cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 89 results. Next

A140393 Erroneous duplicate of A000170, see comments.

Original entry on oeis.org

1, 0, 0, 2, 10, 4, 40, 92, 352, 724, 2680, 14200, 73712, 365596, 2279184, 14772512, 95815104, 666090624, 4968057848, 39029188884, 314666222712, 2691008701644, 24233937684440, 226732487925864
Offset: 1

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Author

N. J. A. Sloane, Jun 18 2008

Keywords

Comments

This is a new calculation of A000170 which produced a different answer for n=24. I do not know which version is correct and I have therefore created this second entry for the values found by the NQueens(AT)home team. See the main entry for this sequence, A000170, for many further references and comments.
As discovered on Nov 07 2008, this sequence is likely to suffer from an overflow error in the implementation of the NQueens(AT)Home project. The results differ by 781684047872 = 0xb600000000 = 182 * 2^32.

Crossrefs

See A000170 for further information.

Extensions

a(24) is probably mistaken. - Thomas B. Preußer, Nov 07 2008

A038754 a(2n) = 3^n, a(2n+1) = 2*3^n.

Original entry on oeis.org

1, 2, 3, 6, 9, 18, 27, 54, 81, 162, 243, 486, 729, 1458, 2187, 4374, 6561, 13122, 19683, 39366, 59049, 118098, 177147, 354294, 531441, 1062882, 1594323, 3188646, 4782969, 9565938, 14348907, 28697814, 43046721, 86093442, 129140163, 258280326, 387420489
Offset: 0

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Author

Henry Bottomley, May 03 2000

Keywords

Comments

In general, for the recurrence a(n) = a(n-1)*a(n-2)/a(n-3), all terms are integers iff a(0) divides a(2) and first three terms are positive integers, since a(2n+k) = a(k)*(a(2)/a(0))^n for all nonnegative integers n and k.
Equals eigensequence of triangle A070909; (1, 1, 2, 3, 6, 9, 18, ...) shifts to the left with multiplication by triangle A070909. - Gary W. Adamson, May 15 2010
The a(n) represent all paths of length (n+1), n >= 0, starting at the initial node on the path graph P_5, see the second Maple program. - Johannes W. Meijer, May 29 2010
a(n) is the difference between numbers of multiple of 3 evil (A001969) and odious (A000069) numbers in interval [0, 2^(n+1)). - Vladimir Shevelev, May 16 2012
A "half-geometric progression": to obtain a term (beginning with the third one) we multiply the before previous one by 3. - Vladimir Shevelev, May 21 2012
Pisano periods: 1, 2, 1, 4, 8, 2, 12, 4, 1, 8, 10, 4, 6, 12, 8, 8, 32, 2, 36, 8, ... . - R. J. Mathar, Aug 10 2012
Numbers k such that the k-th cyclotomic polynomial has a root mod 3. - Eric M. Schmidt, Jul 31 2013
Range of row n of the circular Pascal array of order 6. - Shaun V. Ault, Jun 05 2014
Also, the number of walks of length n on the graph 0--1--2--3--4 starting at vertex 1. - Sean A. Irvine, Jun 03 2025

Examples

			In the interval [0,2^5) we have 11 multiples of 3 numbers, from which 10 are evil and only one (21) is odious. Thus a(4) = 10 - 1 = 9. - _Vladimir Shevelev_, May 16 2012
		

Crossrefs

Programs

  • Haskell
    import Data.List (transpose)
    a038754 n = a038754_list !! n
    a038754_list = concat $ transpose [a000244_list, a008776_list]
    -- Reinhard Zumkeller, Oct 19 2015
    
  • Magma
    [n le 2 select n else 3*Self(n-2): n in [1..40]]; // Vincenzo Librandi, Aug 18 2016
    
  • Maple
    a[0]:=0:a[1]:=1:for n from 2 to 50 do a[n]:=3*a[n-2]+2 od: seq(a[n]+1, n=0..34); # Zerinvary Lajos, Mar 20 2008
    with(GraphTheory): P:=5: G:=PathGraph(P): A:= AdjacencyMatrix(G): nmax:=35; for n from 1 to nmax do B(n):=A^n; a(n):=add(B(n)[1,k],k=1..P) od: seq(a(n),n=1..nmax); # Johannes W. Meijer, May 29 2010
  • Mathematica
    LinearRecurrence[{0,3},{1,2},40] (* Harvey P. Dale, Jan 26 2014 *)
    CoefficientList[Series[(1+2x)/(1-3x^2), {x, 0, 40}], x] (* Vincenzo Librandi, Aug 18 2016 *)
    Module[{nn=20,c},c=3^Range[0,nn];Riffle[c,2c]] (* Harvey P. Dale, Aug 21 2021 *)
  • PARI
    a(n)=(1/6)*(5-(-1)^n)*3^floor(n/2)
    
