cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 11 results. Next

A000266 Expansion of e.g.f. exp(-x^2/2) / (1-x).

Original entry on oeis.org

1, 1, 1, 3, 15, 75, 435, 3045, 24465, 220185, 2200905, 24209955, 290529855, 3776888115, 52876298475, 793144477125, 12690313661025, 215735332237425, 3883235945814225, 73781482970470275, 1475629660064134575, 30988222861346826075, 681740902935880863075
Offset: 0

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Author

Keywords

Comments

a(n) is the number of permutations in the symmetric group S_n whose cycle decomposition contains no transposition.

Examples

			a(3) = 3 because the permutations in S_3 that contain no transpositions are the trivial permutation and the two 3-cycles.
		

References

  • J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 85.
  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
  • R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.

Crossrefs

See also A000138 and A000090.

Programs

  • Maple
    G:=exp(-z^2/2)/(1-z): Gser:=series(G,z=0,26): for n from 0 to 25 do a(n):=n!*coeff(Gser,z,n): end do: seq(a(n), n=0..20); # Paul Weisenhorn, May 29 2010
    # second Maple program:
    a:= proc(n) option remember; `if`(n=0, 1, add(
          a(n-j)*(j-1)!*binomial(n-1, j-1), j=[1, $3..n]))
        end:
    seq(a(n), n=0..30);  # Alois P. Heinz, May 12 2016
  • Mathematica
    a=Log[1/(1-x)]-x^2/2; Range[0,20]! CoefficientList[Series[Exp[a], {x,0,20}], x] (* Geoffrey Critzer, Nov 29 2011 *)
  • PARI
    {a(n) = if( n<0, 0, n! * polcoeff( exp(-(x^2/2)+x*O(x^n)) / (1 - x), n))} /* Michael Somos, Jul 28 2009 */

Formula

E.g.f.: exp( x + Sum_{k>2} x^k / k ). - Michael Somos, Jul 25 2011
a(n) = n! * Sum_{i=0..floor(n/2)} (-1)^i /(i! * 2^i); a(n)/n! ~ Sum_{i>=0} (-1)^i /(i! * 2^i) = e^(-1/2); a(n) ~ e^(-1/2) * n!; a(n) ~ e^(-1/2) * (n/e)^n * sqrt(2*Pi*n). - Avi Peretz (njk(AT)netvision.net.il), Apr 21 2001
A027616(n) + a(n) = n!. - Yuval Dekel (dekelyuval(AT)hotmail.com), Nov 09 2003
a(n) = n!*floor((floor(n/2)! * 2^floor(n/2) / exp(1/2) + 1/2)) / (floor(n/2)! * 2^floor(n/2)), n >= 0. - Simon Plouffe from old notes, 1993
E.g.f.: 1/(1-x)*exp(-(x^2)/2) = 1/((1-x)*G(0)); G(k) = 1+(x^2)/(2*(2*k+1)-2*(x^2)*(2*k+1)/((x^2)+4*(k+1)/G(k+1))); (continued fraction). - Sergei N. Gladkovskii, Nov 24 2011
E.g.f.: 1/Q(0), where Q(k) = 1 - x/(1 - x/(x - (2*k+2)/Q(k+1))); (continued fraction). - Sergei N. Gladkovskii, May 15 2013
D-finite with recurrence: a(n) - n*a(n-1) + (n-1)*a(n-2) - (n-1)*(n-2)*a(n-3) = 0. - R. J. Mathar, Feb 16 2020

Extensions

More terms from Christian G. Bower
Entry improved by comments from Michael Somos, Jul 28 2009
Minor editing by Johannes W. Meijer, Jul 25 2011

A000138 Expansion of e.g.f. exp(-x^4/4)/(1-x).

