cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A079559 Number of partitions of n into distinct parts of the form 2^j-1, j=1,2,....

Original entry on oeis.org

1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 1
Offset: 0

Views

Author

Vladeta Jovovic, Jan 25 2003

Keywords

Comments

Differences of the Meta-Fibonacci sequence for s=0. - Frank Ruskey and Chris Deugau (deugaucj(AT)uvic.ca)
Fixed point of morphism 0-->0, 1-->110 - Joerg Arndt, Jun 07 2007
A006697(k) gives number of distinct subwords of length k, conjectured to be equal to A094913(k)+1. - M. F. Hasler, Dec 19 2007
Characteristic function for the range of A005187: a(A055938(n))=0; a(A005187(n))=1; if a(m)=1 then either a(m-1)=1 or a(m+1)=1. - Reinhard Zumkeller, Mar 18 2009
The number of zeros between successive pairs of ones in this sequence is A007814. - Franklin T. Adams-Watters, Oct 05 2011
Length of n-th run = abs(A088705) + 1. - Reinhard Zumkeller, Dec 11 2011

Examples

			a(11)=1 because we have [7,3,1].
G.f. = 1 + x + x^3 + x^4 + x^7 + x^8 + x^10 + x^11 + x^15 + x^16 + x^18 + ...
From _Omar E. Pol_, Nov 30 2009: (Start)
The sequence, displayed as irregular triangle, in which rows length are powers of 2, begins:
1;
1,0;
1,1,0,0;
1,1,0,1,1,0,0,0;
1,1,0,1,1,0,0,1,1,0,1,1,0,0,0,0;
1,1,0,1,1,0,0,1,1,0,1,1,0,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,0,0,0;
1,1,0,1,1,0,0,1,1,0,1,1,0,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,0,1,1,0,1,1,0,0,1,1,0,1,1,0,0,0,0,0,0;
(End)
		

Crossrefs

Programs

  • Haskell
    a079559 = p $ tail a000225_list where
       p _      0 = 1
       p (k:ks) m = if m < k then 0 else p ks (m - k) + p ks m
    -- Reinhard Zumkeller, Dec 11 2011
    
  • Haskell
    a079559_list = 1 : f [1] where
       f xs = ys ++ f ys where ys = init xs ++ [1] ++ tail xs ++ [0]
    -- Reinhard Zumkeller, May 05 2015
    
  • Maple
    g:=product(1+x^(2^n-1),n=1..15): gser:=series(g,x=0,110): seq(coeff(gser,x,n),n=0..104); # Emeric Deutsch, Apr 06 2006
    d := n -> if n=1 then 1 else A046699(n)-A046699(n-1) fi; # Frank Ruskey and Chris Deugau (deugaucj(AT)uvic.ca)
  • Mathematica
    row[1] = {1}; row[2] = {1, 0}; row[n_] := row[n] = row[n-1] /. 1 -> Sequence[1, 1, 0]; Table[row[n], {n, 1, 7}] // Flatten (* Jean-François Alcover, Jul 30 2012, after Omar E. Pol *)
    CoefficientList[ Series[ Product[1 + x^(2^n - 1), {n, 6}], {x, 0, 104}], x] (* or *)
    Nest[ Flatten[# /. {0 -> {0}, 1 -> {1, 1, 0}}] &, {1}, 6] (* Robert G. Wilson v, Sep 08 2014 *)
  • PARI
    w="1,";for(i=1,5,print1(w=concat([w,w,"0,"])))
    
  • PARI
    A079559(n,w=[1])=until(n<#w=concat([w,w,[0]]),);w[n+1] \\ M. F. Hasler, Dec 19 2007
    
  • PARI
    {a(n) = if( n<0, 0, polcoeff( prod(k=1, #binary(n+1), 1 + x^(2^k-1), 1 + x * O(x^n)), n))} /* Michael Somos, Aug 03 2009 */
    
  • Python
    def a053644(n): return 0 if n==0 else 2**(len(bin(n)[2:]) - 1)
    def a043545(n):
        x=bin(n)[2:]
        return int(max(x)) - int(min(x))
    l=[1]
    for n in range(1, 101): l+=[a043545(n + 1)*l[n + 1 - a053644(n + 1)], ]
    print(l) # Indranil Ghosh, Jun 11 2017

Formula

G.f.: Product_{n>=1} (1 + x^(2^n-1)).
a(n) = 1 if n=0, otherwise A043545(n+1)*a(n+1-A053644(n+1)). - Reinhard Zumkeller, Aug 19 2006
a(n) = p(n,1) with p(n,k) = p(n-k,2*k+1) + p(n,2*k+1) if k <= n, otherwise 0^n. - Reinhard Zumkeller, Mar 18 2009
Euler transform is sequence A111113 sequence offset -1. - Michael Somos, Aug 03 2009
G.f.: Product_{k>0} (1 - x^k)^-A111113(k+1). - Michael Somos, Aug 03 2009
a(n) = A108918(n+1) mod 2. - Joerg Arndt, Apr 06 2011
a(n) = A000035(A153000(n)), n >= 1. - Omar E. Pol, Nov 29 2009, Aug 06 2013

Extensions

Edited by M. F. Hasler, Jan 03 2008

A048883 a(n) = 3^wt(n), where wt(n) = A000120(n).

