A047659 -id:A047659 - cp's OEIS frontend

A000170 Number of ways of placing n nonattacking queens on an n X n board.

1, 1, 0, 0, 2, 10, 4, 40, 92, 352, 724, 2680, 14200, 73712, 365596, 2279184, 14772512, 95815104, 666090624, 4968057848, 39029188884, 314666222712, 2691008701644, 24233937684440, 227514171973736, 2207893435808352, 22317699616364044, 234907967154122528

Offset: 0

N. J. A. Sloane

For n > 3, a(n) is the number of maximum independent vertex sets in the n X n queen graph. - Eric W. Weisstein, Jun 20 2017
Number of nodes on level n of the backtrack tree for the n queens problem (a(n) = A319284(n, n)). - Peter Luschny, Sep 18 2018
Number of permutations of [1...n] such that |p(j)-p(i)| != j-i for iXiangyu Chen, Dec 24 2020
M. Simkin shows that the number of ways to place n mutually nonattacking queens on an n X n chessboard is ((1 +/- o(1))*n*exp(-c))^n, where c = 1.942 +/- 0.003. These are approximately (0.143*n)^n configurations. - Peter Luschny, Oct 07 2021

			a(2) = a(3) = 0, since on 2 X 2 and 3 X 3 chessboards there are no solutions.
.
a(4) = 2:
  +---------+ +---------+
  | . . Q . | | . Q . . |
  | Q . . . | | . . . Q |
  | . . . Q | | Q . . . |
  | . Q . . | | . . Q . |
  +---------+ +---------+
a(5) = 10:
  +-----------+ +-----------+ +-----------+ +-----------+ +-----------+
  | . . . Q . | | . . Q . . | | . . . . Q | | . . . Q . | | . . . . Q |
  | . Q . . . | | . . . . Q | | . . Q . . | | Q . . . . | | . Q . . . |
  | . . . . Q | | . Q . . . | | Q . . . . | | . . Q . . | | . . . Q . |
  | . . Q . . | | . . . Q . | | . . . Q . | | . . . . Q | | Q . . . . |
  | Q . . . . | | Q . . . . | | . Q . . . | | . Q . . . | | . . Q . . |
  +-----------+ +-----------+ +-----------+ +-----------+ +-----------+
  +-----------+ +-----------+ +-----------+ +-----------+ +-----------+
  | Q . . . . | | . Q . . . | | Q . . . . | | . . Q . . | | . Q . . . |
  | . . . Q . | | . . . . Q | | . . Q . . | | Q . . . . | | . . . Q . |
  | . Q . . . | | . . Q . . | | . . . . Q | | . . . Q . | | Q . . . . |
  | . . . . Q | | Q . . . . | | . Q . . . | | . Q . . . | | . . Q . . |
  | . . Q . . | | . . . Q . | | . . . Q . | | . . . . Q | | . . . . Q |
  +-----------+ +-----------+ +-----------+ +-----------+ +-----------+
a(6) = 4:
  +-------------+ +-------------+ +-------------+ +-------------+
  | . . . . Q . | | . . . Q . . | | . . Q . . . | | . Q . . . . |
  | . . Q . . . | | Q . . . . . | | . . . . . Q | | . . . Q . . |
  | Q . . . . . | | . . . . Q . | | . Q . . . . | | . . . . . Q |
  | . . . . . Q | | . Q . . . . | | . . . . Q . | | Q . . . . . |
  | . . . Q . . | | . . . . . Q | | Q . . . . . | | . . Q . . . |
  | . Q . . . . | | . . Q . . . | | . . . Q . . | | . . . . Q . |
  +-------------+ +-------------+ +-------------+ +-------------+
- _Hugo Pfoertner_, Mar 17 2019

M. Gardner, The Unexpected Hanging, pp. 190-2, Simon & Shuster NY 1969
Jieh Hsiang, Yuh-Pyng Shieh and Yao-Chiang Chen, The cyclic complete mappings counting problems, in Problems and Problem Sets for ATP, volume 02-10 of DIKU technical reports, G. Sutcliffe, J. Pelletier and C. Suttner, eds., 2002.
D. E. Knuth, The Art of Computer Programming, Volume 4, Pre-fascicle 5B, Introduction to Backtracking, 7.2.2. Backtrack programming. 2018.
M. Kraitchik, The Problem of The Queens, Mathematical Recreations, 2nd ed., New York, Dover, 1953, pp. 247-256.
Massimo Nocentini, "An algebraic and combinatorial study of some infinite sequences of numbers supported by symbolic and logic computation", PhD Thesis, University of Florence, 2019. See Ex. 67.
W. W. Rouse Ball and H. S. M. Coxeter, Mathematical Recreations and Essays, 13th ed., New York, Dover, 1987, pp. 166-172 (The Eight Queens Problem).
M. A. Sainte-Laguë, Les Réseaux (ou Graphes), Mémorial des Sciences Mathématiques, Fasc. 18, Gauthier-Villars, Paris, 1926, p. 47.
N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
R. J. Walker, An enumerative technique for a class of combinatorial problems, pp. 91-94 of Proc. Sympos. Applied Math., vol. 10, Amer. Math. Soc., 1960.
M. B. Wells, Elements of Combinatorial Computing. Pergamon, Oxford, 1971, p. 238.