  • PARI
    a(n)=3^(n>>1)<
    				
  • SageMath
    [2^(n%2)*3^((n-(n%2))/2) for n in range(61)] # G. C. Greubel, Oct 10 2022

Formula

a(n) = a(n-1)*a(n-2)/a(n-3) with a(0)=1, a(1)=2, a(2)=3.
a(2*n) = (3/2)*a(2*n-1) = 3^n, a(2*n+1) = 2*a(2*n) = 2*3^n.
From Benoit Cloitre, Apr 27 2003: (Start)
a(1)=1, a(n)= 2*a(n-1) if a(n-1) is odd, or a(n)= (3/2)*a(n-1) if a(n-1) is even.
a(n) = (1/6)*(5-(-1)^n)*3^floor(n/2).
a(2*n) = a(2*n-1) + a(2*n-2) + a(2*n-3).
a(2*n+1) = a(2*n) + a(2*n-1). (End)
G.f.: (1+2*x)/(1-3*x^2). - Paul Barry, Aug 25 2003
From Reinhard Zumkeller, Sep 11 2003: (Start)
a(n) = (1 + n mod 2) * 3^floor(n/2).
a(n) = A087503(n) - A087503(n-1). (End)
a(n) = sqrt(3)*(2+sqrt(3))*(sqrt(3))^n/6 - sqrt(3)*(2-sqrt(3))*(-sqrt(3))^n/6. - Paul Barry, Sep 16 2003
From Reinhard Zumkeller, May 26 2008: (Start)
a(n) = A140740(n+2,2).
a(n+1) = a(n) + a(n - n mod 2). (End)
If p(i) = Fibonacci(i-3) and if A is the Hessenberg matrix of order n defined by A(i,j) = p(j-i+1), (i<=j), A(i,j)=-1, (i=j+1), and A(i,j)=0 otherwise. Then, for n>=1, a(n-1) = (-1)^n det A. - Milan Janjic, May 08 2010
a(n) = A182751(n) for n >= 2. - Jaroslav Krizek, Nov 27 2010
a(n) = Sum_{i=0..2^(n+1), i==0 (mod 3)} (-1)^A000120(i). - Vladimir Shevelev, May 16 2012
a(0)=1, a(1)=2, for n>=3, a(n)=3*a(n-2). - Vladimir Shevelev, May 21 2012
Sum_(n>=0) 1/a(n) = 9/4. - Alexander R. Povolotsky, Aug 24 2012
a(n) = sqrt(3*a(n-1)^2 + (-3)^(n-1)). - Richard R. Forberg, Sep 04 2013
a(n) = 2^((1-(-1)^n)/2)*3^((2*n-1+(-1)^n)/4). - Luce ETIENNE, Aug 11 2014
From Reinhard Zumkeller, Oct 19 2015: (Start)
a(2*n) = A000244(n), a(2*n+1) = A008776(n).
For n > 0: a(n+1) = a(n) + if a(n) odd then min{a(n), a(n-1)} else max{a(n), a(n-1)}, see also A128588. (End)
E.g.f.: (7*cosh(sqrt(3)*x) + 4*sqrt(3)*sinh(sqrt(3)*x) - 4)/3. - Stefano Spezia, Feb 17 2022
Sum_{n>=0} (-1)^n/a(n) = 3/4. - Amiram Eldar, Dec 02 2022

A000315 Number of reduced Latin squares of order n; also number of labeled loops (quasigroups with an identity element) with a fixed identity element.

Original entry on oeis.org

1, 1, 1, 4, 56, 9408, 16942080, 535281401856, 377597570964258816, 7580721483160132811489280, 5363937773277371298119673540771840
Offset: 1

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Author

Keywords

Comments

A reduced Latin square of order n is an n X n matrix where each row and column is a permutation of 1..n and the first row and column are 1..n in increasing order. - Michael Somos, Mar 12 2011
The Stones-Wanless (2010) paper shows among other things that a(n) is 0 mod n if n is composite and 1 mod n if n is prime.