Original entry on oeis.org

1, 3, 3, 9, 3, 9, 9, 27, 3, 9, 9, 27, 9, 27, 27, 81, 3, 9, 9, 27, 9, 27, 27, 81, 9, 27, 27, 81, 27, 81, 81, 243, 3, 9, 9, 27, 9, 27, 27, 81, 9, 27, 27, 81, 27, 81, 81, 243, 9, 27, 27, 81, 27, 81, 81, 243, 27, 81, 81, 243, 81, 243, 243, 729, 3, 9, 9, 27, 9, 27, 27, 81, 9, 27, 27, 81, 27, 81
Offset: 0

Views

Author

Keywords

Comments

Or, a(n)=number of 1's ("live" cells) at stage n of a 2-dimensional cellular automata evolving by the rule: 1 if NE+NW+S=1, else 0.
This is the odd-rule cellular automaton defined by OddRule 013 (see Ekhad-Sloane-Zeilberger "Odd-Rule Cellular Automata on the Square Grid" link). - N. J. A. Sloane, Feb 25 2015
Or, start with S=[1]; replace S by [S, 3*S]; repeat ad infinitum.
Fixed point of the morphism 1 -> 13, 3 -> 39, 9 -> 9(27), ... = 3^k -> 3^k 3^(k+1), ... starting from a(0) = 1; 1 -> 13 -> 1339 -> = 1339399(27) -> 1339399(27)399(27)9(27)(27)(81) -> ..., . - Robert G. Wilson v, Jan 24 2006
Equals row sums of triangle A166453 (the square of Sierpiński's gasket, A047999). - Gary W. Adamson, Oct 13 2009
First bisection of A169697=1,5,3,19,3,. a(2n+2)+a(2n+3)=12,12,36,=12*A147610 ? Distribution of terms (in A000244): A011782=1,A000079 for first array, A000079 for second. - Paul Curtz, Apr 20 2010
a(A000225(n)) = A000244(n) and a(m) != A000244(n) for m < A000225(n). - Reinhard Zumkeller, Nov 14 2011
This sequence pertains to phenotype Punnett square mathematics. Start with X=1. Each hybrid cross involves the equation X:3X. Therefore, the ratio in the first (mono) hybrid cross is X=1:3X=3(1) or 3; or 3:1. When you move up to the next hybridization level, replace the previous cross ratio with X. X now represents 2 numbers-1:3. Therefore, the ratio in the second (di) hybrid cross is X=(1:3):3X=[3(1):3(3)] or (3:9). Put it together and you get 1:3:3:9. Each time you move up a hybridization level, replace the previous ratio with X, and use the same equation-X:3X to get its ratio. - John Michael Feuk, Dec 10 2011
Number of odd values in the n-th layer of Pascal's tetrahedron (see A268240). - Caden Le, Mar 03 2025
a(x*y) <= a(x)^A000120(y). - Joe Amos, Mar 28 2025

Examples

			From _Omar E. Pol_, Jun 07 2009: (Start)
Triangle begins:
  1;
  3;
  3,9;
  3,9,9,27;
  3,9,9,27,9,27,27,81;
  3,9,9,27,9,27,27,81,9,27,27,81,27,81,81,243;
  3,9,9,27,9,27,27,81,9,27,27,81,27,81,81,243,9,27,27,81,27,81,81,243,27,...
Or
  1;
  3,3;
  9,3,9,9;
  27,3,9,9,27,9,27,27;
  81,3,9,9,27,9,27,27,81,9,27,27,81,27,81,81;
  243,3,9,9,27,9,27,27,81,9,27,27,81,27,81,81,243,9,27,27,81,27,81,81,243,27...
(End)
		

Crossrefs

For generating functions Product_{k>=0} (1+a*x^(b^k)) for the following values of (a,b) see: (1,2) A000012 and A000027, (1,3) A039966 and A005836, (1,4) A151666 and A000695, (1,5) A151667 and A033042, (2,2) A001316, (2,3) A151668, (2,4) A151669, (2,5) A151670, (3,2) A048883, (3,3) A117940, (3,4) A151665, (3,5) A151671, (4,2) A102376, (4,3) A151672, (4,4) A151673, (4,5) A151674.
A generalization of A001316. Cf. A102376.
Partial sums give A130665. - David Applegate, Jun 11 2009

Programs

  • Haskell
    a048883 = a000244 . a000120  -- Reinhard Zumkeller, Nov 14 2011
  • Mathematica
    Nest[ Join[#, 3#] &, {1}, 6] (* Robert G. Wilson v, Jan 24 2006 and modified Jul 27 2014*)
    a[n_] := 3^DigitCount[n, 2, 1]; Array[a, 80, 0] (* Jean-François Alcover, Nov 15 2017 *)
  • PARI
    a(n)=n=binary(n);3^sum(i=1,#n,n[i])
    

