cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Previous Showing 31-40 of 103 results. Next

A046101 Biquadrateful numbers.

Original entry on oeis.org

16, 32, 48, 64, 80, 81, 96, 112, 128, 144, 160, 162, 176, 192, 208, 224, 240, 243, 256, 272, 288, 304, 320, 324, 336, 352, 368, 384, 400, 405, 416, 432, 448, 464, 480, 486, 496, 512, 528, 544, 560, 567, 576, 592, 608, 624, 625, 640, 648, 656, 672, 688, 704
Offset: 1

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Author

Keywords

Comments

The convention in the OEIS is that squareful, cubeful (A046099), biquadrateful, ... mean the same as "not squarefree" etc., while 2- or square-full, 3- or cube-full (A036966), 4-full (A036967) are used for Golomb's notion of powerful numbers (A001694, see references there), when each prime factor occurs to a power > 1. - M. F. Hasler, Feb 12 2008
Also solutions to equation tau_{-3}(n)=0, where tau_{-3} is A007428. - Enrique Pérez Herrero, Jan 19 2013
Sum_{n>0} 1/a(n)^s = Zeta(s) - Zeta(s)/Zeta(4s). - Enrique Pérez Herrero, Jan 21 2013
A051903(a(n)) > 3. - Reinhard Zumkeller, Sep 03 2015
The asymptotic density of this sequence is 1 - 1/zeta(4) = 1 - 90/Pi^4 = 0.076061... - Amiram Eldar, Jul 09 2020

Crossrefs

Programs

  • Haskell
    a046101 n = a046101_list !! (n-1)
    a046101_list = filter ((> 3) . a051903) [1..]
    -- Reinhard Zumkeller, Sep 03 2015
    
  • Maple
    with(NumberTheory):
    isBiquadrateful := n -> is(denom(Radical(n) / LargestNthPower(n, 2)) <> 1):
    select(isBiquadrateful, [`$`(1..704)]);  # Peter Luschny, Jul 12 2022
  • Mathematica
    lst={};Do[a=0;Do[If[FactorInteger[m][[n, 2]]>3, a=1], {n, Length[FactorInteger[m]]}];If[a==1, AppendTo[lst, m]], {m, 10^3}];lst (* Vladimir Joseph Stephan Orlovsky, Aug 15 2008 *)
    Select[Range[1000],Max[Transpose[FactorInteger[#]][[2]]]>3&] (* Harvey P. Dale, May 25 2014 *)
  • PARI
    is(n)=n>9 && vecmax(factor(n)[,2])>3 \\ Charles R Greathouse IV, Sep 03 2015
    
  • Python
    from sympy import mobius, integer_nthroot
    def A046101(n):
        def f(x): return n+sum(mobius(k)*(x//k**4) for k in range(1, integer_nthroot(x,4)[0]+1))
        m, k = n, f(n)
        while m != k:
            m, k = k, f(k)
        return m # Chai Wah Wu, Aug 05 2024

A036967 4-full numbers: if a prime p divides k then so does p^4.

Original entry on oeis.org

1, 16, 32, 64, 81, 128, 243, 256, 512, 625, 729, 1024, 1296, 2048, 2187, 2401, 2592, 3125, 3888, 4096, 5184, 6561, 7776, 8192, 10000, 10368, 11664, 14641, 15552, 15625, 16384, 16807, 19683, 20000, 20736, 23328, 28561, 31104, 32768, 34992
Offset: 1

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Author

Keywords

Comments

a(m) mod prime(n) > 0 for m < A258601(n); a(A258601(n)) = A030514(n) = prime(n)^4. - Reinhard Zumkeller, Jun 06 2015

References

  • E. Kraetzel, Lattice Points, Kluwer, Chap. 7, p. 276.

Crossrefs

A030514 is a subsequence.