Original entry on oeis.org

1, 1, 2, 6, 18, 90, 540, 3780, 31500, 283500, 2835000, 31185000, 372972600, 4848643800, 67881013200, 1018215198000, 16294848570000, 277012425690000, 4986223662420000, 94738249585980000, 1894745192712372000, 39789649046959812000, 875372279033115864000
Offset: 0

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Author

Keywords

Comments

a(n) is the number of permutations in the symmetric group S_n whose cycle decomposition contains no 4-cycle.

Examples

			a(4) = 18 because in S_4 the permutations with no 4-cycle are the complement of the six 4-cycles so a(4) = 4! - 6 = 18.
		

References

  • J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 85.
  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
  • R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.

Crossrefs

Programs

  • Mathematica
    nn=20;Range[0,nn]!CoefficientList[Series[Exp[-x^4/4]/(1-x),{x,0,nn}],x]  (* Geoffrey Critzer, Oct 28 2012 *)
  • PARI
    {a(n) = if( n<0, 0, n! * polcoeff( exp( -(x^4/4) + x*O(x^n)) / (1 - x), n))} /* Michael Somos, Jul 28 2009 */

Formula

a(n) = n! * Sum_{i=0..floor(n/4)} (-1)^i / (i! * 4^i); a(n)/n! ~ Sum_{i >= 0} (-1)^i / (i! * 4^i) = e^(-1/4); a(n) ~ e^(-1/4) * n!; a(n) ~ e^(-1/4) * (n/e)^n * sqrt(2*Pi*n). - Avi Peretz (njk(AT)netvision.net.il), Apr 22 2001
a(n,k) = n!*floor(floor(n/k)!*k^floor(n/k)/exp(1/k) + 1/2)/(floor(n/k)!*k^floor(n/k)), here k=4, n>=0. Simon Plouffe, from old notes, 1993
E.g.f.: exp(-x^4/4)/(1-x) = 1/G(0); G(k) = 1 - x/(1 - (x^3)/(x^3 - 4*(k+1)/G(k+1))); (continued fraction). - Sergei N. Gladkovskii, Feb 28 2012

Extensions

Entry improved by comments from Michael Somos, Jul 28 2009
Name corrected by Joerg Arndt, May 27 2011

A060725 E.g.f.: exp(-(x^5/5))/(1-x).

Original entry on oeis.org

1, 1, 2, 6, 24, 96, 576, 4032, 32256, 290304, 2975616, 32731776, 392781312, 5106157056, 71486198784, 1070549415936, 17128790654976, 291189441134592, 5241409940422656, 99586788868030464, 1991897970827821056, 41829857387384242176, 920256862522453327872
Offset: 0

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Author

Avi Peretz (njk(AT)netvision.net.il), Apr 22 2001

Keywords

Comments

a(n) is the number of permutations in the symmetric group S_n whose cycle decomposition contains no 5-cycle.

Examples

			a(5) = 96 because in S_5 the permutations with no 5-cycle are the complement of the 24 5-cycles so a(5) = 5! - 24 = 96.
		

References

  • R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.

Crossrefs

Programs

  • Maple
    for n from 0 to 30 do printf(`%d,`, n! * sum(( (-1)^i /(i! * 5^i)), i=0..floor(n/5))) od:
  • Mathematica
    With[{nn=30},CoefficientList[Series[Exp[-(x^5/5)]/(1-x),{x,0,nn}],x] Range[ 0,nn]!] (* Harvey P. Dale, Aug 24 2019 *)
  • PARI
    { for (n=0, 100, write("b060725.txt", n, " ", n! * sum(i=0, n\5, (-1)^i / (i! * 5^i))); ) } \\ Harry J. Smith, Jul 10 2009
    
  • PARI
    {a(n) = if( n<0, 0, n! * polcoeff( exp( -(x^5 / 5) + x*O(x^n)) / (1 - x), n))} /* Michael Somos, Jul 28 2009 */
    
  • PARI
    { A060725_list(numterms) = Vec(serlaplace(exp(-x^5/5 + O(x^numterms))/(1-x))); } /* Eric M. Schmidt, Aug 22 2012 */