Formula

a(n) = Product_{k=0..log_2(n)} 3^b(n,k), where b(n,k) = coefficient of 2^k in binary expansion of n (offset 0). - Paul D. Hanna
a(n) = 3*a(n/2) if n is even, otherwise a(n) = a((n+1)/2).
G.f.: Product_{k>=0} (1+3*x^(2^k)). The generalization k^A000120 has generating function (1 + kx)*(1 + kx^2)*(1 + kx^4)*...
a(n+1) = Sum_{i=0..n} (binomial(n, i) mod 2) * Sum_{j=0..i} (binomial(i, j) mod 2). - Benoit Cloitre, Nov 16 2003
a(0)=1, a(n) = 3*a(n-A053644(n)) for n > 0. - Joe Slater, Jan 31 2016
G.f. A(x) satisfies: A(x) = (1 + 3*x) * A(x^2). - Ilya Gutkovskiy, Jul 09 2019

Extensions

Corrected by Ralf Stephan, Jun 19 2003
Entry revised by N. J. A. Sloane, May 30 2009
Offset changed to 0, Jun 11 2009

A153141 Permutation of nonnegative integers: A059893-conjugate of A153151.

Original entry on oeis.org

0, 1, 3, 2, 7, 6, 4, 5, 15, 14, 12, 13, 8, 9, 10, 11, 31, 30, 28, 29, 24, 25, 26, 27, 16, 17, 18, 19, 20, 21, 22, 23, 63, 62, 60, 61, 56, 57, 58, 59, 48, 49, 50, 51, 52, 53, 54, 55, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 127, 126, 124, 125, 120, 121
Offset: 0

Views

Author

Antti Karttunen, Dec 20 2008

Keywords

Comments

This permutation is induced by a wreath recursion a = s(a,b), b = (b,b) (i.e., binary transducer, where s means that the bits at that state are toggled: 0 <-> 1) given on page 103 of the Bondarenko, Grigorchuk, et al. paper, starting from the active (swapping) state a and rewriting bits from the second most significant bit to the least significant end, continuing complementing as long as the first 1-bit is reached, which is the last bit to be complemented.
The automorphism group of infinite binary tree (isomorphic to an infinitely iterated wreath product of cyclic groups of two elements) embeds naturally into the group of "size-preserving Catalan bijections". Scheme-function psi gives an isomorphism that maps this kind of permutation to the corresponding Catalan automorphism/bijection (that acts on S-expressions). The following identities hold: *A069770 = psi(A063946) (just swap the left and right subtrees of the root), *A057163 = psi(A054429) (reflect the whole tree), *A069767 = psi(A153141), *A069768 = psi(A153142), *A122353 = psi(A006068), *A122354 = psi(A003188), *A122301 = psi(A154435), *A122302 = psi(A154436) and from *A154449 = psi(A154439) up to *A154458 = psi(A154448). See also comments at A153246 and A153830.
a(1) to a(2^n) is the sequence of row sequency numbers in a Hadamard-Walsh matrix of order 2^n, when constructed to give "dyadic" or Payley sequency ordering. - Ross Drewe, Mar 15 2014
In the Stern-Brocot enumeration system for positive rationals (A007305/A047679), this permutation converts the denominator into the numerator: A007305(n) = A047679(a(n)). - Yosu Yurramendi, Aug 01 2020

Examples

			18 = 10010 in binary and after complementing the second, third and fourth most significant bits at positions 3, 2 and 1, we get 1110, at which point we stop (because bit-1 was originally 1) and fix the rest, so we get 11100 (28 in binary), thus a(18)=28. This is the inverse of "binary adding machine". See pages 8, 9 and 103 in the Bondarenko, Grigorchuk, et al. paper.
19 = 10011 in binary. By complementing bits in (zero-based) positions 3, 2 and 1 we get 11101 in binary, which is 29 in decimal, thus a(19)=29.
		

Crossrefs

Inverse: A153142. a(n) = A059893(A153151(A059893(n))) = A059894(A153152(A059894(n))) = A154440(A154445(n)) = A154442(A154443(n)). Corresponds to A069767 in the group of Catalan bijections. Cf. also A154435-A154436, A154439-A154448, A072376.
Differs from A006068 for the first time at n=14, where a(14)=10 while A006068(14)=11.
A240908-A240910 these give "natural" instead of "dyadic" sequency ordering values for Hadamard-Walsh matrices, orders 8,16,32. - Ross Drewe, Mar 15 2014

Programs

  • Python
    def ok(n): return n&(n - 1)==0
    def a153151(n): return n if n<2 else 2*n - 1 if ok(n) else n - 1
    def A(n): return (int(bin(n)[2:][::-1], 2) - 1)/2
    def msb(n): return n if n<3 else msb(n/2)*2
    def a059893(n): return A(n) + msb(n)
    def a(n): return 0 if n==0 else a059893(a153151(a059893(n))) # Indranil Ghosh, Jun 09 2017
    
  • R
    maxlevel <- 5 # by choice
    a <- 1
    for(m in 1:maxlevel){
    a[2^m    ] <- 2^(m+1) - 1
    a[2^m + 1] <- 2^(m+1) - 2
    for (k in 1:(2^m-1)){
       a[2^(m+1) + 2*k    ] <- 2*a[2^m + k]
       a[2^(m+1) + 2*k + 1] <- 2*a[2^m + k] + 1}
    }
    a <- c(0,a)
    # Yosu Yurramendi, Aug 01 2020

Formula

Conjecture: a(n) = f(a(f(a(A053645(n)))) + A053644(n)) for n > 0 where f(n) = A054429(n) for n > 0 with f(0) = 0. - Mikhail Kurkov, Oct 02 2023
From Mikhail Kurkov, Dec 22 2023: (Start)
a(n) < 2^k iff n < 2^k for k >= 0.
Conjectured formulas:
a(2^m + k) = f(2^m + f(k)) for m >= 0, 0 <= k < 2^m with a(0) = 0.
a(n) = f(A153142(f(n))) for n > 0 with a(0) = 0. (End)

A135416 a(n) = A036987(n)*(n+1)/2.