Jordan Bell and Brett Stevens, A survey of known results and research areas for n-queens, Discrete Mathematics, Volume 309, Issue 1, Jan 06 2009, Pages 1-31.
D. Bill, Durango Bill's The N-Queens Problem
J. R. Bitner and E. M. Reingold, Backtrack programming techniques, Commun. ACM, 18 (1975), 651-656.
J. R. Bitner and E. M. Reingold, Backtrack programming techniques, Commun. ACM, 18 (1975), 651-656. [Annotated scanned copy]
Candida Bowtell and Peter Keevash, The n-queens problem, arXiv:2109.08083 [math.CO] 2021.
P. Capstick and K. McCann, The problem of the n queens, apparently unpublished, no date (circa 1990?) [Scanned copy]
V. Chvatal, All solutions to the problem of eight queens
V. Chvatal, All solutions to the problem of eight queens [Cached copy, pdf format, with permission]
Gheorghe Coserea, Solutions for n=8.
Gheorghe Coserea, Solutions for n=9.
Gheorghe Coserea, MiniZinc model for generating solutions.
Matteo Fischetti and Domenico Salvagnin, Chasing First Queens by Integer Programming, 2018.
Matteo Fischetti and Domenico Salvagnin, Finding First and Most-Beautiful Queens by Integer Programming, arXiv:1907.08246 [cs.DS], 2019.
J. Freeman, A neural network solution to the n-queens problem, The Mathematica J., 3 (No. 3, 1993), 52-56.
Ian P. Gent, Christopher Jefferson and Peter Nightingale, Complexity of n-Queens Completion, Journal of Artificial Intelligence Research 59 (2017), see p 816.
Eric Grigoryan, Investigation of the Regularities in the Formation of Solutions n-Queens Problem, Modeling of Artificial Intelligence, 2018, 5(1), 3-21.
E. Grigoryan, Linear algorithm for solution n-Queens Completion problem, arXiv:1912.05935 [cs.AI], 2019.
James Grime and Brady Haran, The 8 Queen Problem, Numberphile video (2015).
Michael Han, Tanya Khovanova, Ella Kim, Evin Liang, Miriam Lubashev, Oleg Polin, Vaibhav Rastogi, Benjamin Taycher, Ada Tsui and Cindy Wei, Fun with Latin Squares, arXiv:2109.01530 [math.HO], 2021.
Kenji Kise, Takahiro Katagiri, Hiroki Honda and Toshitsugu Yuba, Solving the 24-queens Problem using MPI on a PC Cluster, Technical Report UEC-IS-2004-6, Graduate School of Information Systems, The University of Electro-Communications (2004).
D. E. Knuth, Donald Knuth's 24th Annual Christmas Lecture: Dancing Links, Stanfordonline, Video published on YouTube, Dec 12, 2018.
W. Kosters, n-Queens bibliography
Vaclav Kotesovec, Non-attacking chess pieces, Sixth edition, 795 pages, Feb 02 2013 (minor update Mar 29 2016).
Zur Luria, New bounds on the number of n-queens configurations, arXiv:1705.05225 [math.CO], 2017.
Zur Luria, Michael Simkin, A lower bound for the n-queens problem, arXiv:2105.11431 [math.CO], 2021.
E. Masehian, H. Akbaripour and N. Mohabbati-Kalejahi, Solving the n Queens Problem using a Tuned Hybrid Imperialist Competitive Algorithm, 2013.
E. Masehian, H. Akbaripour and N. Mohabbati-Kalejahi, Landscape analysis and efficient metaheuristics for solving the n-queens problem, Computational Optimization and Applications, 2013; DOI 10.1007/s10589-013-9578-z.
Nasrin Mohabbati-Kalejahi, Hossein Akbaripour and Ellips Masehian, Basic and Hybrid Imperialist Competitive Algorithms for Solving the Non-attacking and Non-dominating n -Queens Problems, Studies in Computational Intelligence Volume 577, 2015, pp 79-96. DOI 10.1007/978-3-319-11271-8_6.
Ralph Morrison and Noah Speeter, The Gonality of Queen's Graphs, arXiv:2312.04686 [math.CO], 2023.
Parth Nobel, Akshay Agrawal and Stephen Boyd, Computing tighter bounds on the n-queens constant via Newton’s method, arXiv:2112.03336 [math.CO], 2021.
J. Pope and D. Sonnier, A linear solution to the n-Queens problem using vector spaces, Journal of Computing Sciences in Colleges, Volume 29 Issue 5, May 2014 Pages 77-83.
T. B. Preußer and M. R. Engelhardt, Putting Queens in Carry Chains, No. 27, Journal of Signal Processing Systems, Volume 88, Issue 2, August 2017. (The title refers to the fact that the article discusses the case n = 27.)
Thomas B. Preußer, Bernd Nägel and Rainer G. Spallek, Putting Queens in Carry Chains, Slides, HIPEAC WRC'09.
E. M. Reingold, Letter to N. J. A. Sloane, Dec 27 1973
I. Rivin, I. Vardi and P. Zimmermann, The n-queens problem, Amer. Math. Monthly, 101 (1994), 629-639.
Werner Florian Samayoa, Maria Liz Crespo, Sergio Carrato, Agustin Silva, and Andres Cicuttin, HyperFPGA: An Experimental Testbed for Heterogeneous Supercomputing, 2023.
Michael Simkin, The number of n-queens configurations, arXiv:2107.13460 [math.CO], 2021.
Wenxi Wang, Muhammad Usman, Alyas Almaawi, Kaiyuan Wang, Kuldeep S. Meel and Sarfraz Khurshid, A Study of Symmetry Breaking Predicates and Model Counting, National University of Singapore (2020).
Eric Weisstein's World of Mathematics, Maximum Independent Vertex Set
Eric Weisstein's World of Mathematics, Queen Graph
Eric Weisstein's World of Mathematics, Queens Problem
M. B. Wells, Elements of Combinatorial Computing, Pergamon, Oxford, 1971. [Annotated scanned copy of pages 237-240]
Wikipedia, Eight Queens Puzzle
Cheng Zhang and Jianpeng Ma, Counting Solutions for the N-queens and Latin Square Problems by Efficient Monte Carlo Simulations, arXiv:0808.4003 [cond-mat.stat-mech], 2008.

