1, 4, 3, 1, 1, 4, 4, 1, 1, 4, 5, 1, 1, 4, 5, 2, 1, 4, 6, 2, 1, 4, 6, 3, 1, 4, 6, 4, 1, 4, 6, 4, 1, 1, 5, 6, 4, 1, 1, 5, 7, 4, 1, 1, 5, 8, 4, 1, 1, 5, 8, 5, 1, 1, 5, 9, 5, 1, 1, 5, 9, 6, 1, 1, 5, 9, 7, 1
Offset: 0

Views

Author

Alois P. Heinz, Mar 04 2023

Keywords

Comments

T(n,k) is defined for all n >= 0 and k >= 0. Terms that are not in the triangle are zero.

Examples

			T(6,2) = 3: 3, 5, 6, or in binary: 11_2, 101_2, 110_2.
T(15,3) = 4: 7, 11, 13, 14, or in binary: 111_2, 1011_2, 1101_2, 1110_2.
Triangle T(n,k) begins:
  1;
  1, 1;
  1, 2;
  1, 2, 1;
  1, 3, 1;
  1, 3, 2;
  1, 3, 3;
  1, 3, 3, 1;
  1, 4, 3, 1;
  1, 4, 4, 1;
  1, 4, 5, 1;
  1, 4, 5, 2;
  1, 4, 6, 2;
  1, 4, 6, 3;
  1, 4, 6, 4;
  1, 4, 6, 4, 1;
  ...
		

Crossrefs

Columns k=0-2 give: A000012, A029837(n+1) = A113473(n) for n>0, A340068(n+1).
Last elements of rows give A090996(n+1).

Programs

  • Maple
    b:= proc(n) option remember; `if`(n<0, 0,
          b(n-1)+x^add(i, i=Bits[Split](n)))
        end:
    T:= n-> (p-> seq(coeff(p, x, i), i=0..degree(p)))(b(n)):
    seq(T(n), n=0..23);
  • PARI
    T(n,k) = my(v1); v1 = Vecrev(binary(n+1)); v1 = Vecrev(select(x->(x>0),v1,1)); sum(j=0, min(k,#v1-1), binomial(v1[j+1]-1,k-j)) \\ Mikhail Kurkov, Nov 27 2024

Formula

T(n,k) = T(n-1,k) + [A000120(n) = k] where [] is the Iverson bracket and T(n,k) = 0 for n<0.
T(2^n-1,k) = A007318(n,k) = binomial(n,k).
T(n,floor(log_2(n+1))) = A090996(n+1).
Sum_{k>=0} T(n,k) = n+1.
Sum_{k>=0} k * T(n,k) = A000788(n).
Sum_{k>=0} k^2 * T(n,k) = A231500(n).
Sum_{k>=0} k^3 * T(n,k) = A231501(n).
Sum_{k>=0} k^4 * T(n,k) = A231502(n).
Sum_{k>=0} 2^k * T(n,k) = A006046(n+1).
Sum_{k>=0} 3^k * T(n,k) = A130665(n).
Sum_{k>=0} 4^k * T(n,k) = A116520(n+1).
Sum_{k>=0} 5^k * T(n,k) = A130667(n+1).
Sum_{k>=0} 6^k * T(n,k) = A116522(n+1).
Sum_{k>=0} 7^k * T(n,k) = A161342(n+1).
Sum_{k>=0} 8^k * T(n,k) = A116526(n+1).
Sum_{k>=0} 10^k * T(n,k) = A116525(n+1).
Sum_{k>=0} n^k * T(n,k) = A361257(n).
T(n,k) = Sum_{j=0..min(k, A000120(n+1)-1)} binomial(A272020(n+1,j+1)-1,k-j) for n >= 0, k >= 0 (see Peter J. Taylor link). - Mikhail Kurkov, Nov 27 2024

A064194 a(2n) = 3*a(n), a(2n+1) = 2*a(n+1)+a(n), with a(1) = 1.

Original entry on oeis.org

1, 3, 7, 9, 17, 21, 25, 27, 43, 51, 59, 63, 71, 75, 79, 81, 113, 129, 145, 153, 169, 177, 185, 189, 205, 213, 221, 225, 233, 237, 241, 243, 307, 339, 371, 387, 419, 435, 451, 459, 491, 507, 523, 531, 547, 555, 563, 567, 599, 615, 631, 639, 655, 663, 671, 675
Offset: 1

Views

Author

Guillaume Hanrot and Paul Zimmermann, Sep 21 2001

Keywords

Comments

Number of ring multiplications needed to multiply two degree-n polynomials using Karatsuba's algorithm.
Number of gates in the AND/OR problem (see Chang/Tsai reference).
a(n) is also the number of odd elements in the n X n symmetric Pascal matrix. - Stefano Spezia, Nov 14 2022

References

  • A. A. Karatsuba and Y. P. Ofman, Multiplication of multiplace numbers by automata. Dokl. Akad. Nauk SSSR 145, 2, 293-294 (1962).