Original entry on oeis.org

1, 0, 2, 0, 0, 0, 4, 0, 0, 0, 0, 0, 0, 0, 8, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 16, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 32, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
Offset: 1

Views

Author

N. J. A. Sloane, based on a message from Guy Steele and Don Knuth, Mar 01 2008

Keywords

Comments

Guy Steele defines a family of 36 integer sequences, denoted here by GS(i,j) for 1 <= i, j <= 6, as follows. a[1]=1; a[2n] = i-th term of {0,1,a[n],a[n]+1,2a[n],2a[n]+1}; a[2n+1] = j-th term of {0,1,a[n],a[n]+1,2a[n],2a[n]+1}. The present sequence is GS(1,5).
The full list of 36 sequences:
GS(1,1) = A000007
GS(1,2) = A000035
GS(1,3) = A036987
GS(1,4) = A007814
GS(1,5) = A135416 (the present sequence)
GS(1,6) = A135481
GS(2,1) = A135528
GS(2,2) = A000012
GS(2,3) = A000012
GS(2,4) = A091090
GS(2,5) = A135517
GS(2,6) = A135521
GS(3,1) = A036987
GS(3,2) = A000012
GS(3,3) = A000012
GS(3,4) = A000120
GS(3,5) = A048896
GS(3,6) = A038573
GS(4,1) = A135523
GS(4,2) = A001511
GS(4,3) = A008687
GS(4,4) = A070939
GS(4,5) = A135529
GS(4,6) = A135533
GS(5,1) = A048298
GS(5,2) = A006519
GS(5,3) = A080100
GS(5,4) = A087808
GS(5,5) = A053644
GS(5,6) = A000027
GS(6,1) = A135534
GS(6,2) = A038712
GS(6,3) = A135540
GS(6,4) = A135542
GS(6,5) = A054429
GS(6,6) = A003817
(with a(0)=1): Moebius transform of A038712.

Crossrefs

Equals A048298(n+1)/2. Cf. A036987, A182660.

Programs

  • Maple
    GS:=proc(i,j,M) local a,n; a:=array(1..2*M+1); a[1]:=1;
    for n from 1 to M do
    a[2*n] :=[0,1,a[n],a[n]+1,2*a[n],2*a[n]+1][i];
    a[2*n+1]:=[0,1,a[n],a[n]+1,2*a[n],2*a[n]+1][j];
    od: a:=convert(a,list); RETURN(a); end;
    GS(1,5,200):
  • Mathematica
    i = 1; j = 5; Clear[a]; a[1] = 1; a[n_?EvenQ] := a[n] = {0, 1, a[n/2], a[n/2]+1, 2*a[n/2], 2*a[n/2]+1}[[i]]; a[n_?OddQ] := a[n] = {0, 1, a[(n-1)/2], a[(n-1)/2]+1, 2*a[(n-1)/2], 2*a[(n-1)/2]+1}[[j]]; Array[a, 105] (* Jean-François Alcover, Sep 12 2013 *)
  • PARI
    A048298(n) = if(!n,0,if(!bitand(n,n-1),n,0));
    A135416(n) = (A048298(n+1)/2); \\ Antti Karttunen, Jul 22 2018
    
  • Python
    def A135416(n): return int(not(n&(n+1)))*(n+1)>>1 # Chai Wah Wu, Jul 06 2022

Formula

G.f.: sum{k>=1, 2^(k-1)*x^(2^k-1) }.
Recurrence: a(2n+1) = 2a(n), a(2n) = 0, starting a(1) = 1.

Extensions

Formulae and comments by Ralf Stephan, Jun 20 2014

A004754 Numbers n whose binary expansion starts 10.

Original entry on oeis.org

2, 4, 5, 8, 9, 10, 11, 16, 17, 18, 19, 20, 21, 22, 23, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 128, 129, 130, 131
Offset: 1

Views

Author

Keywords

Comments

A000120(a(n)) = A000120(n); A023416(a(n-1)) = A008687(n) for n > 1. - Reinhard Zumkeller, Dec 04 2015

Examples

			10 in binary is 1010, so 10 is in sequence.
		

Crossrefs

Cf. A123001 (binary version), A004755 (11), A004756 (100), A004757 (101), A004758 (110), A004759 (111).
Apart from initial terms, same as A004761.