Cf. A002562, A065256.
Cf. A036464 (2Q), A047659 (3Q), A061994 (4Q), A108792 (5Q), A176186 (6Q).
Cf. A099152, A006717, A051906, A319284 (backtrack trees).
Cf. A260318, A260319, A260320.
Main diagonal of A348129.

Strong conjecture: there is a constant c around 2.54 such that a(n) is asymptotic to n!/c^n; weak conjecture: lim_{n -> infinity} (1/n) * log(n!/a(n)) = constant = 0.90.... - Benoit Cloitre, Nov 10 2002
Lim_{n->infinity} a(n)^(1/n)/n = exp(-A359441) = 0.1431301... [Simkin 2021]. - Vaclav Kotesovec, Jan 01 2023
a(n) = 8 * A260320(n) + 4 * A260319(n) + 2 * A260318(n) for n >= 2 (see Kraitchik reference). - Jason Bard, Aug 12 2025

Terms for n=21-23 computed by Sylvain PION (Sylvain.Pion(AT)sophia.inria.fr) and Joel-Yann FOURRE (Joel-Yann.Fourre(AT)ens.fr).
a(24) from Kenji KISE (kis(AT)is.uec.ac.jp), Sep 01 2004
a(25) from Objectweb ProActive INRIA Team (proactive(AT)objectweb.org), Jun 11 2005 [Communicated by Alexandre Di Costanzo (Alexandre.Di_Costanzo(AT)sophia.inria.fr)]. This calculation took about 53 years of CPU time.
a(25) has been confirmed by the NTU 25Queen Project at National Taiwan University and Ming Chuan University, led by Yuh-Pyng (Arping) Shieh, Jul 26 2005. This computation took 26613 days CPU time.
The NQueens-at-Home web site gives a different value for a(24), 226732487925864. Thanks to Goran Fagerstrom for pointing this out. I do not know which value is correct. I have therefore created a new entry, A140393, which gives the NQueens-at-home version of the sequence. - N. J. A. Sloane, Jun 18 2008
It now appears that this sequence (A000170) is correct and A140393 is wrong. - N. J. A. Sloane, Nov 08 2008
Added a(26) as calculated by Queens(AT)TUD [http://queens.inf.tu-dresden.de/]. - Thomas B. Preußer, Jul 11 2009
Added a(27) as calculated by the Q27 Project [https://github.com/preusser/q27]. - Thomas B. Preußer, Sep 23 2016
a(0) = 1 prepended by Joerg Arndt, Sep 16 2018

A036464 Number of ways to place two nonattacking queens on an n X n board.

Original entry on oeis.org

0, 0, 8, 44, 140, 340, 700, 1288, 2184, 3480, 5280, 7700, 10868, 14924, 20020, 26320, 34000, 43248, 54264, 67260, 82460, 100100, 120428, 143704, 170200, 200200, 234000, 271908, 314244, 361340, 413540, 471200, 534688, 604384

Offset: 1

Robert G. Wilson v, Raymond Bush (c17h21no4(AT)hotmail.com), Kirk Conely, N. J. A. Sloane

Vincenzo Librandi, Table of n, a(n) for n = 1..1000
S. Chaiken, C. R. H. Hanusa and T. Zaslavsky, A q-queens problem I. General theory, January 26, 2013. - _N. J. A. Sloane_, Feb 16 2013
S. Chaiken, C. R. H. Hanusa and T. Zaslavsky, A q-Queens Problem. IV. Queens, Bishops, Nightriders (and Rooks), arXiv:1609.00853 [math.CO], Sep 03 2016.
V. Kotesovec, Non-attacking chess pieces
I. Rivin, I. Vardi and P. Zimmermann, The n-queens problem, Amer. Math. Monthly, 101 (1994), 629-639.
Index entries for linear recurrences with constant coefficients, signature (5,-10,10,-5,1).

Cf. A047659, A061994, A108792, A176186, A178721.