Programs

  • Haskell
    import Data.Set (singleton, deleteFindMin, fromList, union)
    a036967 n = a036967_list !! (n-1)
    a036967_list = 1 : f (singleton z) [1, z] zs where
       f s q4s p4s'@(p4:p4s)
         | m < p4 = m : f (union (fromList $ map (* m) ps) s') q4s p4s'
         | otherwise = f (union (fromList $ map (* p4) q4s) s) (p4:q4s) p4s
         where ps = a027748_row m
               (m, s') = deleteFindMin s
       (z:zs) = a030514_list
    -- Reinhard Zumkeller, Jun 03 2015
    
  • Mathematica
    Join[{1},Select[Range[35000],Min[Transpose[FactorInteger[#]][[2]]]>3&]] (* Harvey P. Dale, Jun 05 2012 *)
  • PARI
    is(n)=n==1 || vecmin(factor(n)[,2])>3 \\ Charles R Greathouse IV, Sep 17 2015
    
  • PARI
    M(v,u,lim)=vecsort(concat(vector(#v, i, my(m=lim\v[i]); v[i]*select(t->t<=m, u))))
    Gen(lim,k)={my(v=[1]); forprime(p=2, sqrtnint(lim, k), v=M(v, concat([1], vector(logint(lim,p)-k+1,e,p^(e+k-1))), lim));v}
    Gen(35000,4) \\ Andrew Howroyd, Sep 10 2024
    
  • Python
    from sympy import factorint
    A036967_list = [n for n in range(1,10**5) if min(factorint(n).values(),default=4) >= 4] # Chai Wah Wu, Aug 18 2021
    
  • Python
    from math import gcd
    from sympy import integer_nthroot, factorint
    def A036967(n):
        def bisection(f,kmin=0,kmax=1):
            while f(kmax) > kmax: kmax <<= 1
            while kmax-kmin > 1:
                kmid = kmax+kmin>>1
                if f(kmid) <= kmid:
                    kmax = kmid
                else:
                    kmin = kmid
            return kmax
        def f(x):
            c = n+x
            for u in range(1,integer_nthroot(x,7)[0]+1):
                if all(d<=1 for d in factorint(u).values()):
                    for w in range(1,integer_nthroot(a:=x//u**7,6)[0]+1):
                        if gcd(w,u)==1 and all(d<=1 for d in factorint(w).values()):
                            for y in range(1,integer_nthroot(z:=a//w**6,5)[0]+1):
                                if gcd(w,y)==1 and gcd(u,y)==1 and all(d<=1 for d in factorint(y).values()):
                                    c -= integer_nthroot(z//y**5,4)[0]
            return c
        return bisection(f,n,n) # Chai Wah Wu, Sep 10 2024

Formula

Sum_{n>=1} 1/a(n) = Product_{p prime} (1 + 1/(p^3*(p-1))) = 1.1488462139214317030108176090790939019972506733993367867997411290952527... - Amiram Eldar, Jul 09 2020

Extensions

More terms from Erich Friedman
Corrected by Vladeta Jovovic, Aug 17 2002

A062838 Cubes of squarefree numbers.

Original entry on oeis.org

1, 8, 27, 125, 216, 343, 1000, 1331, 2197, 2744, 3375, 4913, 6859, 9261, 10648, 12167, 17576, 24389, 27000, 29791, 35937, 39304, 42875, 50653, 54872, 59319, 68921, 74088, 79507, 97336, 103823, 132651, 148877, 166375, 185193, 195112, 205379, 226981, 238328
Offset: 1

Views

Author

Jason Earls, Jul 21 2001

Keywords

Comments

Cubefull numbers (A036966) all of whose nonunitary divisors are not cubefull (A362147). - Amiram Eldar, May 13 2023

Crossrefs

Other powers of squarefree numbers: A005117(1), A062503(2), A113849(4), A072774(all).
A329332 column 3 in ascending order.

Programs

  • Mathematica
    Select[Range[70], SquareFreeQ]^3 (* Harvey P. Dale, Jul 20 2011 *)
  • PARI
    for(n=1,35, if(issquarefree(n),print(n*n^2)))
    
  • PARI
    a(n) = my(m, c); if(n<=1, n==1, c=1; m=1; while(cAltug Alkan, Dec 03 2015
    
  • Python
    from math import isqrt
    from sympy import mobius
    def A062838(n):
        def f(x): return n+x-sum(mobius(k)*(x//k**2) for k in range(1, isqrt(x)+1))
        m, k = n, f(n)
        while m != k: m, k = k, f(k)
        return m**3 # Chai Wah Wu, Sep 11 2024