Formula

The formula for a(n) is: a(n) = n! * sum i=0 ... [ n/5 ]( (-1)^i /(i! * 5^i)) by this formula we have as n -> infinity: a(n)/n! ~ sum i >= 0 (-1)^i /(i! * 5^i) = e^(-1/5) or a(n) ~ e^(-1/5) * n! and using Stirling's formula in A000142: a(n) ~ e^(-1/5) * (n/e)^n * sqrt(2 * Pi * n).
a(n,k) = n!*floor(floor(n/k)!*k^floor(n/k)/exp(1/k) + 1/2)/(floor(n/k)! * k^floor(n/k)), k=5, n>=0. - Simon Plouffe, Feb 18 2011

Extensions

More terms from James Sellers, Apr 24 2001
Entry improved by comments from Michael Somos, Jul 28 2009

A274760 The multinomial transform of A001818(n) = ((2*n-1)!!)^2.

Original entry on oeis.org

1, 1, 10, 478, 68248, 21809656, 13107532816, 13244650672240, 20818058883902848, 48069880140604832128, 156044927762422185270016, 687740710497308621254625536, 4000181720339888446834235653120, 29991260979682976913756629498334208
Offset: 0

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Author

Johannes W. Meijer, Jul 27 2016

Keywords

Comments

The multinomial transform [MNL] transforms an input sequence b(n) into the output sequence a(n). Given the fact that the structure of the a(n) formulas, see the examples, lead to the multinomial coefficients A036039 the MNL transform seems to be an appropriate name for this transform. The multinomial transform is related to the exponential transform, see A274804 and the third formula. For the inverse multinomial transform [IML] see A274844.
To preserve the identity IML[MNL[b(n)]] = b(n) for n >= 0 for a sequence b(n) with offset 0 the shifted sequence b(n-1) with offset 1 has to be used as input for the MNL, otherwise information about b(0) will be lost in transformation.
In the a(n) formulas, see the examples, the multinomial coefficients A036039 appear.
We observe that a(0) = 1 and that this term provides no information about any value of b(n), this notwithstanding we will start the a(n) sequence with a(0) = 1.
The Maple programs can be used to generate the multinomial transform of a sequence. The first program uses the first formula which was found by Paul D. Hanna, see A158876, and Vladimir Kruchinin, see A215915. The second program uses properties of the e.g.f., see the sequences A158876, A213507, A244430 and A274539 and the third formula. The third program uses information about the inverse multinomial transform, see A274844.
Some MNL transform pairs are, n >= 1: A000045(n) and A244430(n-1); A000045(n+1) and A213527(n-1); A000108(n) and A213507(n-1); A000108(n-1) and A243953(n-1); A000142(n) and A158876(n-1); A000203(n) and A053529(n-1); A000110(n) and A274539(n-1); A000041(n) and A215915(n-1); A000035(n-1) and A177145(n-1); A179184(n) and A038205(n-1); A267936(n) and A000266(n-1); A267871(n) and A000090(n-1); A193356(n) and A088009(n-1).

Examples

			Some a(n) formulas, see A036039:
  a(0) = 1
  a(1) = 1*x(1)
  a(2) = 1*x(2) + 1*x(1)^2
  a(3) = 2*x(3) + 3*x(1)*x(2) + 1*x(1)^3
  a(4) = 6*x(4) + 8*x(1)*x(3) + 3*x(2)^2 + 6*x(1)^2*x(2) + 1*x(1)^4
  a(5) = 24*x(5) + 30*x(1)*x(4) + 20*x(2)*x(3) + 20*x(1)^2*x(3) + 15*x(1)*x(2)^2 + 10*x(1)^3*x(2) + 1*x(1)^5
		

References

  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, 1995, pp. 18-23.