Column k=2 of A348129.

f:=n->n^4/2 - 5*n^3/3 + 3*n^2/2 - n/3; [seq(f(n),n=1..200)]; # N. J. A. Sloane, Feb 16 2013

f[k_] := 2 k; t[n_] := Table[f[k], {k, 1, n}]
a[n_] := SymmetricPolynomial[2, t[n]]
Table[a[n], {n, 2, 50}]   (* A036464 *)
Table[a[n]/4, {n, 2, 50}] (* A000914 *)
(* Clark Kimberling, Dec 31 2011 *)
CoefficientList[Series[4 x^2 (2 + x) / (1-x)^5, {x, 0, 40}], x] (* Vincenzo Librandi, May 02 2013 *)
LinearRecurrence[{5,-10,10,-5,1},{0,0,8,44,140},50] (* Harvey P. Dale, Mar 26 2015 *)

a(n) = C(n, 3)*(3*n-1).
G.f.: 4*x^3*(2+x)/(1-x)^5. - Colin Barker, May 02 2012
a(n) = 2*sum_{i=1..n-2} i(i + 1)^2. - Wesley Ivan Hurt, Mar 18 2014
E.g.f.: (exp(x) * x^3 * (8 + 3*x))/6. - Vaclav Kotesovec, Feb 15 2015
For n>0, a(n) = A163102(n-1) - A006331(n-1). - Antal Pinter, Sep 20 2015

A061994 Number of ways to place 4 nonattacking queens on an n X n board.

Original entry on oeis.org

0, 0, 0, 0, 2, 82, 982, 7002, 34568, 131248, 412596, 1123832, 2739386, 6106214, 12654614, 24675650, 45704724, 80999104, 138170148, 227938788, 365106738, 569681574, 868289594, 1295775946, 1897176508, 2729909796

Offset: 0

Antonio G. Astudillo (afg_astudillo(AT)hotmail.com), May 31 2001

An analytical solution for the 4-queens problem permits us to combine six particular cases into a single "unified" expression: a(n) = n(n-1)(45n^6 - 855n^5 + 6945n^4 - 30891n^3 + 78864n^2 - 106226n + 53404)/1080 + (n^3 - 21/2n^2 + 28n - 14)*floor(n/2) + 32/9(n-1)*floor(n/3) + (16/9n-4)*floor((n+1)/3). The method used to derive this formula helps to fine-tune an estimate by E. Lucas for a(n) (see comment to A047659 "3-queens problem"). For any fixed value of k > 1, a(n) = n^(2k)/k! - 5/3n^(2k-1)/(k-2)! + O(n^(2k-2)). - Sergey Perepechko, Sep 16 2005

Vaclav Kotesovec, Between chessboard and computer, 1996, pp. 204-206.

Vincenzo Librandi, Table of n, a(n) for n = 0..1000
Louis Azemard, Une communication de Vaclav Kotesovec, Echecs et Mathématiques, Rex Multiplex 38/1992.
Vaclav Kotesovec, Non-attacking chess pieces, 6ed, 2013, p. 12.
Index entries for linear recurrences with constant coefficients, signature (3,1,-9,0,12,7,-15,-16,16,15,-7,-12,0,9,-1,-3,1).

Cf. A036464, A047659.

Column k=4 of A348129.

CoefficientList[Series[x^4*(2 +76*x +734*x^2 +3992*x^3 +13318*x^4 +29356*x^5 +46304*x^6 +53580*x^7 +46890*x^8 +29768*x^9 +13522*x^10 +3804*x^11 +574*x^12)/((1-x)^3*(1-x^2)^4*(1-x^3)^2), {x, 0, 40}], x] (* Vincenzo Librandi, May 12 2013 *)
LinearRecurrence[{3,1,-9,0,12,7,-15,-16,16,15,-7,-12,0,9,-1,-3,1}, {0,0,0,0,2,82, 982,7002,34568,131248,412596,1123832,2739386,6106214,12654614,24675650, 45704724}, 40] (* Harvey P. Dale, Jan 21 2017 *)

def p(x): return x^4*(2 +76*x +734*x^2 +3992*x^3 +13318*x^4 +29356*x^5 +46304*x^6 +53580*x^7 +46890*x^8 +29768*x^9 +13522*x^10 +3804*x^11 +574*x^12)/((1-x)^3*(1-x^2)^4*(1-x^3)^2)
def A061994_list(prec):
    P. = PowerSeriesRing(ZZ, prec)
    return P( p(x) ).list()
A061994_list(40) # G. C. Greubel, Apr 30 2022

G.f.: x^4*(2 + 76*x + 734*x^2 + 3992*x^3 + 13318*x^4 + 29356*x^5 + + 46304*x^6 + + 53580*x^7 + 46890*x^8 + 29768*x^9 + 13522*x^10 + 3804*x^11 + 574*x^12)/((1-x)^3*(1-x^2)^4*(1-x^3)^2).
Recurrence: a(n) = 3*a(n-1) + a(n-2) - 9*a(n-3) + 12*a(n-5) + 7*a(n-6) - 15*a(n-7) - 16*a(n-8) + 16*a(n-9) + 15*a(n-10) - 7*a(n-11) - 12*a(n-12) + 9*a(n-14) - a(n-15) - 3*a(n-16) + a(n-17), n >= 17.
Explicit formula (V. Kotesovec, 1992) for n >= 2: a(n) = n^8/24 - 5*n^7/6 + 65*n^6/9 - 1051*n^5/30 + 817*n^4/8 added to one of the following terms:
  - 4769*n^3/27 + 1963*n^2/12 - 1769*n/30         if n = 0 (mod 6)
  - 9565*n^3/54 + 1013*n^2/6 - 6727*n/90 + 257/27 if n = 1 (mod 6)
  - 4769*n^3/27 + 1963*n^2/12 - 5467*n/90 + 28/27 if n = 2 (mod 6)
  - 9565*n^3/54 + 1013*n^2/6 - 2189*n/30 + 7      if n = 3 (mod 6)
  - 4769*n^3/27 + 1963*n^2/12 - 5467*n/90 + 68/27 if n = 4 (mod 6)
  - 9565*n^3/54 + 1013*n^2/6 - 6727*n/90 + 217/27 if n = 5 (mod 6).
a(n) = n^8/24 - 5n^7/6 + 65n^6/9 - 1051n^5/30 + 817n^4/8 - 19103n^3/108 + 3989n^2/24 - 18131n/270 + 253/54 + (n^3/4 - 21n^2/8 + 7n - 7/2)*(-1)^n + 32*(n - 1)/27*cos(2*Pi*n/3) + 40/81*sqrt(3)*sin(2*Pi*n/3). - Vaclav Kotesovec, Feb 11 2010
E.g.f.: (3*(exp(2*x)*(5060 - 4645*x + 1755*x^2 - 590*x^3 + 480*x^4 + 414*x^5 + 870*x^6 + 360*x^7 + 45*x^8) - 135*(28 + 37*x + 15*x^2 + 2*x^3)) - 1920 * exp(x/2) * (2+x) * cos(sqrt(3)*x/2) - 320 * sqrt(3) * exp(x/2) * (6*x-5) * sin(sqrt(3)*x/2)) / (3240 * exp(x)). - Vaclav Kotesovec, Feb 15 2015

