cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-8 of 8 results.

A048250 Sum of the squarefree divisors of n.

Original entry on oeis.org

1, 3, 4, 3, 6, 12, 8, 3, 4, 18, 12, 12, 14, 24, 24, 3, 18, 12, 20, 18, 32, 36, 24, 12, 6, 42, 4, 24, 30, 72, 32, 3, 48, 54, 48, 12, 38, 60, 56, 18, 42, 96, 44, 36, 24, 72, 48, 12, 8, 18, 72, 42, 54, 12, 72, 24, 80, 90, 60, 72, 62, 96, 32, 3, 84, 144, 68, 54, 96, 144, 72, 12, 74
Offset: 1

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Author

Keywords

Comments

Also sum of divisors of the squarefree kernel of n: a(n) = A000203(A007947(n)). - Reinhard Zumkeller, Jul 19 2002
The absolute values of the Dirichlet inverse of A001615. - R. J. Mathar, Dec 22 2010
Row sums of the triangle in A206778. - Reinhard Zumkeller, Feb 12 2012
Inverse Möbius transform of n * mu(n)^2 = |A055615(n)|. - Wesley Ivan Hurt, Jun 08 2023

Examples

			For n=1000, out of the 16 divisors, four are squarefree: {1,2,5,10}. Their sum is 18. Or, 1000 = 2^3*5^3 hence a(1000) = (2+1)*(5+1) = 18.
		

References

  • D. Suryanarayana, On the core of an integer, Indian J. Math. 14 (1972) 65-74.

Crossrefs

Sum of the k-th powers of the squarefree divisors of n for k=0..10: A034444 (k=0), this sequence (k=1), A351265 (k=2), A351266 (k=3), A351267 (k=4), A351268 (k=5), A351269 (k=6), A351270 (k=7), A351271 (k=8), A351272 (k=9), A351273 (k=10).
Cf. A240976 (tenth of Dgf at s=3).

Programs

  • Haskell
    a034448 = sum . a206778_row  -- Reinhard Zumkeller, Feb 12 2012
    
  • Maple
    A048250 := proc(n) local ans, i:ans := 1: for i from 1 to nops(ifactors(n)[ 2 ]) do ans := ans*(1+ifactors(n)[ 2 ][ i ] [ 1 ]): od: RETURN(ans) end:
    # alternative:
    seq(mul(1+p, p = numtheory:-factorset(n)), n=1..1000); # Robert Israel, Mar 18 2015
  • Mathematica
    sumOfSquareFreeDivisors[ n_ ] := Plus @@ Select[ Divisors[ n ], MoebiusMu[ # ] != 0 & ]; Table[ sumOfSquareFreeDivisors[ i ], {i, 85} ]
    Table[Total[Select[Divisors[n],SquareFreeQ]],{n,80}] (* Harvey P. Dale, Jan 25 2013 *)
    a[1] = 1; a[n_] := Times@@(1 + FactorInteger[n][[;;,1]]); Array[a, 100] (* Amiram Eldar, Dec 19 2018 *)
  • PARI
    a(n)=if(n<1,0,sumdiv(n,d,if(core(d)==d,d)))
    
  • PARI
    a(n)=if(n<1,0,direuler(p=2,n,(1+p*X)/(1-X))[n])
    
  • PARI
    a(n)=sumdiv(n,d,moebius(d)^2*d); \\ Joerg Arndt, Jul 06 2011
    
  • PARI
    a(n)=my(f=factor(n)); for(i=1,#f~,f[i,2]=1); sigma(f) \\ Charles R Greathouse IV, Sep 09 2014
    
  • Python
    from math import prod
    from sympy import primefactors
    def A048250(n): return prod(p+1 for p in primefactors(n)) # Chai Wah Wu, Apr 20 2023
  • Sage
    def A048250(n): return mul(map(lambda p: p+1, prime_divisors(n)))
    [A048250(n) for n in (1..73)]  # Peter Luschny, May 23 2013
    