Formula

A055229(a(n)) = A005117(n) and A055229(m) < A005117(n) for m < a(n). - Reinhard Zumkeller, Apr 09 2010
a(n) = A005117(n)^3. - R. J. Mathar, Dec 03 2015
{a(n)} = {A225546(A000400(n)) : n >= 0}, where {a(n)} denotes the set of integers in the sequence. - Peter Munn, Oct 31 2019
Sum_{n>=1} 1/a(n) = zeta(3)/zeta(6) = 945*zeta(3)/Pi^6 (A157289). - Amiram Eldar, May 22 2020

Extensions

More terms from Dean Hickerson, Jul 24 2001
More terms from Vladimir Joseph Stephan Orlovsky, Aug 15 2008

A262675 Exponentially evil numbers.

Original entry on oeis.org

1, 8, 27, 32, 64, 125, 216, 243, 343, 512, 729, 864, 1000, 1024, 1331, 1728, 1944, 2197, 2744, 3125, 3375, 4000, 4096, 4913, 5832, 6859, 7776, 8000, 9261, 10648, 10976, 12167, 13824, 15552, 15625, 16807, 17576, 19683, 21952, 23328, 24389, 25000, 27000, 27648, 29791
Offset: 1

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Author

Vladimir Shevelev, Sep 27 2015

Keywords

Comments

Or the numbers whose prime power factorization contains primes only in evil exponents (A001969): 0, 3, 5, 6, 9, 10, 12, ...
If n is in the sequence, then n^2 is also in the sequence.
A268385 maps each term of this sequence to a unique nonzero square (A000290), and vice versa. - Antti Karttunen, May 26 2016

Examples

			864 = 2^5*3^3; since 5 and 3 are evil numbers, 864 is in the sequence.
		

Crossrefs

Subsequence of A036966.
Apart from 1, a subsequence of A270421.
Indices of ones in A270418.
Sequence A270437 sorted into ascending order.

Programs

  • Haskell
    a262675 n = a262675_list !! (n-1)
    a262675_list = filter
       (all (== 1) . map (a010059 . fromIntegral) . a124010_row) [1..]
    -- Reinhard Zumkeller, Oct 25 2015
    
  • Mathematica
    {1}~Join~Select[Range@ 30000, AllTrue[Last /@ FactorInteger[#], EvenQ@ First@ DigitCount[#, 2] &] &] (* Michael De Vlieger, Sep 27 2015, Version 10 *)
    expEvilQ[n_] := n == 1 || AllTrue[FactorInteger[n][[;; , 2]], EvenQ[DigitCount[#, 2, 1]] &]; With[{max = 30000}, Select[Union[Flatten[Table[i^2*j^3, {j, Surd[max, 3]}, {i, Sqrt[max/j^3]}]]], expEvilQ]] (* Amiram Eldar, Dec 01 2023 *)
  • PARI
    isok(n) = {my(f = factor(n)); for (i=1, #f~, if (hammingweight(f[i,2]) % 2, return (0));); return (1);} \\ Michel Marcus, Sep 27 2015
    
  • Perl
    use ntheory ":all"; sub isok { my @f = factor_exp($[0]); return scalar(grep { !(hammingweight($->[1]) % 2) } @f) == @f; } # Dana Jacobsen, Oct 26 2015

Formula

Product_{k=1..A001221(n)} A010059(A124010(n,k)) = 1. - Reinhard Zumkeller, Oct 25 2015
Sum_{n>=1} 1/a(n) = Product_{p prime} (1 + Sum_{k>=2} 1/p^A001969(k)) = Product_{p prime} f(1/p) = 1.2413599378..., where f(x) = (1/(1-x) + Product_{k>=0} (1 - x^(2^k)))/2. - Amiram Eldar, May 18 2023, Dec 01 2023

Extensions

More terms from Michel Marcus, Sep 27 2015

A335988 Cubefull exponentially odd numbers: numbers whose prime factorization contains only odd exponents that are larger than 1.