Minor edits by Vaclav Kotesovec, Feb 15 2015

A108792 Number of ways to place 5 nonattacking queens on an n X n board.

Original entry on oeis.org

10, 248, 4618, 46736, 310496, 1535440, 6110256, 20609544, 60963094, 162323448, 396155466, 899046952, 1917743448, 3879011584, 7491080844, 13892164232, 24854703014, 43071383040, 72532831794, 119038462248, 190849299076

Offset: 5

Sergey Perepechko, Jul 09 2005

Vincenzo Librandi, Table of n, a(n) for n = 5..1000
Christopher R. H. Hanusa, T Zaslavsky, S Chaiken, A q-Queens Problem. IV. Queens, Bishops, Nightriders (and Rooks), arXiv preprint arXiv:1609.00853, a12016
V. Kotesovec, Non-attacking chess pieces
Index entries for linear recurrences with constant coefficients, signature (1, -3, -7, -3, 11, 21, 13, -13, -41, -44, -8, 49, 81, 57, -15, -88, -106, -48, 48, 106, 88, 15, -57, -81, -49, 8, 44, 41, 13, -13, -21, -11, 3, 7, 3, -1, -1).

Cf. A047659, A061994.

Column k=5 of A348129.

CoefficientList[Series[-(14206 x^31 + 150238*x^30 + 916976 x^29 + 3972232 x^28 + 13522008 x^27 + 37968860 x^26 + 90996604 x^25 + 190236360 x^24 + 352607230 x^23 + 586165718 x^22 + 881664746 x^21 + 1207443842 x^20 + 1512654886 x^19 + 1738866194 x^18 + 1837742548 x^17 + 1786911600 x^16 + 1598078300 x^15 + 1312598856 x^14 + 987611934 x^13 + 677994354 x^12 + 422347390 x^11 + 236939238 x^10 + 118533110 x^9 + 52176470 x^8 + 19855936 x^7 + 6376140 x^6 + 1672768 x^5 + 341612 x^4 + 50540 x^3 + 4836 x^2 + 258 x + 10) / ((x - 1)^11 (x + 1)^6 (x^2 + 1)^2 (x^2 + x + 1)^4 (x^4 + x^3 + x^2 + x + 1)^2), {x, 0, 35}], x] (* Vincenzo Librandi, May 16 2013 *)
LinearRecurrence[{-1,3,7,3,-11,-21,-13,13,41,44,8,-49,-81,-57,15,88,106,48,-48,-106,-88,-15,57,81,49,-8,-44,-41,-13,13,21,11,-3,-7,-3,1,1},{10,248,4618,46736,310496,1535440,6110256,20609544,60963094,162323448,396155466,899046952,1917743448,3879011584,7491080844,13892164232,24854703014,43071383040,72532831794,119038462248,190849299076,299547508728,461105824676,697264240408,1037206552414,1519678218528,2195518394830,3130809484640,4410583469036,6143370199976,8466479411308,11552406363136,15616183774498,20924209082128,27804270360662,36657476189408,47971684617044},25] (* Harvey P. Dale, Mar 29 2025 *)