Formula

If n = Product p_i^e_i, a(n) = Product (p_i + 1). - Vladeta Jovovic, Apr 19 2001
Dirichlet g.f.: zeta(s)*zeta(s-1)/zeta(2*s-2). - Michael Somos, Sep 08 2002
a(n) = Sum_{d|n} mu(d)^2*d = Sum_{d|n} |A055615(d)|. - Benoit Cloitre, Dec 09 2002
Pieter Moree (moree(AT)mpim-bonn.mpg.de), Feb 20 2004 can show that Sum_{n <= x} a(n) = x^2/2 + O(x*sqrt{x}) and adds: "As S. R. Finch pointed out to me, in Suryanarayana's paper this is proved under the Riemann hypothesis with error term O(x^{7/5+epsilon})".
a(n) = psi(rad(n)) = A001615(A007947(n)). - Enrique Pérez Herrero, Aug 24 2010
a(n) = rad(n)*psi(n)/n = A001615(n)*A007947(n)/n. - Enrique Pérez Herrero, Aug 31 2010
G.f.: Sum_{k>=1} mu(k)^2*k*x^k/(1 - x^k). - Ilya Gutkovskiy, Jan 03 2017
Lim_{n->oo} (1/n) * Sum_{k=1..n} a(k)/k = 1. - Amiram Eldar, Jun 10 2020
a(n) = Sum_{d divides n} mu(d)^2*core(d), where core(n) = A007913(n). - Peter Bala, Jan 24 2024

A000188 (1) Number of solutions to x^2 == 0 (mod n). (2) Also square root of largest square dividing n. (3) Also max_{ d divides n } gcd(d, n/d).

Original entry on oeis.org

1, 1, 1, 2, 1, 1, 1, 2, 3, 1, 1, 2, 1, 1, 1, 4, 1, 3, 1, 2, 1, 1, 1, 2, 5, 1, 3, 2, 1, 1, 1, 4, 1, 1, 1, 6, 1, 1, 1, 2, 1, 1, 1, 2, 3, 1, 1, 4, 7, 5, 1, 2, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 3, 8, 1, 1, 1, 2, 1, 1, 1, 6, 1, 1, 5, 2, 1, 1, 1, 4, 9, 1, 1, 2, 1, 1, 1, 2, 1, 3
Offset: 1

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Author

Keywords

Comments

Shadow transform of the squares A000290. - Vladeta Jovovic, Aug 02 2002
Labos Elemer and Henry Bottomley independently proved that (2) and (3) define the same sequence. Bottomley also showed that (1) and (2) define the same sequence.
Proof that (2) = (3): Let max{gcd(d, n/d)} = K, then d = Kx, n/d = Ky so n = KKxy where xy is the squarefree part of n, otherwise K is not maximal. Observe also that g = gcd(K, xy) is not necessarily 1. Thus K is also the "maximal square-root factor" of n. - Labos Elemer, Jul 2000
We can write sqrt(n) = b*sqrt(c) where c is squarefree. Then b = A000188(n) is the "inner square root" of n, c = A007913(n) and b*c = A019554(n) = "outer square root" of n.

Examples

			a(8) = 2 because the largest square dividing 8 is 4, the square root of which is 2.
a(9) = 3 because 9 is a perfect square and its square root is 3.
a(10) = 1 because 10 is squarefree.
		

Crossrefs

Cf. A019554 (outer square root), A053150 (inner 3rd root), A019555 (outer 3rd root), A053164 (inner 4th root), A053166 (outer 4th root), A015052 (outer 5th root), A015053 (outer 6th root).
Cf. A240976 (Dgf at s=2).

Programs

  • Haskell
    a000188 n = product $ zipWith (^)
                          (a027748_row n) $ map (`div` 2) (a124010_row n)
    -- Reinhard Zumkeller, Apr 22 2012
    
  • Maple
    with(numtheory):A000188 := proc(n) local i: RETURN(op(mul(i,i=map(x->x[1]^floor(x[2]/2),ifactors(n)[2])))); end;
  • Mathematica
    Array[Function[n, Count[Array[PowerMod[#, 2, n ] &, n, 0 ], 0 ] ], 100]
    (* Second program: *)
    nMax = 90; sList = Range[Floor[Sqrt[nMax]]]^2; Sqrt[#] &/@ Table[ Last[ Select[ sList, Divisible[n, #] &]], {n, nMax}] (* Harvey P. Dale, May 11 2011 *)
    a[n_] := With[{d = Divisors[n]}, Max[GCD[d, Reverse[d]]]] (* Mamuka Jibladze, Feb 15 2015 *)
    f[p_, e_] := p^Floor[e/2]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Sep 18 2020 *)
  • PARI
    a(n)=if(n<1,0,sum(i=1,n,i*i%n==0))
    
  • PARI
    a(n)=sqrtint(n/core(n)) \\ Zak Seidov, Apr 07 2009
    
  • PARI
    a(n)=core(n, 1)[2] \\ Michel Marcus, Feb 27 2013
    
  • Python
    from sympy.ntheory.factor_ import core
    from sympy import integer_nthroot
    def A000188(n): return integer_nthroot(n//core(n),2)[0] # Chai Wah Wu, Jun 14 2021