References

  • L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 183.
  • J. Denes, A. D. Keedwell, editors, Latin Squares: new developments in the theory and applications, Elsevier, 1991, pp. 1, 388.
  • R. A. Fisher and F. Yates, Statistical Tables for Biological, Agricultural and Medical Research. 6th ed., Hafner, NY, 1963, p. 22.
  • C. R. Rao, S. K. Mitra and A. Matthai, editors, Formulae and Tables for Statistical Work. Statistical Publishing Society, Calcutta, India, 1966, p. 193.
  • J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 210.
  • H. J. Ryser, Combinatorial Mathematics. Mathematical Association of America, Carus Mathematical Monograph 14, 1963, pp. 37, 53.
  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
  • M. B. Wells, Elements of Combinatorial Computing. Pergamon, Oxford, 1971, p. 240.

Crossrefs

Formula

a(n) = A002860(n) / (n! * (n-1)!) = A000479(n) / (n-1)!.

Extensions

Added June 1995: the 10th term was probably first computed by Eric Rogoyski
a(11) (from the McKay-Wanless article) from Richard Bean, Feb 17 2004

A051223 Number of ways of placing n nonattacking superqueens on an n X n board.

Original entry on oeis.org

1, 0, 0, 0, 0, 0, 0, 0, 0, 4, 44, 156, 1876, 5180, 32516, 202900, 1330622, 8924976, 64492432, 495864256, 3977841852, 34092182276, 306819842212, 2883202816808, 28144109776812, 286022102245804
Offset: 1

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Author

Ulrich Schimke (ulrschimke(AT)aol.com)

Keywords

Comments

A superqueen moves like a queen and a knight.
A linear-time algorithm giving an explicit solution for any n >= 10 for the n-super-queens-problem can be found at the link. Included is an online solver, implemented in JavaScript. - Frank Schwellinger (nummer_eins(AT)web.de), Mar 19 2004. [But see the next comment - N. J. A. Sloane, Jul 01 2021]
Escamocher and O'Sullivan (2021) claim Schwellinger's algorithm is incorrect, and that their own algorithm is the first published linear-time algorithm. - N. J. A. Sloane, Jul 01 2021

Crossrefs

Extensions

a(20) from Bill link added Jul 25 2006
a(21)-a(23) from R. Oprisch's website added by Max Alekseyev, Sep 29 2006
a(24)-a(26) from W. Schubert, Jul 31 2009, Nov 29 2009, Jan 18 2011

A002562 Number of ways of placing n nonattacking queens on n X n board (symmetric solutions count only once).

Original entry on oeis.org

1, 0, 0, 1, 2, 1, 6, 12, 46, 92, 341, 1787, 9233, 45752, 285053, 1846955, 11977939, 83263591, 621012754, 4878666808, 39333324973, 336376244042, 3029242658210, 28439272956934, 275986683743434, 2789712466510289, 29363495934315694
Offset: 1

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Author

Keywords

Examples

			a(4) = 1:
  +---------+
  | . . Q . |
  | Q . . . |
  | . . . Q |
  | . Q . . |
  +---------+
a(5) = 2:
  +-----------+ +-----------+
  | . . . Q . | | . . . Q . |
  | . Q . . . | | Q . . . . |
  | . . . . Q | | . . Q . . |
  | . . Q . . | | . . . . Q |
  | Q . . . . | | . Q . . . |
  +-----------+ +-----------+
a(6) = 1:
  +-------------+
  | . . . . Q . |
  | . . Q . . . |
  | Q . . . . . |
  | . . . . . Q |
  | . . . Q . . |
  | . Q . . . . | - _Hugo Pfoertner_, Mar 17 2019
  +-------------+
a(7) = 6:
  +---------------+  +---------------+  +---------------+
  | Q . . . . . . |  | Q . . . . . . |  | . Q . . . . . |
  | . . Q . . . . |  | . . . Q . . . |  | . . . Q . . . |
  | . . . . Q . . |  | . . . . . . Q |  | Q . . . . . . |
  | . . . . . . Q |  | . . Q . . . . |  | . . . . . . Q |
  | . Q . . . . . |  | . . . . . Q . |  | . . . . Q . . |
  | . . . Q . . . |  | . Q . . . . . |  | . . Q . . . . |
  | . . . . . Q . |  | . . . . Q . . |  | . . . . . Q . |
  +---------------+  +---------------+  +---------------+
.
  +---------------+  +---------------+  +---------------+
  | . Q . . . . . |  | . Q . . . . . |  | . Q . . . . . |
  | . . . . Q . . |  | . . . . Q . . |  | . . . . . Q . |
  | Q . . . . . . |  | . . . . . . Q |  | . . Q . . . . |
  | . . . Q . . . |  | . . . Q . . . |  | . . . . . . Q |
  | . . . . . . Q |  | Q . . . . . . |  | . . . Q . . . |
  | . . Q . . . . |  | . . Q . . . . |  | Q . . . . . . |
  | . . . . . Q . |  | . . . . . Q . |  | . . . . Q . . |
  +---------------+  +---------------+  +---------------+
- _Hugo Pfoertner_, Mar 18 2019
		