Explicit formula (Vaclav Kotesovec, Apr 04 2010): a(n) = 1/120*n^10 - 5/18*n^9 + 301/72*n^8 - 1679/45*n^7 + 78383/360*n^6 - 77519/90*n^5 + 1867681/810*n^4 - 6499681/1620*n^3 + 5324093/1296*n^2 - 12758453/6480*n + 13038851/64800 + (1/8*n^5 - 143/48*n^4 + 82/3*n^3 - 5647/48*n^2 + 10475/48*n - 3547/32)*(-1)^n + (29/2*n - 35/2)*cos(Pi*n/2) + (2*n+15)*sin(Pi*n/2) + (32/27*n^3 - 1328/81*n^2 + 6328/81*n - 5488/81)*cos(2*Pi*n/3) + (40*sqrt(3)/81*n^2 - 1496*sqrt(3)/243*n + 7024*sqrt(3)/243)*sin(2*Pi*n/3) + ((8*sqrt(5)/25 + 8/5)*n - 16*sqrt(5)/25 - 64/25)*cos(2*Pi*n/5) + 8*sqrt(22*sqrt(5)+50)/25*sin(2*Pi*n/5) + ((8/5-8*sqrt(5)/25)*n+16*sqrt(5)/25-64/25)*cos(Pi*n/5)*(-1)^n - 8*sqrt(50-22*sqrt(5))/25*sin(Pi*n/5)*(-1)^n. - Vaclav Kotesovec, Apr 04 2010
G.f.: -x^5*(14206*x^31+150238*x^30+916976*x^29+3972232*x^28+13522008*x^27+37968860*x^26+90996604*x^25+190236360*x^24+352607230*x^23+586165718*x^22+881664746*x^21+1207443842*x^20+1512654886*x^19+1738866194*x^18+1837742548*x^17+1786911600*x^16+1598078300*x^15+1312598856*x^14+987611934*x^13+677994354*x^12+422347390*x^11+236939238*x^10+118533110*x^9+52176470*x^8+19855936*x^7+6376140*x^6+1672768*x^5+341612*x^4+50540*x^3+4836*x^2+258*x+10)/((x-1)^11*(x+1)^6*(x^2+1)^2*(x^2+x+1)^4*(x^4+x^3+x^2+x+1)^2),
Recurrence: a(n)= - a(n-1) + 3*a(n-2) + 7*a(n-3) + 3*a(n-4) - 11*a(n-5) - 21*a(n-6) - 13*a(n-7) + 13*a(n-8) + 41*a(n-9) + 44*a(n-10) + 8*a(n-11) - 49*a(n-12) - 81*a(n-13) - 57*a(n-14) + 15*a(n-15) + 88*a(n-16) +106*a(n-17) + 48*a(n-18) - 48*a(n-19) -106*a(n-20) - 88*a(n-21) - 15*a(n-22) + 57*a(n-23) + 81*a(n-24) + 49*a(n-25) - 8*a(n-26) - 44*a(n-27) - 41*a(n-28) - 13*a(n-29) + 13*a(n-30) + 21*a(n-31) + 11*a(n-32) - 3*a(n-33) - 7*a(n-34) - 3*a(n-35) + a(n-36) + a(n-37). - Vaclav Kotesovec, Apr 05 2010

A002624 Expansion of (1-x)^(-3) * (1-x^2)^(-2).

Original entry on oeis.org

1, 3, 8, 16, 30, 50, 80, 120, 175, 245, 336, 448, 588, 756, 960, 1200, 1485, 1815, 2200, 2640, 3146, 3718, 4368, 5096, 5915, 6825, 7840, 8960, 10200, 11560, 13056, 14688, 16473, 18411, 20520, 22800, 25270, 27930, 30800, 33880, 37191, 40733, 44528

Offset: 0

N. J. A. Sloane

Given an irregular triangular matrix M with the triangular numbers in every column shifted down twice for columns >0, A002624 = M * [1, 2, 3, ...]. Example: row 4 of triangle M = (15, 6, 1), then (15, 6, 1) dot (1, 2, 3) = a(4) = 30 = (15 + 12 + 3). - Gary W. Adamson, Mar 02 2010
The Kn21, Kn22, Kn23, Fi2 and Ze2 triangle sums of A139600 are related to the sequence given above, e.g., Ze2(n) = a(n-1) - a(n-2) - a(n-3) + 4*a(n-4), with a(n) = 0 for n <= -1. For the definitions of these triangle sums see A180662. - Johannes W. Meijer, Apr 29 2011
8*a(n) + 16*a(n+1) + 16*a(n+2) is the number of ways to place 3 queens on an (n+6) X (n+6) chessboard so that they diagonally attack each other exactly twice. Also true for the nonexistent terms for n=-1, n=-2 and n=-3 assuming that they are zeros. In graph-theory representation they thus form the corresponding open walk (Eulerian trail) with V={1,2,3} vertices and length of 2. - Antal Pinter, Dec 31 2015
a(n) is the number of partitions of n into parts with three kinds of 1 and two kinds of 2. - Joerg Arndt, Jan 18 2016

N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Vincenzo Librandi, Table of n, a(n) for n = 0..10000
Steven Edwards and William Griffiths, Generalizations of Delannoy and cross polytope numbers, Fib. Q., Vol. 55, No. 4 (2017), pp. 356-366.
E. Fix and J. L. Hodges, Jr., Significance probabilities of the Wilcoxon test, Annals Math. Stat., 26 (1955), 301-312.
E. Fix and J. L. Hodges, Significance probabilities of the Wilcoxon test, Annals Math. Stat., 26 (1955), 301-312. [Annotated scanned copy]
Jia Huang, Partially Palindromic Compositions, J. Int. Seq. (2023) Vol. 26, Art. 23.4.1. See pp. 4, 20.
INRIA Algorithms Project, Encyclopedia of Combinatorial Structures 204
Antal Pinter, Numerical solution of the k=3 Queens problem, 2011, Q(n) at p.8.
Antal Pinter, Software utility for enumerating positions of non-attacking and attacking chess pieces , Backtrack_V7Pro
Simon Plouffe, Approximations de séries génératrices et quelques conjectures, Dissertation, Université du Québec à Montréal, 1992; arXiv:0911.4975 [math.NT], 2009.
Simon Plouffe, 1031 Generating Functions, Appendix to Thesis, Montreal, 1992
Index entries for linear recurrences with constant coefficients, signature (3,-1,-5,5,1,-3,1).