Formula

a(n) = n/A019554(n) = sqrt(A008833(n)).
a(n) = Sum_{d^2|n} phi(d), where phi is the Euler totient function A000010.
Multiplicative with a(p^e) = p^floor(e/2). - David W. Wilson, Aug 01 2001
Dirichlet series: Sum_{n >= 1} a(n)/n^s = zeta(2*s - 1)*zeta(s)/zeta(2*s), (Re(s) > 1).
Dirichlet convolution of A037213 and A008966. - R. J. Mathar, Feb 27 2011
Finch & Sebah show that the average order of a(n) is 3 log n/Pi^2. - Charles R Greathouse IV, Jan 03 2013
a(n) = sqrt(n/A007913(n)). - M. F. Hasler, May 08 2014
Sum_{n>=1} lambda(n)*a(n)*x^n/(1-x^n) = Sum_{n>=1} n*x^(n^2), where lambda() is the Liouville function A008836 (cf. A205801). - Mamuka Jibladze, Feb 15 2015
a(2*n) = a(n)*(A096268(n-1) + 1). - observed by Velin Yanev, Jul 14 2017, The formula says that a(2n) = 2*a(n) only when 2-adic valuation of n (A007814(n)) is odd, otherwise a(2n) = a(n). This follows easily from the definition (2). - Antti Karttunen, Nov 28 2017
Sum_{k=1..n} a(k) ~ 3*n*((log(n) + 3*gamma - 1)/Pi^2 - 12*zeta'(2)/Pi^4), where gamma is the Euler-Mascheroni constant A001620. - Vaclav Kotesovec, Dec 01 2020
Conjecture: a(n) = Sum_{k=1..n} A010052(n*k). - Velin Yanev, Jul 04 2021
G.f.: Sum_{k>=1} phi(k) * x^(k^2) / (1 - x^(k^2)). - Ilya Gutkovskiy, Aug 20 2021

Extensions

Edited by M. F. Hasler, May 08 2014

A350014 Numbers whose square has a number of divisors coprime to 6.

Original entry on oeis.org

1, 4, 8, 9, 25, 27, 32, 36, 49, 64, 72, 100, 108, 121, 125, 169, 196, 200, 216, 225, 243, 256, 288, 289, 343, 361, 392, 441, 484, 500, 512, 529, 576, 675, 676, 729, 800, 841, 864, 900, 961, 968, 972, 1000, 1089, 1125, 1156, 1225, 1323, 1331, 1352, 1369, 1372, 1444
Offset: 1

Views

Author

Michael De Vlieger, Jan 17 2022

Keywords

Comments

a(n) = m in A001694 such that d(m^2) is not divisible by 3, where d(n) = A000005(n).
Supersequence of A051676 (composite numbers whose square has a prime number of divisors).
Subsequence of A001694 (powerful numbers).
Numbers whose prime factorization has only exponents that are congruent to {0, 2} mod 3 (A007494). - Amiram Eldar, Mar 31 2022

Crossrefs

Programs

  • Maple
    A350014 := proc(n)
        option remember ;
        local a;
        if n =1 then
            1;
        else
            for a from procname(n-1)+1 do
                if igcd(numtheory[tau](a^2),6) = 1 then
                    return a;
                end if;
            end do:
        end if;
    end proc:
    seq(A350014(n),n=1..20) ; # R. J. Mathar, Apr 06 2022
  • Mathematica
    Select[Range[1500], CoprimeQ[DivisorSigma[0, #^2], 6] &] (* or *)
    With[{nn = 1500}, Select[Union@ Flatten@ Table[a^2*b^3, {b, nn^(1/3)}, {a, Sqrt[nn/b^3]}], Mod[DivisorSigma[0, #^2], 3] != 0 &]]
  • PARI
    isok(m) = gcd(numdiv(m^2), 6) == 1; \\ Michel Marcus, Mar 04 2022

Formula

a(n) = {m : gcd(d(m^2), 6) = 1}.
Sum_{n>=1} 1/a(n) = 15*zeta(3)/Pi^2 (= 10 * A240976). - Amiram Eldar, Mar 31 2022

A078747 Expansion of Sum_{k>0} k*phi(k)*x^k/(1+x^k).