Original entry on oeis.org

1, 8, 27, 32, 125, 128, 216, 243, 343, 512, 864, 1000, 1331, 1944, 2048, 2187, 2197, 2744, 3125, 3375, 3456, 4000, 4913, 6859, 7776, 8192, 9261, 10648, 10976, 12167, 13824, 16000, 16807, 17496, 17576, 19683, 24389, 25000, 27000, 29791, 30375, 31104, 32768, 35937
Offset: 1

Views

Author

Amiram Eldar, Jul 03 2020

Keywords

Comments

This sequence is a permutation of A355038.
This sequence is also a permutation of the exponentially odd numbers (A268335) multiplied by the square of their squarefree kernel (A007947).
a(n)/rad(a(n)) is a permutation of the squares.
a(n)/rad(a(n))^2 is a permutation of the exponentially odd numbers.

Examples

			8 = 2^3 is a term since the exponent of its prime factor 2 is 3 which is odd and larger than 1.
		

Crossrefs

Intersection of A001694 and A268335.
Intersection of A036966 and A268335.
A355038 in ascending order.
A030078, A050997, A092759, A179665, A079395 and A138031 are subsequences.

Programs

  • Mathematica
    Join[{1}, Select[Range[10^5], AllTrue[Last /@ FactorInteger[#], #1 > 1 && OddQ[#1] &] &]]
  • Python
    from math import isqrt, prod
    from sympy import factorint
    def afind(N): # all terms up to limit N
        cands = (n**2*prod(factorint(n**2)) for n in range(1, isqrt(N//2)+2))
        return sorted(c for c in cands if c <= N)
    print(afind(4*10**4)) # Michael S. Branicky, Jun 16 2022

Formula

Sum_{n>=1} 1/a(n) = Product_{p prime} (1 + 1/(p*(p^2-1))) = 1.2312911... (A065487).

A337050 Numbers without an exponent 2 in their prime factorization.

Original entry on oeis.org

1, 2, 3, 5, 6, 7, 8, 10, 11, 13, 14, 15, 16, 17, 19, 21, 22, 23, 24, 26, 27, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 46, 47, 48, 51, 53, 54, 55, 56, 57, 58, 59, 61, 62, 64, 65, 66, 67, 69, 70, 71, 73, 74, 77, 78, 79, 80, 81, 82, 83, 85, 86, 87
Offset: 1

Views

Author

Amiram Eldar, Aug 12 2020

Keywords

Comments

Numbers k such that the powerful part (A057521) of k is a cubefull number (A036966).
Numbers k such that A003557(k) = k/A007947(k) is a powerful number (A001694).
The asymptotic density of this sequence is Product_{primes p} (1 - 1/p^2 + 1/p^3) = 0.748535... (A330596).
A304364 is apparently a subsequence.
These numbers were named semi-2-free integers by Suryanarayana (1971). - Amiram Eldar, Dec 29 2020

Examples

			6 = 2^1 * 3^1 is a term since none of the exponents in its prime factorization is equal to 2.
9 = 3^2 is not a term since it has an exponent 2 in its prime factorization.
		

Crossrefs

Complement of A038109.
A005117, A036537, A036966, A048109, A175496, A268335 and A336590 are subsequences.
Numbers without an exponent k in their prime factorization: A001694 (k=1), this sequence (k=2), A386799 (k=3), A386803 (k=4), A386807 (k=5).
Numbers that have exactly m exponents in their prime factorization that are equal to 2: this sequence (m=0), A386796 (m=1), A386797 (m=2), A386798 (m=3).

Programs

  • Maple
    q:= n-> andmap(i-> i[2]<>2, ifactors(n)[2]):
    select(q, [$1..100])[];  # Alois P. Heinz, Aug 12 2020
  • Mathematica
    Select[Range[100], !MemberQ[FactorInteger[#][[;;, 2]], 2] &]
  • PARI
    is(n) = {my(f = factor(n)); for(i = 1, #f~, if(f[i, 2] == 2, return(0))); 1; } \\ Amiram Eldar, Oct 21 2023

Formula

Sum_{n>=1} 1/a(n)^s = zeta(s) * Product_{p prime} (1 - 1/p^(2*s) + 1/p^(3*s)), for s > 1. - Amiram Eldar, Oct 21 2023

A065487 Decimal expansion of Product_{p prime} (1 + 1/(p*(p^2-1))).