Cf. A047659, A139600, A180662.

[( (n+1)^4 +10*(n+1)^3 +32*(n+1)^2 +32*(n+1) +(6*(n+1) +15)*((n+1) mod 2) )/96 : n in [0..50]]; // Vincenzo Librandi, Oct 08 2011

A002624:=-1/(z+1)**2/(z-1)**5; # Simon Plouffe in his 1992 dissertation

f[n_] := Block[{m = n - 1}, (m^4 + 10m^3 + 32m^2 + 32m + (6m + 15)Mod[m, 2])/96]; Table[ f[n], {n, 2, 45}]
(* Or *) CoefficientList[ Series[1/((1 - x)^3 (1 - x^2)^2), {x, 0, 44}], x] (* Robert G. Wilson v, Feb 26 2005 *)

Vec(1/(1-x)^3/(1-x^2)^2+O(x^99)) \\ Charles R Greathouse IV, Apr 19 2012

a(n)=(n^4 + 14*n^3 + 68*n^2 + 136*n - n%2*(6*n + 21))/96 + 1 \\ Charles R Greathouse IV, Feb 18 2016

a(n-1) = ( n^4 +10*n^3 +32*n^2 +32*n +(6*n +15)*(n mod 2) )/96.
From Antal Pinter, Oct 03 2014: (Start)
a(n) = C(n + 2, 2) + 2*C(n, 2) + 3*C(n - 2, 2) + 4*C(n - 4, 2) + ...
a(n) = Sum_{i = 1..z} i*C(n + 4 - 2i, 2)  where z = (2*n + 3 + (-1)^n)/4.
a(n) = (3*(2*n + 7)*(-1)^n + 2*n^4 + 28*n^3 + 136*n^2 + 266*n + 171)/192.
(End)
a(n) = A007009(n+1) - A001752(n-1) for n>0. - Antal Pinter, Dec 27 2015
a(n) = Sum_{j=0..n+1} A006918(j). - Richard Turk, Feb 18 2016

Formula and more terms from Frank Ellermann, Mar 14 2002

A172124 Number of ways to place 3 nonattacking bishops on an n X n board.

Original entry on oeis.org

0, 0, 26, 232, 1124, 3896, 10894, 26192, 56296, 110960, 204130, 355000, 589196, 940072, 1450134, 2172576, 3172944, 4530912, 6342186, 8720520, 11799860, 15736600, 20711966, 26934512, 34642744, 44107856, 55636594, 69574232

Offset: 1

Vaclav Kotesovec, Jan 26 2010

E. Bonsdorff, K. Fabel, O. Riihimaa, Schach und Zahl, 1966, p. 51-63

Vincenzo Librandi, Table of n, a(n) for n = 1..1000
Christopher R. H. Hanusa, T. Zaslavsky, and S. Chaiken, A q-Queens Problem. IV. Queens, Bishops, Nightriders (and Rooks), arXiv preprint arXiv:1609.00853, a12016
Vaclav Kotesovec, Number of ways of placing non-attacking queens and kings on boards of various sizes
Index entries for linear recurrences with constant coefficients, signature (6,-14,14,0,-14,14,-6,1).

Cf. A047659, A172123.

[(n*(n-2)*(2*n^4 -4*n^3 +7*n^2 -6*n +4) +3*(n mod 2))/12: n in [1..40]]; // G. C. Greubel, Apr 16 2022

CoefficientList[Series[2x^2(3x^4 +18x^3 +48x^2 +38x +13)/((1-x)^7 (x+1)), {x, 0, 30}], x] (* Vincenzo Librandi, May 26 2013 *)

[(n*(n-2)*(2*n^4 -4*n^3 +7*n^2 -6*n +4) +3*(n%2))/12 for n in (1..40)] # G. C. Greubel, Apr 16 2022

Explicit formulas (Karl Fabel, 1966): (Start)
a(n) = n*(n-2)*(2*n^4 - 4*n^3 + 7*n^2 - 6*n + 4)/12 if n is even.
a(n) = (n-1)*(2*n^5 - 6*n^4 + 9*n^3 - 11*n^2 + 5*n - 3)/12 if n is odd. (End)
G.f.: 2*x^3*(13+38*x+48*x^2+18*x^3+3*x^4)/((1-x)^7*(1+x)). - .Vaclav Kotesovec, Mar 25 2010
a(n) = (2*(n-2)*n*(2*n^4-4*n^3+7*n^2-6*n+4)-3*(-1)^n+3)/24. - Bruno Berselli, May 26 2013
E.g.f.: (1/24)*( (3 - 6*x + 6*x^2 + 100*x^3 + 130*x^4 + 44*x^5 + 4*x^6)*exp(x) - 3*exp(-x) ). - G. C. Greubel, Apr 16 2022

A172134 Number of ways to place 3 nonattacking knights on an n X n board.