Programs

  • Haskell
    import Data.List (transpose)
    a004754 n = a004754_list !! (n-1)
    a004754_list = 2 : concat (transpose [zs, map (+ 1) zs])
                       where zs = map (* 2) a004754_list
    -- Reinhard Zumkeller, Dec 04 2015
    
  • Mathematica
    w = {1, 0}; Select[Range[2, 131], If[# < 2^(Length@ w - 1), True, Take[IntegerDigits[#, 2], Length@ w] == w] &] (* Michael De Vlieger, Aug 08 2016 *)
  • PARI
    a(n)=n+2^floor(log(n)/log(2))
    
  • PARI
    is(n)=n>1 && !binary(n)[2] \\ Charles R Greathouse IV, Sep 23 2012
    
  • Python
    def A004754(n): return n+(1<Chai Wah Wu, Jul 13 2022

Formula

a(2n) = 2a(n), a(2n+1) = 2a(n) + 1 + [n==0].
a(n) = n + 2^floor(log_2(n)) = n + A053644(n).
a(2^m+k) = 2^(m+1) + k, m >= 0, 0 <= k < 2^m. - Yosu Yurramendi, Aug 08 2016

Extensions

Edited by Ralf Stephan, Oct 12 2003

A003817 a(0) = 0, a(n) = a(n-1) OR n.

Original entry on oeis.org

0, 1, 3, 3, 7, 7, 7, 7, 15, 15, 15, 15, 15, 15, 15, 15, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 31, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63, 63
Offset: 0

Views

Author

Keywords

Comments

Also, 0+1+2+...+n in lunar arithmetic in base 2 written in base 10. - N. J. A. Sloane, Oct 02 2010
For n>0: replace all 0's with 1's in binary representation of n. - Reinhard Zumkeller, Jul 14 2003

Crossrefs

This is Guy Steele's sequence GS(6, 6) (see A135416).
Cf. A167832, A167878. - Reinhard Zumkeller, Nov 14 2009
Cf. A179526; subsequence of A007448. - Reinhard Zumkeller, Jul 18 2010
Cf. A265705.

Programs

  • Haskell
    import Data.Bits ((.|.))
    a003817 n = if n == 0 then 0 else 2 * a053644 n - 1
    a003817_list = scanl (.|.) 0 [1..] :: [Integer]
    -- Reinhard Zumkeller, Dec 08 2012, Jan 15 2012
    
  • Maple
    A003817 := n -> n + Bits:-Nand(n, n):
    seq(A003817(n), n=0..61); # Peter Luschny, Sep 23 2019
  • Mathematica
    a[0] = 0; a[n_] := a[n] = BitOr[ a[n-1], n]; Table[a[n], {n, 0, 61}] (* Jean-François Alcover, Dec 19 2011 *)
    nxt[{n_,a_}]:={n+1,BitOr[a,n+1]}; Transpose[NestList[nxt,{0,0},70]] [[2]] (* Harvey P. Dale, May 06 2016 *)
    2^BitLength[Range[0,100]]-1 (* Paolo Xausa, Feb 08 2024 *)
  • PARI
    a(n)=1<<(log(2*n+1)\log(2))-1 \\ Charles R Greathouse IV, Dec 08 2011
    
  • Python
    def a(n): return 0 if n==0 else 1 + 2*a(int(n/2)) # Indranil Ghosh, Apr 28 2017
    
  • Python
    def A003817(n): return (1<Chai Wah Wu, Jul 17 2024

Formula

a(n) = a(n-1) + n*(1-floor(a(n-1)/n)). If 2^(k-1) <= n < 2^k, a(n) = 2^k - 1. - Benoit Cloitre, Aug 25 2002
a(n) = 1 + 2*a(floor(n/2)) for n > 0. - Benoit Cloitre, Apr 04 2003
G.f.: (1/(1-x)) * Sum_{k>=0} 2^k*x^2^k. - Ralf Stephan, Apr 18 2003
a(n) = 2*A053644(n)-1 = A092323(n) + A053644(n). - Reinhard Zumkeller, Feb 15 2004; corrected by Anthony Browne, Jun 26 2016
a(n) = OR{k OR (n-k): 0<=k<=n}. - Reinhard Zumkeller, Jul 15 2008
For n>0: a(n+1) = A035327(n) + n = A035327(n) XOR n. - Reinhard Zumkeller, Nov 14 2009
A092323(n+1) = floor(a(n)/2). - Reinhard Zumkeller, Jul 18 2010
a(n) = A265705(n,0) = A265705(n,n). - Reinhard Zumkeller, Dec 15 2015
a(n) = A062383(n) - 1.
G.f. A(x) satisfies: A(x) = 2*A(x^2)*(1 + x) + x/(1 - x). - Ilya Gutkovskiy, Aug 31 2019
a(n) >= A175039(n) - Austin Shapiro, Dec 29 2022

A130665 a(n) = Sum_{k=0..n} 3^wt(k), where wt() = A000120().