Crossrefs

Programs

  • Maple
    nmax:= 13: b := proc(n): (doublefactorial(2*n-1))^2 end: a:= proc(n) option remember: if n=0 then 1 else add(((n-1)!/(n-k)!) * b(k) * a(n-k), k=1..n) fi: end: seq(a(n), n = 0..nmax); # End first MNL program.
    nmax:=13: b := proc(n): (doublefactorial(2*n-1))^2 end: t1 := exp(add(b(n)*x^n/n, n = 1..nmax+1)): t2 := series(t1, x, nmax+1): a := proc(n): n!*coeff(t2, x, n) end: seq(a(n), n = 0..nmax); # End second MNL program.
    nmax:=13: b := proc(n): (doublefactorial(2*n-1))^2 end: f := series(log(1+add(s(n)*x^n/n!, n=1..nmax)), x, nmax+1): d := proc(n): n*coeff(f, x, n) end: a(0) := 1: a(1) := b(1): s(1) := b(1): for n from 2 to nmax do s(n) := solve(d(n)-b(n), s(n)): a(n):=s(n): od: seq(a(n), n=0..nmax); # End third MNL program.
  • Mathematica
    b[n_] := (2*n - 1)!!^2;
    a[0] = 1; a[n_] := a[n] = Sum[((n-1)!/(n-k)!)*b[k]*a[n-k], {k, 1, n}];
    Table[a[n], {n, 0, 13}] (* Jean-François Alcover, Nov 17 2017 *)

Formula

a(n) = Sum_{k=1..n} ((n-1)!/(n-k)!)*b(k)*a(n-k), n >= 1 and a(0) = 1, with b(n) = A001818(n) = ((2*n-1)!!)^2.
a(n) = n!*P(n), with P(n) = (1/n)*(Sum_{k=0..n-1} b(n-k)*P(k)), n >= 1 and P(0) = 1, with b(n) = A001818(n) = ((2*n-1)!!)^2.
E.g.f.: exp(Sum_{n >= 1} b(n)*x^n/n) with b(n) = A001818(n) = ((2*n-1)!!)^2.
denom(a(n)/2^n) = A001316(n); numer(a(n)/2^n) = [1, 1, 5, 239, 8531, 2726207, ...].

A060726 For n >= 1, a(n) is the number of permutations in the symmetric group S_n such that their cycle decomposition contains no 6-cycle.

Original entry on oeis.org

1, 1, 2, 6, 24, 120, 600, 4200, 33600, 302400, 3024000, 33264000, 405820800, 5275670400, 73859385600, 1107890784000, 17726252544000, 301346293248000, 5419293175296000, 102966570330624000, 2059331406612480000
Offset: 0

Views

Author

Avi Peretz (njk(AT)netvision.net.il), Apr 22 2001

Keywords

Comments

This is the expansion of exp ((-x^6)/6) /(1-x).

Examples

			a(6) = 600 because in S_6 the permutations with no 6-cycle are the complement of the 120 6-cycles so a(6) = 6! - 120 = 600.
		

References

  • R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.

Crossrefs

Programs

  • Maple
    for n from 0 to 30 do printf(`%d,`, n! * sum(( (-1)^i /(i! * 6^i)), i=0..floor(n/6))) od:
  • PARI
    a(n)={n! * sum(i=0, n\6, (-1)^i / (i! * 6^i))} \\ Harry J. Smith, Jul 10 2009

Formula

The formula for a(n) is: a(n) = n! * Sum_{i=0..floor(n/6)} ((-1)^i /(i! * 6^i)) by this formula we have as n -> infinity: a(n)/n! ~ Sum_{i>= 0} (-1)^i /(i! * 6^i) = e^(-1/6) or a(n) ~ e^(-1/6) * n! and using Stirling's formula in A000142: a(n) ~ e^(-1/6) * (n/e)^n * sqrt(2 * Pi * n)
a(n,k) = n!*floor(floor(n/k)!*k^floor(n/k)/exp(1/k) + 1/2)/(floor(n/k)!*k^floor(n/k)), k=6, n >= 0. - Simon Plouffe, Feb 18 2011

Extensions

More terms from James Sellers, Apr 24 2001

A114320 Triangle T(n,k) = number of permutations of n elements with k 2-cycles.