Original entry on oeis.org

1, 2, 3, 1, 2, 9, 1, 1, 4, 8, 8, 8, 8, 6, 0, 3, 5, 6, 2, 7, 7, 4, 7, 8, 7, 6, 5, 1, 2, 7, 2, 0, 3, 3, 7, 0, 9, 8, 6, 3, 6, 9, 4, 5, 9, 4, 5, 6, 1, 7, 1, 5, 3, 4, 1, 2, 4, 8, 3, 1, 1, 2, 8, 7, 5, 6, 9, 2, 6, 9, 6, 0, 7, 9, 7, 4, 1, 0, 8, 6, 7, 8, 0, 7, 2, 2, 1, 1, 4, 0, 4, 9, 3, 3, 5, 2, 7, 8, 2
Offset: 1

Views

Author

N. J. A. Sloane, Nov 19 2001

Keywords

Examples

			1.2312911488886035627747876512720337...
		

Crossrefs

Programs

  • Mathematica
    $MaxExtraPrecision = 600; digits = 99; terms = 600; P[n_] := PrimeZetaP[n]; LR = Join[{0, 0, 0}, LinearRecurrence[{0, 2, -1, -1, 1}, {3, 0, 5, -3, 7}, terms + 10]]; r[n_Integer] := LR[[n]]; Exp[NSum[r[n]*P[n - 1]/(n - 1), {n, 3, terms}, NSumTerms -> terms, WorkingPrecision -> digits + 10]] // RealDigits[#, 10, digits]& // First (* Jean-François Alcover, Apr 18 2016 *)
  • PARI
    prodeulerrat(1 + 1/(p*(p^2-1))) \\ Amiram Eldar, Mar 17 2021

Formula

Equals Sum_{k>=1} 1/A001615(A036966(k)). - Amiram Eldar, Jun 23 2020
Equals Sum_{k>=1} A003557(k)/k^3. - Amiram Eldar, Jan 25 2024
Equals lim_{m->oo} (1/m) * Sum_{k=1..m} A047994(k)/A000010(k). - Amiram Eldar, Feb 04 2024

A362974 Decimal expansion of Product_{p prime} (1 + 1/p^(4/3) + 1/p^(5/3)).

Original entry on oeis.org

4, 6, 5, 9, 2, 6, 6, 1, 2, 2, 5, 0, 0, 6, 5, 6, 9, 4, 1, 2, 7, 7, 4, 3, 1, 1, 0, 8, 9, 1, 3, 6, 2, 5, 8, 6, 2, 1, 3, 0, 5, 4, 3, 3, 6, 7, 2, 8, 3, 2, 5, 6, 5, 3, 8, 4, 7, 5, 7, 6, 9, 2, 4, 0, 1, 5, 3, 0, 3, 4, 1, 8, 0, 8, 6, 5, 7, 3, 5, 2, 3, 8, 7, 2, 1, 8, 0, 7, 7, 5, 8, 9, 0, 2, 6, 8, 4, 6, 2, 3, 4, 9, 0, 9, 7
Offset: 1

Views

Author

Amiram Eldar, May 11 2023

Keywords

Comments

The coefficient c_0 of the leading term in the asymptotic formula for the number of cubefull numbers (A036966) not exceeding x, N(x) = c_0 * x^(1/3) + c_1 * x^(1/4) + c_2 * x^(1/5) + o(x^(1/8)) (Bateman and Grosswald, 1958; Finch, 2003).

Examples

			4.65926612250065694127743110891362586213054336728325...
		

References

  • Steven R. Finch, Mathematical Constants, Cambridge University Press, 2003, section 2.6.1, pp. 113-115.

Crossrefs

Cf. A036966, A090699 (analogous constant for powerful numbers), A244000, A337736, A362973, A362975 (c_1), A362976 (c_2).
Cf. A051904.

Programs

  • Mathematica
    $MaxExtraPrecision = 1000; m = 1000; c = LinearRecurrence[{0, 0, 0, -1, -1}, {0, 0, 0, 4, 5}, m]; RealDigits[(1 + 1/2^(4/3) + 1/2^(5/3)) * (1 + 1/3^(4/3) + 1/3^(5/3)) * Exp[NSum[Indexed[c, n]*(PrimeZetaP[n/3] - 1/2^(n/3) - 1/3^(n/3))/n, {n, 4, m}, NSumTerms -> m, WorkingPrecision -> m]], 10, 120][[1]]
  • PARI
    prodeulerrat(1 + 1/p^4 + 1/p^5, 1/3)

Formula

Equals 1 + lim_{m->oo} (1/m) Sum_{k=1..m} A337736(k).