Original entry on oeis.org

1, 4, 7, 16, 19, 28, 37, 64, 67, 76, 85, 112, 121, 148, 175, 256, 259, 268, 277, 304, 313, 340, 367, 448, 457, 484, 511, 592, 619, 700, 781, 1024, 1027, 1036, 1045, 1072, 1081, 1108, 1135, 1216, 1225, 1252, 1279, 1360, 1387, 1468, 1549, 1792, 1801, 1828, 1855
Offset: 0

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Author

N. J. A. Sloane, based on a message from Don Knuth, Jun 23 2007

Keywords

Comments

Partial sums of A048883. - David Applegate, Jun 11 2009
From Gary W. Adamson, Aug 26 2016: (Start)
The formula of Mar 26 2010 is equivalent to the left-shifted vector of matrix powers (lim_{k->infinity} M^k), of the production matrix M:
1, 0, 0, 0, 0, 0, ...
4, 0, 0, 0, 0, 0, ...
3, 1, 0, 0, 0, 0, ...
0, 4, 0, 0, 0, 0, ...
0, 3, 1, 0, 0, 0, ...
0, 0, 4, 0, 0, 0, ...
0, 0, 3, 1, 0, 0, ...
...
The sequence divided by its aerated variant is (1, 4, 3, 0, 0, 0, ...). (End)

Crossrefs

Programs

  • Haskell
    a130665 = sum . map (3 ^) . (`take` a000120_list) . (+ 1)
    -- Reinhard Zumkeller, Apr 18 2012
    
  • Maple
    u:=3; a[1]:=1; M:=30; for n from 1 to M do a[2*n] := (u+1)*a[n]; a[2*n+1] := u*a[n] + a[n+1]; od; t1:=[seq( a[n], n=1..2*M )]; # Gives sequence with a different offset
  • Mathematica
    f[n_] := Sum[3^Count[ IntegerDigits[k, 2], 1], {k, 0, n}]; Array[f, 51, 0] (* Robert G. Wilson v, Jun 28 2010 *)
  • Python
    def a(n):  # formula version, n=10^10000 takes ~1 second
        if n == 0:
            return 1
        msb = 1 << (n.bit_length() - 1)
        return msb**2 + 3 * a(n-msb) # Stefan Pochmann, Mar 15 2023
    
  • Python
    def a(n):  # optimized, n=10^50000 takes ~1 second
        n += 1
        total = 0
        power3 = 1
        while n:
            log = n.bit_length() - 1
            total += power3 << (2*log)
            n -= 1 << log
            power3 *= 3
        return total # Stefan Pochmann, Mar 15 2023

Formula

With a different offset: a(1) = 1; a(n) = max { 3*a(k)+a(n-k) | 1 <= k <= n/2 }, for n>1.
a(2n+1) = 4*a(n) and a(2n) = 3*a(n-1) + a(n).
a(n) = (A147562(n+1) - 1)*3/4 + 1. - Omar E. Pol, Nov 08 2009
a(n) = A160410(n+1)/4. - Omar E. Pol, Nov 12 2009
Let r(x) = (1 + 4x + 3x^2), then (1 + 4x + 7x^2 + 16x^3 + ...) =
r(x)* r(x^2) * r(x^4) * r(x^8) * ... - Gary W. Adamson, Mar 26 2010
For asymptotics see the discussion in the comments in A006046. - N. J. A. Sloane, Mar 11 2021
a(n) = Sum_{k=0..floor(log_2(n+1))} 3^k * A360189(n,k). - Alois P. Heinz, Mar 06 2023
a(n) = msb^2 + 3*a(n-msb), where msb = A053644(n). - Stefan Pochmann, Mar 15 2023

Extensions

Simpler definition (and new offset) from David Applegate, Jun 11 2009
Lower limit of sum in definition changed from 1 to 0 by Robert G. Wilson v, Jun 28 2010

A004755 Binary expansion starts 11.

Original entry on oeis.org

3, 6, 7, 12, 13, 14, 15, 24, 25, 26, 27, 28, 29, 30, 31, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122
Offset: 1

Views

Author

Keywords

Comments

a(n) is the smallest value > a(n-1) (or > 1 for n=1) for which A001511(a(n)) = A001511(n). - Franklin T. Adams-Watters, Oct 23 2006

Examples

			12 in binary is 1100, so 12 is in the sequence.
		

Crossrefs

Equals union of A079946 and A080565.
Cf. A004754 (10), A004756 (100), A004757 (101), A004758 (110), A004759 (111).

Programs

  • Haskell
    import Data.List (transpose)
    a004755 n = a004755_list !! (n-1)
    a004755_list = 3 : concat (transpose [zs, map (+ 1) zs])
                       where zs = map (* 2) a004755_list
    -- Reinhard Zumkeller, Dec 04 2015
    
  • Maple
    a:= proc(n) n+2*2^floor(log(n)/log(2)) end: seq(a(n),n=1..60); # Muniru A Asiru, Oct 16 2018
  • Mathematica
    Flatten[Table[FromDigits[#,2]&/@(Join[{1,1},#]&/@Tuples[{0,1},n]),{n,0,5}]] (* Harvey P. Dale, Feb 05 2015 *)
  • PARI
    a(n)=n+2*2^floor(log(n)/log(2))
    
  • PARI
    is(n)=n>2 && binary(n)[2] \\ Charles R Greathouse IV, Sep 23 2012
    
  • Python
    f = open('b004755.txt', 'w')
    lo = 3
    hi = 4
    i = 1
    while i<16384:
        for x in range(lo,hi):
            f.write(str(i)+" "+str(x)+"\n")
            i += 1
        lo <<= 1
        hi <<= 1
    # Kenny Lau, Jul 05 2016
    