References

  • Martin Gardner, Fractal Music, Hypercards and More, Freeman, NY, 1991, p. 231-233.
  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
  • M. B. Wells, Elements of Combinatorial Computing. Pergamon, Oxford, 1971, p. 238.

Crossrefs

Formula

a(n) = (1/8) * (Q(n) + P(n) + 2 * R(n)), where Q(n) = A000170(n) [all solutions], P(n) = A032522(n) [point symmetric solutions] and R(n) = A033148(n) [rotationally symmetric solutions].

Extensions

a(17) and a(18) found by Ulrich Schimke in Goettingen, Germany (UlrSchimke(AT)aol.com)
Formula and a(19) to a(23) added by Matthias Engelhardt in Nuremberg, Germany, Jan 23 2000
Terms (calculated from formula) added by Thomas B. Preußer, Dec 15 2008
a(26) (derived from formula after recent extension of A000170) added by Thomas B. Preußer, Jul 12 2009
a(27) (derived from formula after recent extension of A000170) added by Thomas B. Preußer, Sep 23 2016

A000136 Number of ways of folding a strip of n labeled stamps.

Original entry on oeis.org

1, 2, 6, 16, 50, 144, 462, 1392, 4536, 14060, 46310, 146376, 485914, 1557892, 5202690, 16861984, 56579196, 184940388, 622945970, 2050228360, 6927964218, 22930109884, 77692142980, 258360586368, 877395996200, 2929432171328, 9968202968958, 33396290888520, 113837957337750
Offset: 1

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Author

Keywords

References

  • N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
  • M. B. Wells, Elements of Combinatorial Computing. Pergamon, Oxford, 1971, p. 238.

Crossrefs

Formula

a(n) = 2*n * A000560(n-1) for n >= 3.
a(n) = n * A000682(n). - Andrew Howroyd, Dec 06 2015

A274650 Triangle read by rows: T(n,k), (0 <= k <= n), in which each term is the least nonnegative integer such that no row, column, diagonal, or antidiagonal contains a repeated term.

Original entry on oeis.org

0, 1, 2, 3, 0, 1, 2, 4, 3, 5, 5, 1, 0, 2, 3, 4, 3, 5, 1, 6, 7, 6, 7, 2, 0, 5, 4, 8, 8, 5, 9, 4, 7, 2, 10, 6, 7, 10, 8, 3, 0, 6, 9, 5, 4, 11, 6, 12, 7, 1, 8, 3, 10, 9, 13, 9, 8, 4, 11, 2, 0, 1, 12, 6, 7, 10, 10, 11, 7, 12, 4, 3, 2, 9, 8, 14, 13, 15, 12, 9, 10, 6, 8, 1, 0, 11, 7, 4, 16, 14, 17
Offset: 0