Original entry on oeis.org

0, 4, 36, 276, 1360, 4752, 13340, 32084, 68796, 135040, 247152, 427380, 705144, 1118416, 1715220, 2555252, 3711620, 5272704, 7344136, 10050900, 13539552, 17980560, 23570764, 30535956, 39133580, 49655552, 62431200, 77830324

Offset: 1

Vaclav Kotesovec, Jan 26 2010

E. Bonsdorff, K. Fabel, O. Riihimaa, Schach und Zahl, 1966, p. 51-63

Vincenzo Librandi, Table of n, a(n) for n = 1..1000
Vaclav Kotesovec, Number of ways of placing non-attacking queens and kings on boards of various sizes
Index entries for linear recurrences with constant coefficients, signature (7,-21,35,-35,21,-7,1).

Cf. A047659, A172124, A172132.

Column k=3 of A244081.

[n le 3 select (n*(n-1))^2 else (n-2)*(n+5)*(n^4 -3*n^3 -8*n^2 +66*n -108)/6: n in [1..50]]; // G. C. Greubel, Apr 18 2022

CoefficientList[Series[4x(3x^8 -20x^7 +43x^6 -38x^5 +23x^4 -11x^3 -27x^2 -2x -1)/ (x-1)^7, {x, 0, 40}], x] (* Vincenzo Librandi, May 02 2013 *)

def A172134(n):
    if (n<4): return (n*(n-1))^2
    else: return (n-2)*(n+5)*(n^4 -3*n^3 -8*n^2 +66*n -108)/6
[A172134(n) for n in (1..50)] # G. C. Greubel, Apr 18 2022

Explicit formula (Karl Fabel, 1966): a(n) = (n - 2)*(n + 5)*(n^4 - 3*n^3 - 8*n^2 + 66*n - 108)/6, for n >= 4.
G.f.: 4*x^2*(3*x^8-20*x^7+43*x^6-38*x^5+23*x^4-11*x^3-27*x^2-2*x-1)/(x-1)^7. - Vaclav Kotesovec, Mar 25 2010
From G. C. Greubel, Apr 18 2022: (Start)
a(n) = 7*a(n-1) -21*a(n-2) +35*a(n-3) -35*a(n-4) +21*a(n-5) -7*a(n-6) +a(n-7), for n >= 11.
E.g.f.: (1/6)*(-1080 - 312*x + 12*x^2 +13*x^3 + (1080 - 768*x + 228*x^2 + 38*x^4 + 15*x^5 + x^6)*exp(x)). (End)

A172226 Number of ways to place 3 nonattacking wazirs on an n X n board.

Original entry on oeis.org

0, 0, 22, 276, 1474, 5248, 14690, 35012, 74326, 144544, 262398, 450580, 739002, 1166176, 1780714, 2642948, 3826670, 5420992, 7532326, 10286484, 13830898, 18336960, 24002482, 31054276, 39750854, 50385248, 63287950

Offset: 1

Vaclav Kotesovec, Jan 29 2010

A wazir is a (fairy chess) leaper [0,1].

Vincenzo Librandi, Table of n, a(n) for n = 1..1000
V. Kotesovec, Number of ways of placing non-attacking queens and kings on boards of various sizes
Eric Weisstein's World of Mathematics, Grid Graph
Wikipedia, Wazir (chess)
Index entries for linear recurrences with constant coefficients, signature (7,-21,35,-35,21,-7,1).

Cf. A172225, A047659, A061996, A172124, A172134, A172138.

I:=[0, 0, 22, 276, 1474, 5248, 14690, 35012]; [n le 8 select I[n] else 7*Self(n-1)-21*Self(n-2)+35*Self(n-3)-35*Self(n-4)+21*Self(n-5)-7*Self(n-6)+Self(n-7): n in [1..40]]; // Vincenzo Librandi, Apr 30 2013

[0] cat [(n-2)*(n^5+2*n^4-11*n^3-10*n^2+42*n-12)/6: n in [2..30]]; // Vincenzo Librandi, Apr 30 2013

A172226:=n->`if`(n=1, 0, (n-2)*(n^5 + 2*n^4 - 11*n^3 - 10*n^2 + 42*n - 12)/6); seq(A172226(n), n=1..60); # Wesley Ivan Hurt, Feb 06 2014

CoefficientList[Series[2 x^2 (x^5 - 9 x^4 + 22 x^3 - 2  x^2 - 61 x - 11) / (x-1)^7, {x, 0, 60}], x] (* Vincenzo Librandi, Apr 30 2013 *)
LinearRecurrence[{7,-21,35,-35,21,-7,1},{0,0,22,276,1474,5248,14690,35012},30] (* Harvey P. Dale, Apr 08 2022 *)

a(n) = (n-2)*(n^5 + 2*n^4 - 11*n^3 - 10*n^2 + 42*n - 12)/6, n>=2.
G.f.: 2*x^3*(x^5-9*x^4+22*x^3-2*x^2-61*x-11)/(x-1)^7. - Vaclav Kotesovec, Mar 25 2010
a(n) = 7*a(n-1)-21*a(n-2)+35*a(n-3)-35*a(n-4)+21*a(n-5)-7*a(n-6)+a(n-7). - Vincenzo Librandi, Apr 30 2013
a(n) = A232833(n,3). - R. J. Mathar, Apr 11 2024

cp's OEIS Frontend

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A108792 Number of ways to place 5 nonattacking queens on an n X n board.

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A002624 Expansion of (1-x)^(-3) * (1-x^2)^(-2).

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A172124 Number of ways to place 3 nonattacking bishops on an n X n board.

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A172134 Number of ways to place 3 nonattacking knights on an n X n board.

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