  • Python
    def A004755(n): return n+(1<Chai Wah Wu, Jul 13 2022

Formula

a(2n) = 2*a(n), a(2n+1) = 2*a(n) + 1 + 2*[n==0].
a(n) = n + 2 * 2^floor(log_2(n)) = A004754(n) + A053644(n).
a(n) = 2n + A080079(n). - Benoit Cloitre, Feb 22 2003
G.f.: (1/(1+x)) * (1 + Sum_{k>=0, t=x^2^k} 2^k*(2t+t^2)/(1+t)).
a(n) = n + 2^(floor(log_2(n)) + 1) = n + A062383(n). - Franklin T. Adams-Watters, Oct 23 2006
a(2^m+k) = 2^(m+1) + 2^m + k, m >= 0, 0 <= k < 2^m. - Yosu Yurramendi, Aug 08 2016

Extensions

Edited by Ralf Stephan, Oct 12 2003

A303767 May code of n: a(0) = 0, and for n > 0, if n = 2^k, a(n) = n + a(n-1), otherwise, when n = 2^k + r (with 0 < r < 2^k), then a(n) = 2^k + a(r-1); see comments for equivalent alternative descriptions.

Original entry on oeis.org

0, 1, 3, 2, 6, 4, 5, 7, 15, 8, 9, 11, 10, 14, 12, 13, 29, 16, 17, 19, 18, 22, 20, 21, 23, 31, 24, 25, 27, 26, 30, 28, 60, 32, 33, 35, 34, 38, 36, 37, 39, 47, 40, 41, 43, 42, 46, 44, 45, 61, 48, 49, 51, 50, 54, 52, 53, 55, 63, 56, 57, 59, 58, 62, 126, 64, 65, 67, 66, 70, 68, 69, 71, 79, 72, 73, 75, 74, 78, 76, 77, 93, 80, 81
Offset: 0

Views

Author

Antti Karttunen, May 02 2018

Keywords

Comments

This is also "minimal subset/superset bitmask" transform of the nonnegative integers, A001477. In that transform, applicable to any N -> N injection f, we start from a(0) = 0, after which for n > 0, if there are one or more k_i that are not already present in the sequence among terms a(0) .. a(n-1), and for which bitor(k_i,a(n-1)) = a(n-1), then a(n) = that k_i for which f(k_i) is minimized; otherwise, a(n) = that h_i for which f(h_i) is minimized among the infinite set of numbers h_i for which bitand(h_i,a(n-1)) = a(n-1) and that are not yet present in the sequence. In this case f(n) = A001477(n) = n.
The original, equivalent definition is:
a(0) = 0 and for n > 0, if there are one or more k_i that are not already present in the sequence among terms a(0) .. a(n-1), and for which bitor(k_i,a(n-1)) = a(n-1), then a(n) = that k_i which gives minimum value of A019565(k_i) amongst them; otherwise, when no such k_i exists, a(n) = the least number not already present that can be obtained by toggling a single 0-bit of a(n-1) to 1. This is done by trying to toggle successive vacant bits from the least significant end of the binary representation of a(n-1), until such a sum a(n-1) + 2^h (= a(n-1) bitxor 2^h) is found that is not already present in the sequence.
Shares with permutations like A003188, A006068, A300838, A302846, A303765 and A304083 the property that when moving from any a(n) to a(n+1) either a subset of 0-bits are toggled on (changed to 1's), or a subset of 1-bits are toggled off (changed to 0's), but no both kind of changes may occur at the same step.
Also, like A003188, A006068 and many other base-2 representation related permutations, this permutation preserves the binary size of n (A000523(n)), and furthermore, a(n) seems to stay at most points (except at powers of 2) remarkably close to n.
From Antti Karttunen, May 23 2018: (Start)
Outline of the proof that the definition involving A019565 is equivalent to the recurrent formula:
Even though A019565 is nonmonotonic, for example A019565(4) = 5 = p_3 < A019565(3) = 6 = p_1 * p_2, and in general, although there are always primes p_k < p_{i1} * p_{i2} * ... * p_{ih}, with i1, i2, ..., ih < k, it doesn't matter here, because not just the position of the most significant 1-bit is monotonic in this sequence (see the binary representation at A304747), but also in each subrange (2^k)+2 .. (2^(k+1))-1 the position of the second most significant 1-bit moves only leftward, i.e., is monotonic, which follows from the recursive formula.
To see this, consider the first time in this sequence when in a batch of terms (of equal binary width) we have bits in position k (the most significant position) and (k-1) on (that is, both are 1's), the latter corresponding to prime p_k: while in principle a bit-based rule could choose to subtract 2^(k-1), in preference to any 1-bits to the right of it (that correspond to primes p_{i1} .. p_{ih}), it cannot do so at this stage, because it is the second most significant 1-bit, and then it would not move only leftward, contradicting what was said above. Neither this can occur later when more 1-bits have appeared to their left: the recursive formula guarantees it.
Also conversely, even though p_4 = 7 > 6 = p_1 * p_2, and in general, we always have such prime p_k > p_{i1} * p_{i2} * ... * p_{ih}, with i1, i2, ..., ih < k, and while here A019565-based rule (see comments in A303760) would prefer dividing p_k out instead of any subset of p_{i1} .. p_{ih}, it happens that in that rule, the index of the largest prime (A061395) grows monotonically, so at the stage where p_k is the largest prime of the batch of length 2^(k-1), p_k just cannot be divided out, and also here the structure of the later batches is strictly determined by recursion.
(End)