Views

Author

Omar E. Pol, Jul 02 2016

Keywords

Comments

Similar to A274528, but the triangle here is a right triangle.
The same rule applied to an equilateral triangle gives A274528.
By analogy, the offset for both rows and columns is the same as the offset of A274528.
We construct the triangle by reading from left to right in each row, starting with T(0,0) = 0.
Presumably every diagonal and every column is also a permutation of the nonnegative integers, but the proof does not seem so straightforward. Of course neither the rows nor the antidiagonals are permutations of the nonnegative integers, since they are finite in length.
Omar E. Pol's conjecture that every column and every diagonal of the triangle is a permutation of the nonnegative integers is true: see the link. - N. J. A. Sloane, Jun 07 2017
It appears that the numbers generally appear for the first time in or near the right border of the triangle.
Theorem 1: the middle diagonal gives A000004 (the zero sequence).
Proof: T(0,0) = 0 by definition. For the next rows we have that in row 1 there are no zeros because the first term belongs to a column that contains a zero and the second term belongs to a diagonal that contains a zero. In row 2 the unique zero is T(2,1) = 0 because the preceding term belongs to a column that contains a zero and the following term belongs to a diagonal that contains a zero. Then we have two recurrences for all rows of the triangle:
a) If T(n,k) = 0 then row n+1 does not contain a zero because every term belongs to a column that contains a zero or it belongs to a diagonal that contains a zero.
b) If T(n,k) = 0 the next zero is T(n+2,k+1) because every preceding term in row n+2 is a positive integer because it belongs to a column that contains a zero and, on the other hand, the column, the diagonal and the antidiagonal of T(n+2,k+1) do not contain zeros.
Finally, since both T(n,k) = 0 and T(n+2,k+1) = 0 are located in the middle diagonal, the other terms of the middle diagonal are zeros, or in other words: the middle diagonal gives A000004 (the zero sequence). QED
Theorem 2: all zeros are in the middle diagonal.
Proof: consider the first n rows of the triangle. Every element located above or at the right-hand side of the middle diagonal must be positive because it belongs to a diagonal that contains one of the zeros of the middle diagonal. On the other hand every element located below the middle diagonal must be positive because it belongs to a column that contains one of the zeros of the middle diagonal, hence there are no zeros outside of the middle diagonal, or in other words: all zeros are in the middle diagonal. QED
From Hartmut F. W. Hoft, Jun 12 2017: (Start)
T(2k,k) = 0, for all k >= 0, and T(n,{(n-1)/2,(n+2)/2,(n-2)/2,(n+1)/2}) = 1, for all n >= 0 with n mod 8 = {1,2,4,5} respectively, and no 0's or 1's occur in other positions. The triangle of positions of 0's and 1's for this sequence is the triangle in the Comment section of A274651 with row and column indices and values shifted down by one.
The sequence of rows containing 1's is A047613 (n mod 8 = {1,2,4,5}), those containing only 1's is A016813 (n mod 8 = {1,5}), those containing both 0's and 1's is A047463 (n mod 8 = {2,4}), those containing only 0's is A047451 (n mod 8 = {0,6}), and those containing neither 0's nor 2's is A004767 (n mod 8 = {3,7}).
(End)

Examples

			Triangle begins:
   0;
   1,  2;
   3,  0,  1;
   2,  4,  3,  5;
   5,  1,  0,  2,  3;
   4,  3,  5,  1,  6,  7;
   6,  7,  2,  0,  5,  4,  8;
   8,  5,  9,  4,  7,  2, 10,  6;
   7, 10,  8,  3,  0,  6,  9,  5,  4;
  11,  6, 12,  7,  1,  8,  3, 10,  9, 13;
   9,  8,  4, 11,  2,  0,  1, 12,  6,  7, 10;
  10, 11,  7, 12,  4,  3,  2,  9,  8, 14, 13, 15;
  12,  9, 10,  6,  8,  1,  0, 11,  7,  4, 16, 14, 17;
  ...
From _Omar E. Pol_, Jun 07 2017: (Start)
The triangle may be reformatted as an isosceles triangle so that the zero sequence (A000004) appears in the central column (but note that this is NOT the way the triangle is constructed!):
.
.                    0;
.                  1,  2;
.                3,  0,  1;
.              2,  4,  3,  5;
.            5,  1,  0,  2,  3;
.          4,  3,  5,  1,  6,  7;
.        6,  7,  2,  0,  5,  4,  8;
.     8,   5,  9,  4,  7,  2, 10,  6;
.   7,  10,  8,  3,  0,  6,  9,  5,  4;
...
(End)
		

Crossrefs

Cf. A000004 (middle diagonal).
Cf. A046092 (indices of the zeros).
Every diagonal and every column of the right triangle is a permutation of A001477.
The left and right edges of the right triangle give A286294 and A286295.
Cf. A274651 is the same triangle but with 1 added to every entry.
Other sequences of the same family are A269526, A274528, A274820, A274821, A286297, A288530, A288531.
Sequences mentioned in N. J. A. Sloane's proof are A000170, A274616 and A287864.
Cf. A288384.
See A308179, A308180 for a very similar triangle.