A065483 Decimal expansion of totient constant Product_{p prime} (1 + 1/(p^2*(p-1))).

Original entry on oeis.org

1, 3, 3, 9, 7, 8, 4, 1, 5, 3, 5, 7, 4, 3, 4, 7, 2, 4, 6, 5, 9, 9, 1, 5, 2, 5, 8, 6, 5, 1, 4, 8, 8, 6, 0, 5, 2, 7, 7, 5, 2, 4, 2, 2, 4, 9, 7, 8, 8, 1, 8, 2, 8, 0, 6, 6, 6, 3, 0, 1, 5, 0, 6, 7, 6, 4, 6, 7, 9, 4, 8, 2, 7, 2, 7, 6, 0, 0, 9, 8, 2, 3, 7, 3, 7, 3, 4, 3, 6, 6, 4, 4, 0, 8, 5, 0, 4, 5, 4
Offset: 1

Views

Author

N. J. A. Sloane, Nov 19 2001

Keywords

Comments

The sum of the reciprocals of the cubefull numbers (A036966). - Amiram Eldar, Jun 23 2020

Examples

			1.339784153574347246599152586514886052775...
		

Crossrefs

Programs

  • Mathematica
    $MaxExtraPrecision = 500; digits = 99; terms = 500; P[n_] := PrimeZetaP[n]; LR = Join[{0, 0, 0}, LinearRecurrence[{2, -1, -1, 1}, {3, 4, 5, 3}, terms + 10]]; r[n_Integer] := LR[[n]]; Exp[NSum[r[n]*P[n - 1]/(n - 1), {n, 3, terms}, NSumTerms -> terms, WorkingPrecision -> digits + 10]] // RealDigits[#, 10, digits]& // First (* Jean-François Alcover, Apr 18 2016 *)
  • PARI
    prodeulerrat(1 + 1/(p^2*(p-1))) \\ Vaclav Kotesovec, Sep 19 2020

Formula

Equals (6/Pi^2) * A065484. - Amiram Eldar, Jun 23 2020

A384051 The number of integers k from 1 to n such that the greatest divisor of k that is a unitary divisor of n is a cubefull number.

Original entry on oeis.org

1, 1, 2, 3, 4, 2, 6, 8, 8, 4, 10, 6, 12, 6, 8, 16, 16, 8, 18, 12, 12, 10, 22, 16, 24, 12, 27, 18, 28, 8, 30, 32, 20, 16, 24, 24, 36, 18, 24, 32, 40, 12, 42, 30, 32, 22, 46, 32, 48, 24, 32, 36, 52, 27, 40, 48, 36, 28, 58, 24, 60, 30, 48, 64, 48, 20, 66, 48, 44
Offset: 1

Views

Author

Amiram Eldar, May 18 2025

Keywords

Crossrefs

Unitary analog of A384040.
The number of integers k from 1 to n such that the greatest divisor of k that is a unitary divisor of n is: A047994 (1), A384048 (squarefree), A384049 (cubefree), A384050 (powerful), this sequence (cubefull), A384052 (square), A384053 (cube), A384054 (exponentially odd), A384055 (odd), A384056 (power of 2), A384057 (3-smooth), A384058 (5-rough).

Programs

  • Mathematica
    f[p_, e_] := p^e - If[e < 3, 1, 0]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a,100]
  • PARI
    a(n) = {my(f = factor(n)); prod(i = 1, #f~, f[i,1]^f[i,2] - if(f[i,2] < 3, 1, 0));}

Formula

Multiplicative with a(p^e) = p^e-1 if e <= 2, and p^e if e >= 3.
a(n) = n * A047994(n) / A384049(n).
a(n) = A047994(A360539(n)) * A360540(n).
Dirichlet g.f.: zeta(s-1) * Product_{p prime} (1 - 1/p^s - 1/p^(2*s) + 1/p^(2*s-1) + 1/p^(3*s-1)).
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = Product_{p prime} (1 - 1/p^2 + 1/p^3 - 1/p^4 + 1/p^5) = 0.714093594477970831206... .
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