Examples

			From _Michael De Vlieger_, May 23 2018: (Start)
Table below shows the initial 17 terms at right. First column is index n,
second shows "." if A303760(n) = largest divisor of A303760(n-1), or factor p.
   n     p\d  m=A303760(n)  A054841(m)    a(n)
  -------------------------------------------
   0       .        1               0       0
   1       2        2               1       1
   2       3        6              11       3
   3       .        3              10       2
   4       5       15             110       6
   5       .        5             100       4
   6       2       10             101       5
   7       3       30             111       7
   8       7      210            1111      15
   9       .        7            1000       8
  10       2       14            1001       9
  11       3       42            1011      11
  12       .       21            1010      10
  13       5      105            1110      14
  14       .       35            1100      12
  15       2       70            1101      13
  16      11      770           11101      29
  ...  (End)
		

Crossrefs

Cf. A303768 (inverse), A304747 (terms shown in base-2).
Cf. also A303763, A303765, A303769, A303775, A304083 (similar sequences).

Programs

  • Mathematica
    Map[FromDigits[#, 2] &@ Reverse@ If[# == 1, {0}, Function[f, ReplacePart[Table[0, {PrimePi[f[[-1, 1]]]}], #] &@ Map[PrimePi@ First@ # -> Last@ # &, f]]@ FactorInteger@ #] &@# &, Nest[Append[#, Block[{d = Divisors@ #[[-1]], p = 2}, If[Complement[d, #] != {}, Complement[d, #][[1]], While[Nand[Mod[#[[-1]], p] != 0, FreeQ[#, p #[[-1]] ] ], p = NextPrime@ p]; p #[[-1]] ] ] ] &, {1}, 83]] (* Michael De Vlieger, May 23 2018 *)
  • PARI
    A209229(n) = (n && !bitand(n,n-1));
    A053644(n) = { my(k=1); while(k<=n, k<<=1); (k>>1); }; \\ From A053644
    A303767(n) = if(!n,n,if(A209229(n),n+A303767(n-1),A053644(n)+A303767(n-A053644(n)-1))); \\ Program based on new recurrence added May 06 2018
    
  • PARI
    up_to = (2^7)-1;
    A006519(n) = (2^valuation(n, 2));
    A019565(n) = {my(j,v); factorback(Mat(vector(if(n, #n=vecextract(binary(n), "-1..1")), j, [prime(j), n[j]])~))}; \\ From A019565
    A048675(n) = { my(f = factor(n)); sum(k=1, #f~, f[k, 2]*2^primepi(f[k, 1]))/2; };
    v303767 = vector(up_to);
    m303768 = Map();
    w=1; for(n=1,up_to,s = Set([]); for(m=1,w, if((bitor(w,m)==w) && !mapisdefined(m303768,m), s = setunion(Set([A019565(m)]),s))); if(length(s)>0, w = A048675(vecmin(s)), b=A006519(1+w); while(bitand(w,b) || mapisdefined(m303768,w+b), b <<= 1); w += b); v303767[n] = w; mapput(m303768,w,n));
    A303767(n) = if(!n,n,v303767[n]);
    A303768(n) = if(!n,n,mapget(m303768,n));

Formula

a(0) = 0, and for n > 0, if n = 2^k, a(n) = n + a(n-1), otherwise, when n = 2^k + r (with 0 < r < 2^k), then a(n) = 2^k + a(r-1). \\ Antti Karttunen, May 06 2018
a(n) = A048675(A303760(n)).
a(n) = A052331(A303771(n)).
For all n >= 1, A000523(a(n)) = A000523(n), A007088(a(n)) = A304747(n).

Extensions

Name replaced with an equivalent, but simpler definition by Antti Karttunen, May 06 2018

A072376 a(n) = a(floor(n/2)) + a(floor(n/4)) + a(floor(n/8)) + ... starting with a(0)=0 and a(1)=1.

Original entry on oeis.org

0, 1, 1, 1, 2, 2, 2, 2, 4, 4, 4, 4, 4, 4, 4, 4, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 32, 32, 32, 32, 32, 32, 32, 32, 32, 32, 32, 32, 32, 32, 32, 32
Offset: 0

Views

Author

Henry Bottomley, Jul 19 2002

Keywords

Crossrefs

Programs

  • Mathematica
    lim = 100; CoefficientList[Series[1/(2 - 2 x) (2 x - x^2 + Sum[ 2^(k - 1) x^2^k, {k, Floor@ Log2@ lim}]), {x, 0, lim}], x] (* Michael De Vlieger, Jan 26 2016 *)
  • PARI
    a(n)=if(n<2, return(n)); 2^logint(n\2,2) \\ Charles R Greathouse IV, Jan 26 2016
    
  • Python
    def A072376(n): return n if n < 2 else 1 << n.bit_length()-2 # Chai Wah Wu, Jun 30 2022

Formula

For n > 1: a(n) = msb(n)/2 = 2^floor(log_2(n)-1) = 2*a(floor(n/2)).
G.f.: 1/(2-2x) * (2x-x^2 + Sum_{k>=1} 2^(k-1)*x^2^k). - Ralf Stephan, Apr 18 2003
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