Original entry on oeis.org

1, 1, 7, 5, 21, 7, 43, 21, 61, 21, 111, 35, 157, 43, 147, 85, 273, 61, 343, 105, 301, 111, 507, 147, 521, 157, 547, 215, 813, 147, 931, 341, 777, 273, 903, 305, 1333, 343, 1099, 441, 1641, 301, 1807, 555, 1281, 507, 2163, 595, 2101, 521, 1911, 785, 2757, 547
Offset: 1

Views

Author

Vladeta Jovovic, Dec 22 2002

Keywords

Crossrefs

Programs

  • Mathematica
    f[p_, e_] := If[p == 2, (4^e - 1)/3, (p^(2*e + 1) + 1)/(p + 1)]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 50] (* Amiram Eldar, Oct 15 2022 *)
  • PARI
    a(n) = {my(f = factor(n)); prod(i = 1, #f~, if(f[i,1] == 2, (4^f[i,2]-1)/3, (f[i,1]^(2*f[i,2]+1)+1)/(f[i,1]+1))); } \\ Amiram Eldar, Oct 15 2022

Formula

Multiplicative with a(2^e) = (4^e-1)/3, a(p^e) = (p^(2*e+1)+1)/(p+1), p>2.
L.g.f.: log(Product_{k>=1} (1 + x^k)^phi(k)) = Sum_{n>=1} a(n)*x^n/n. - Ilya Gutkovskiy, May 21 2018
Sum_{k=1..n} a(k) ~ c * n^3, where c = zeta(3)/(4*zeta(2)) = 0.182690... (A240976). - Amiram Eldar, Oct 15 2022
Dirichlet g.f.: (zeta(s)*zeta(s-2)/zeta(s-1))*(1-2^(1-s)). - Amiram Eldar, Dec 30 2022

A362984 Decimal expansion of the asymptotic mean of the abundancy index of the powerful numbers (A001694).

Original entry on oeis.org

2, 1, 4, 9, 6, 8, 6, 9, 0, 3, 0, 1, 5, 2, 6, 7, 6, 5, 1, 2, 8, 2, 1, 9, 0, 4, 2, 1, 0, 5, 1, 0, 9, 4, 1, 6, 1, 4, 5, 9, 8, 7, 6, 5, 3, 2, 7, 5, 1, 0, 0, 9, 9, 9, 8, 7, 3, 2, 7, 3, 3, 4, 3, 7, 8, 9, 7, 6, 2, 7, 1, 7, 9, 4, 0, 3, 6, 4, 2, 3, 6, 5, 7, 4, 2, 7, 4, 2, 3, 7, 7, 1, 7, 0, 2, 4, 2, 2, 8, 9, 7, 3, 8, 6, 2
Offset: 1

Views

Author

Amiram Eldar, May 12 2023

Keywords

Comments

The abundancy index of a positive integer k is A000203(k)/k = A017665(k)/A017666(k).
The asymptotic mean of the abundancy index over all the positive integers is lim_{m->oo} (1/m) * Sum_{k=1..m} A000203(k)/k = Pi^2/6 = zeta(2) = 1.644934... (A013661).

Examples

			2.14968690301526765128219042105109416145987653275100999873...
		

Crossrefs

Similar constants (the asymptotic mean of the abundancy index of other sequences): A013661 (all positive integers), A082020 (cubefree), A111003 (odd), A157292 (5-free), A157294 (7-free), A157296 (9-free), A240976 (squares), A245058 (even), A306633 (squarefree), A362985 (cubefull).

Programs

  • Mathematica
    $MaxExtraPrecision = 1000; m = 1000; c = LinearRecurrence[{2, -3, 4, -6, 7, -7, 7, -6, 5, -3, 2, -1}, {0, 0, 0, 4, 5, 6, 0, -12, -9, -5, 0, 22}, m]; RealDigits[(2^4 + 2^2 + 2^(3/2) - 1)/(2^4 - 2)*(3^4 + 3^2 + 3^(3/2) - 1)/(3^4 - 3) * Exp[NSum[Indexed[c, n]*(PrimeZetaP[n/2] - 1/2^(n/2) - 1/3^(n/2))/n, {n, 4, m}, NSumTerms -> m, WorkingPrecision -> m]], 10, 120][[1]]
  • PARI
    prodeulerrat((p^8 + p^4 + p^3 - 1)/(p^8 - p^2), 1/2)

Formula

Equals lim_{m->oo} (1/m) * Sum_{k=1..m} A180114(k)/A001694(k).
Equals Product_{p prime} (p^4 + p^2 + p^(3/2) - 1)/(p^4 - p) = Product_{p prime} (1 + (p^2 + p^(3/2) + p - 1)/(p^4 - p)) (Jakimczuk and Lalín, 2022).