Original entry on oeis.org

1, 1, 1, 1, 3, 3, 15, 6, 3, 75, 30, 15, 435, 225, 45, 15, 3045, 1575, 315, 105, 24465, 12180, 3150, 420, 105, 220185, 109620, 28350, 3780, 945, 2200905, 1100925, 274050, 47250, 4725, 945, 24209955, 12110175, 3014550, 519750, 51975, 10395, 290529855
Offset: 0

Views

Author

Vladeta Jovovic, Feb 05 2006

Keywords

Comments

Row n has 1+floor(n/2) terms. Row sums yield the factorials (A000142). Sum(k*T(n,k),k>0)=n!/2 for n>=2. - Emeric Deutsch, Feb 17 2006

Examples

			T(3,1) = 3 because we have (1)(23), (12)(3) and (13)(2).
Triangle begins:
    1;
    1;
    1,   1;
    3,   3;
   15,   6,   3;
   75,  30,  15;
  435, 225,  45,  15;
  ...
		

Crossrefs

Programs

  • Maple
    G:= exp((y-1)*x^2/2)/(1-x): Gser:= simplify(series(G,x=0,15)): P[0]:=1: for n from 1 to 12 do P[n]:= n!*coeff(Gser,x^n) od: for n from 0 to 12 do seq(coeff(y*P[n], y^j), j=1..1+floor(n/2)) od;  # yields sequence in triangular form - Emeric Deutsch, Feb 17 2006
  • Mathematica
    d = Exp[-x^2/2!]/(1 - x);f[list_] := Select[list, # > 0 &]; Flatten[Map[f, Transpose[Table[Range[0, 10]!CoefficientList[Series[x^(2 k)/(2^k k!) d, {x, 0, 10}], x], {k, 0, 5}]]]]  (* Geoffrey Critzer, Nov 29 2011 *)

Formula

E.g.f.: exp((y-1)*x^2/2)/(1-x). More generally, e.g.f. for number of permutations of n elements with k m-cycles is exp((y-1)*x^m/m)/(1-x).
T(n,k) = n!/(2^k*k!) * Sum_{j=0..floor(n/2)-k} (-1/2)^j/j!. - Alois P. Heinz, Nov 30 2011

Extensions

More terms from Emeric Deutsch, Feb 17 2006

A060727 For n >= 1 a(n) is the number of permutations in the symmetric group S_n such that their cycle decomposition contains no 7-cycle.

Original entry on oeis.org

1, 1, 2, 6, 24, 120, 720, 4320, 34560, 311040, 3110400, 34214400, 410572800, 5337446400, 75613824000, 1134207360000, 18147317760000, 308504401920000, 5553079234560000, 105508505456640000, 2110170109132800000, 44288746761093120000, 974352428744048640000
Offset: 0

Views

Author

Avi Peretz (njk(AT)netvision.net.il), Apr 22 2001

Keywords

Comments

This is the expansion of exp ((-x^7)/7)/(1-x).

Examples

			a(7) = 4320 because in S_7 the permutations with no 7-cycle are the complement of the 720 7-cycles so a(7) = 7! - 720 = 4320.
		

References

  • R. P. Stanley, Enumerative Combinatorics, Wadsworth, Vol. 1, 1986, page 93, problem 7.