Programs

  • Mathematica
    (* function a274651[] is defined in A274651 *)
    (* computation of rows 0 ... n-1 *)
    a274650[n_] := a274651[n]-1
    Flatten[a274650[13]] (* data *)
    TableForm[a274650[13]] (* triangle *)
    (* Hartmut F. W. Hoft, Jun 12 2017 *)
  • PARI
    See Links section.

Formula

T(n,k) = A274651(n+1,k+1) - 1.

A333706 Number T(n,k) of permutations p of [n] such that |p(i+k) - p(i)| <> k for i in [n-k]; triangle T(n,k), n>=0, 0<=k<=n, read by rows.

Original entry on oeis.org

1, 0, 1, 0, 0, 2, 0, 0, 4, 6, 0, 2, 16, 20, 24, 0, 14, 44, 80, 108, 120, 0, 90, 200, 384, 544, 672, 720, 0, 646, 1288, 2240, 3264, 4128, 4800, 5040, 0, 5242, 9512, 15424, 23040, 28992, 34752, 38880, 40320, 0, 47622, 78652, 123456, 176832, 231936, 280512, 323520, 352800, 362880
Offset: 0

Views

Author

Alois P. Heinz, Apr 02 2020

Keywords

Comments

T(n,k) is defined for n,k >= 0. The triangle contains only the terms with k<=n. T(n,k) = n! for k>=n.

Examples

			Triangle T(n,k) begins:
  1;
  0,    1;
  0,    0,    2;
  0,    0,    4,     6;
  0,    2,   16,    20,    24;
  0,   14,   44,    80,   108,   120;
  0,   90,  200,   384,   544,   672,   720;
  0,  646, 1288,  2240,  3264,  4128,  4800,  5040;
  0, 5242, 9512, 15424, 23040, 28992, 34752, 38880, 40320;
  ...
		

Crossrefs

Columns k=0-10 (for n>=k) give: A000007, A002464, A110128, A117574, A189255, A189256, A189271, A360384, A360386, A360462, A360463.
Main diagonal gives A000142.
T(2n,n) gives A189849.
T(n+1,n) gives 4*A138772(n).
T(n+2,n) gives 16*A333804(n).
Cf. A000170 (condition is satisfied for all k), A248686 (p(i) at distance k are sorted).

A003090 Number of species (or "main classes" or "paratopy classes") of Latin squares of order n.

Original entry on oeis.org

1, 1, 1, 2, 2, 12, 147, 283657, 19270853541, 34817397894749939, 2036029552582883134196099
Offset: 1

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Author

Keywords

References

  • F. Harary and E. M. Palmer, Graphical Enumeration, Academic Press, NY, 1973, p. 231.
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Extensions

a(9)-a(10) (from the McKay-Meynert-Myrvold article) from Richard Bean, Feb 17 2004
a(11) from Petteri Kaski (petteri.kaski(AT)cs.helsinki.fi), Sep 18 2009

A137774 Number of ways to place n nonattacking empresses on an n X n board.

Original entry on oeis.org

1, 2, 2, 8, 20, 94, 438, 2766, 19480, 163058, 1546726, 16598282, 197708058, 2586423174, 36769177348, 563504645310, 9248221393974, 161670971937362, 2996936692836754, 58689061747521430, 1210222434323163704, 26204614054454840842, 594313769819021397534, 14086979362268860896282
Offset: 1

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Author

Vaclav Kotesovec, Jan 27 2011

Keywords

Comments

An empress moves like a rook and a knight.

Crossrefs

Formula

Asymptotics (Vaclav Kotesovec, Jan 26 2011): a(n)/n! -> 1/e^4.
General asymptotic formulas for number of ways to place n nonattacking pieces rook + leaper[r,s] on an n X n board:
a(n)/n! -> 1/e^2 for 0
a(n)/n! -> 1/e^4 for 0

Extensions

Terms a(16)-a(17) from Vaclav Kotesovec, Feb 06 2011
Terms a(18)-a(19) from Wolfram Schubert, Jul 24 2011
Terms a(20)-a(24) (computed by Wolfram Schubert), Vaclav Kotesovec, Aug 25 2012
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