Crossrefs

Cf. A023416, A267584, A047999 (Sierpinski triangle).
Cf. also A268514.
Sequences of form a(n)=r*a(ceil(n/2))+s*a(floor(n/2)), a(1)=1, for (r,s) = (1,1), (1,2), (2,1), (1,3), (2,2), (3,1), (1,4), (2,3), (3,2), (4,1): A000027, A006046, A064194, A130665, A073121, A268524, A116520, A268525, A268526, A268527.

Programs

  • Magma
    [n le 1 select 1 else Self(Floor(n/2)) + 2*Self(Ceiling(n/2)): n in [1..60]]; // Vincenzo Librandi, Aug 30 2016
  • Maple
    f:=proc(n) option remember; if n=1 then 1 elif n mod 2 = 0 then 3*f(n/2) else 2*f((n+1)/2)+f((n-1)/2); fi; end; [seq(f(n),n=1..60)]; # N. J. A. Sloane, Jan 17 2016
  • Mathematica
    a[n_] := a[n] = If[EvenQ[n], 3 a[n/2], 2 a[# + 1] + a[#] &[(n - 1)/2]]; a[1] = 1; Array[a, 56] (* Michael De Vlieger, Oct 29 2022 *)
  • PARI
    a(n) = sum(i=0, n-1, sum(j=0, n-1, binomial(i+j, i) % 2)); \\ Michel Marcus, Aug 25 2013
    

Formula

Partial sums of the sequence { b(1)=1, b(n)=2^(e0(n-1)+1) } (essentially A267584), where e0(n)=A023416(n) is the number of zeros in the binary expansion of n. [Chang/Tsai] - Ralf Stephan, Jul 29 2003
a(1) = 1, a(n) = a(floor(n/2)) + 2*a(ceiling(n/2)), n > 1.
a(n+1) = Sum_{0<=i, j<=n} (binomial(i+j, i) mod 2). - Benoit Cloitre, Mar 07 2005
In particular, a(2^k)=3^k, a(3*2^k)=7*3^k. - N. J. A. Sloane, Jan 18 2016
a(n) = 2*A268514(n-1) + 1. - N. J. A. Sloane, Feb 07 2016

Extensions

Edited with clearer definition by N. J. A. Sloane, Jan 18 2016

A080263 A014486-encoding of the branch-reduced binomial-mod-2 binary trees.

Original entry on oeis.org

2, 50, 906, 247986, 4072138, 1059204274, 272900475786, 17953590946285746, 287705670922216138, 73724537815637830834, 18880972926031430339466, 1237678872789190922262530226, 316876593058175709191975346890
Offset: 0

Views

Author

Antti Karttunen, Mar 02 2003

Keywords

Comments

These trees are obtained from the successive generations of Rule 90 cellular automaton (A070886) or Pascal's triangle computed modulo 2 (A047999), with alive cells of the automaton (respectively: the odd binomials) forming the vertices of the zigzag tree.

References

  • J. C. P. Miller, Periodic Forests of Stunted Trees, Phil. Tran. Roy. Soc. London A266 (1970) 63; A293 (1980) 48.

Crossrefs

Same sequence in binary: A080264. Cf. A080265. Breadth-first-wise encodings of the same trees: A080268. Corresponding branch-reduced zigzag trees: A080293.
Number of edges in general trees/internal nodes in binary trees: A006046, number of zigzag-edges (those colored black in illustrations) is one less: A074330. Cf. A080978.

A151566 Leftist toothpicks (see Comments for definition).

Original entry on oeis.org

0, 1, 2, 4, 6, 8, 10, 14, 18, 20, 22, 26, 30, 34, 38, 46, 54, 56, 58, 62, 66, 70, 74, 82, 90, 94, 98, 106, 114, 122, 130, 146, 162, 164, 166, 170, 174, 178, 182, 190, 198, 202, 206, 214, 222, 230, 238, 254, 270, 274, 278, 286, 294, 302, 310, 326, 342, 350, 358, 374, 390, 406
Offset: 0

Views

Author

N. J. A. Sloane, May 23 2009

Keywords

Comments

Similar to A139250, except that when we add toothpicks to horizontal toothpicks, we only add them at the left-hand end.
Sequence gives total number of toothpicks in the n-th generation. First differences are in A060632.
This is equivalent to the Sierpinski triangle A047999. Each inverted T formed by two toothpicks is equivalent to a triangle in the Sierpinski sieve. See Gould's sequence A001316. [From Omar E. Pol, May 23 2009]

Crossrefs

Formula

a(2n) = 2*A006046(n), a(2n+1) = a(2n) + A001316(n) = 2*A006046(n) + A001316(n).
G.f.: (x*(1+x)/(1-x)) * Product_{k>0} (1 + 2 * x^(2^k)). - Seiichi Manyama, Oct 12 2019
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