Crossrefs

Programs

  • Maple
    for n from 0 to 30 do printf(`%d,`, n! * sum(( (-1)^i /(i! * 7^i)), i=0..floor(n/7))) od:
  • PARI
    { for (n=0, 100, write("b060727.txt", n, " ", n! * sum(i=0, n\7, (-1)^i / (i! * 7^i))); ) } \\ Harry J. Smith, Jul 10 2009

Formula

The formula for a(n) is: a(n) = n! * sum i=0 ... [ n/7 ]( (-1)^i /(i! * 7^i)) by this formula we have as n -> infinity: a(n)/n! ~ sum i >= 0 (-1)^i /(i! * 7^i) = e^(-1/7) or a(n) ~ e^(-1/7) * n! and using Stirling's formula in A000142: a(n) ~ e^(-1/7) * (n/e)^n * sqrt(2 * Pi * n)
a(n,k) = n!*floor(floor(n/k)!*k^floor(n/k)/exp(1/k) + 1/2)/(floor(n/k)!*k^floor(n/k)), k=7, n>=0. - Simon Plouffe, Feb 18 2011

Extensions

More terms from James Sellers, Apr 24 2001

A102736 Number of permutations of n elements without cycles whose length is a multiple of 3.

Original entry on oeis.org

1, 1, 2, 4, 16, 80, 400, 2800, 22400, 179200, 1792000, 19712000, 216832000, 2818816000, 39463424000, 552487936000, 8839806976000, 150276718592000, 2554704216064000, 48539380105216000, 970787602104320000, 19415752042086400000, 427146544925900800000, 9824370533295718400000, 225960522265801523200000, 5649013056645038080000000, 146874339472770990080000000, 3818732826292045742080000000
Offset: 0

Views

Author

Vladeta Jovovic, Feb 08 2005

Keywords

Comments

Differs from A247007 first at n=27. - Alois P. Heinz, Sep 09 2014

Examples

			G.f. = 1 + x + 2*x^2 + 4*x^3 + 16*x^4 + 80*x^5 + 400*x^6 + 2800*x^7 + ...
		

Crossrefs

Programs

  • Maple
    a:= proc(n) option remember; `if`(n=0, 1, add(`if`(
          irem(j, 3)=0, 0, a(n-j)*(j-1)!*binomial(n-1, j-1)), j=1..n))
        end:
    seq(a(n), n=0..27);  # Alois P. Heinz, Jul 31 2017
  • Mathematica
    nn=21;a=Sum[x^n/n,{n,3,nn,3}];Range[0,nn]!CoefficientList[Series[Exp[Log[1/(1-x)]-a],{x,0,nn}],x]  (* Geoffrey Critzer, Nov 11 2012 *)
    a[ n_] := If[ n < 0, 0, n! With[{m = Quotient[n, 3]}, (-1)^m Binomial[-2/3, m]]]; (* Michael Somos, Aug 05 2016 *)
  • PARI
    {a(n) = my(m); if( n<0, 0, m = n\3; n! * (-1)^m * binomial(-2/3, m))}; /* Michael Somos, Aug 05 2016 */

Formula

E.g.f.: (1-x^3)^(1/3)/(1-x).
a(n) ~ n! * 3^(1/3) / (GAMMA(2/3) * n^(1/3)). - Vaclav Kotesovec, Mar 15 2014

A122974 Triangle T(n,k), the number of permutations on n elements that have no cycles of length k.

Original entry on oeis.org

0, 1, 1, 2, 3, 4, 9, 15, 16, 18, 44, 75, 80, 90, 96, 265, 435, 520, 540, 576, 600, 1854, 3045, 3640, 3780, 4032, 4200, 4320, 14833, 24465, 29120, 31500, 32256, 33600, 34560, 35280, 133496, 220185, 259840, 283500, 290304, 302400, 311040, 317520, 322560
Offset: 1

Views

Author

Dennis P. Walsh, Oct 27 2006

Keywords

Comments

Read as sequence, a(n) is the number of permutations on j elements with no cycles of length i where j=round((2*n)^.5) and i=n-C(j,2).
T(n,k) generalizes several sequences already in the On-Line Encyclopedia, such as A000166, the number of permutations on n elements with no fixed points and A000266, the number of permutations on n elements with no transpositions (i.e., no 2-cycles). See the cross references for further examples.

Examples

			T(3,2)=3 since there are exactly 3 permutations of 1,2,3 that have no cycles of length 2, namely, (1)(2)(3),(1 2 3) and (2 1 3).
Triangle T(n,k) begins:
      0;
      1,     1;
      2,     3,     4;
      9,    15,    16,    18;
     44,    75,    80,    90,    96;
    265,   435,   520,   540,   576,   600;
   1854,  3045,  3640,  3780,  4032,  4200,  4320;
  14833, 24465, 29120, 31500, 32256, 33600, 34560, 35280;
  ...
		

Crossrefs

Cf. T(n, 1)=A000166 for n=>1 T(n, 2)=A000266 for n=>2 T(n, 3)=A000090 for n=>3 T(n, 4)=A000138 for n=>4 T(n, 5)=A060725 for n=>5 T(n, 6)=A060726 for n=>6 T(n, 7)=A060727 for n=>7.
T(n,n) gives A094304(n+1).

Programs

  • Maple
    seq((round((2*n)^.5))!*sum((-1/(n-binomial(round((2*n)^.5),2)))^r/r!,r=0..floor(round((2*n)^.5)/(n-binomial(round((2*n)^.5),2)))),n=1..66);
    # second Maple program:
    T:= proc(n, k) option remember; `if`(n=0, 1, add(`if`(j=k, 0,
          T(n-j, k)*binomial(n-1, j-1)*(j-1)!), j=1..n))
        end:
    seq(seq(T(n, k), k=1..n), n=1..12);  # Alois P. Heinz, Nov 24 2019
  • Mathematica
    T[n_, k_] := T[n, k] = If[n==0, 1, Sum[If[j==k, 0, T[n - j, k] Binomial[n - 1, j - 1] (j - 1)!], {j, 1, n}]];
    Table[Table[T[n, k], {k, 1, n}], {n, 1, 12}] // Flatten (* Jean-François Alcover, Dec 08 2019, after Alois P. Heinz *)

Formula

T(n,k)=n!*sum r=0..floor(n/k)((-1/k)^r/r!) E.G.F: exp(-x^k/k)/(1-x) a(n)=(round((2*n)^.5))!*sum((-1/(n-binomial(round((2*n)^.5),2)))^r/r!,r=0..floor(round((2*n)^.5)/(n-binomial(round((2*n)^.5),2)))).
T(n,k) = n! - A293211(n,k). - Alois P. Heinz, Nov 24 2019

A319364 Expansion of e.g.f. exp(x^3/3)/(1 - x).

Original entry on oeis.org

1, 1, 2, 8, 32, 160, 1000, 7000, 56000, 506240, 5062400, 55686400, 668483200, 8690281600, 121663942400, 1825003980800, 29200063692800, 496401082777600, 8935231687782400, 169769402067865600, 3395388041357312000, 71303153503662080000, 1568669377080565760000, 36079395672853012480000
Offset: 0

Views

Author

Ilya Gutkovskiy, Sep 17 2018

Keywords

Crossrefs

Programs

  • Maple
    seq(n!*coeff(series(exp(x^3/3)/(1 - x),x=0,24),x,n),n=0..23); # Paolo P. Lava, Jan 09 2019
  • Mathematica
    nmax = 23; CoefficientList[Series[Exp[x^3/3]/(1 - x), {x, 0, nmax}], x] Range[0, nmax]!
  • PARI
    my(x='x+O('x^30)); Vec(serlaplace(exp(x^3/3)/(1 - x))) \\ Michel Marcus, Dec 17 2020

Formula

a(n) ~ n!*exp(1/3).
D-finite with recurrence: n*a(n) - n^2*a(n-1) - n*(n-1)*(n-2)*a(n-3) + n*(n-1)*(n-2)*(n-3)*a(n-4) = 0. - Robert Israel, Dec 17 2020
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