A362985 Decimal expansion of the asymptotic mean of the abundancy index of the cubefull numbers (A036966).

Original entry on oeis.org

2, 4, 8, 2, 1, 7, 9, 1, 9, 6, 4, 2, 2, 3, 5, 9, 5, 2, 5, 4, 6, 1, 6, 7, 6, 4, 3, 6, 7, 4, 6, 8, 7, 6, 9, 8, 5, 3, 6, 3, 6, 8, 9, 4, 0, 9, 7, 1, 9, 3, 0, 4, 6, 8, 3, 5, 4, 3, 6, 3, 9, 3, 2, 8, 1, 4, 4, 4, 2, 3, 3, 8, 8, 5, 7, 6, 7, 5, 0, 4, 6, 3, 4, 1, 1, 5, 0, 7, 3, 1, 0, 3, 9, 8, 0, 4, 4, 7, 4, 0, 3, 7, 3, 1, 0
Offset: 1

Views

Author

Amiram Eldar, May 12 2023

Keywords

Examples

			2.48217919642235952546167643674687698536368940971930468354...
		

Crossrefs

Similar constants (the asymptotic mean of the abundancy index of other sequences): A013661 (all positive integers), A082020 (cubefree), A111003 (odd), A157292 (5-free), A157294 (7-free), A157296 (9-free), A245058 (even), A240976 (squares), A306633 (squarefree), A362984 (powerful).

Programs

  • Mathematica
    $MaxExtraPrecision = 1000; m = 1000; c = LinearRecurrence[{2, -1, -2, 3, -2, -1, 3, -2, -2, 3, -1, -2, 3, -1, -1, 1}, {0, 0, 0, -4, 0, 6, 7, 4, 9, 0, -11, -22, -26, -21, -15, 20}, m]; RealDigits[((2^5 + 2^(10/3) + 2^3 + 2^(8/3) - 1)/(2^(10/3)*(2^(5/3) + 2^(1/3) + 1)))*((3^5 + 3^(10/3) + 3^3 + 3^(8/3) - 1)/(3^(10/3)*(3^(5/3) + 3^(1/3) + 1))) * Zeta[4/3] * Exp[NSum[Indexed[c, n]*(PrimeZetaP[n/3] - 1/2^(n/3) - 1/3^(n/3))/n, {n, 4, m}, NSumTerms -> m, WorkingPrecision -> m]], 10, 120][[1]]
  • PARI
    zeta(4/3) * prodeulerrat((p^15 + p^10 + p^9 + p^8 - 1)/(p^10 * (p^5 + p + 1)), 1/3)

Formula

Equals lim_{m->oo} (1/m) * Sum_{k=1..m} A362986(k)/A036966(k).
Equals zeta(4/3) * Product_{p prime} ((p^5 + p^(10/3) + p^3 + p^(8/3) - 1)/(p^(10/3) * (p^(5/3) + p^(1/3) + 1))).

A341747 Decimal expansion of zeta(3) * zeta(4) * Product_{p prime} (1 + 1/p^2 - 2/p^3 - 2/p^5 + 2/p^6).

Original entry on oeis.org

1, 3, 8, 6, 9, 2, 4, 1, 7, 0, 4, 1, 3, 5, 6, 5, 8, 6, 8, 9, 8, 8, 1, 4, 9, 1, 9, 7, 6, 6, 5, 1, 0, 6, 8, 3, 6, 1, 6, 5, 2, 6, 2, 0, 7, 8, 2, 6, 3, 9, 2, 9, 9, 1, 7, 4, 1, 1, 3, 7, 0, 1, 5, 8, 1, 3, 7, 2, 6, 0, 2, 1, 5, 6, 6, 1, 7, 6, 7, 9, 2, 2, 6, 3, 4, 1, 2
Offset: 1

Views

Author

Amiram Eldar, Feb 18 2021

Keywords

Comments

The constant c in the asymptotic formulas Sum_{n1, n2 <= x} sigma(lcm(n1, n2)) = c * x^4/4 + O(x^(7/2 + eps)) and Sum_{n1, n2 <= x} sigma(lcm(n1, n2))/(n1*n2) = c * x^2 + O(x^(3/2 + eps)).

Examples

			1.38692417041356586898814919766510683616526207826392...
		

Crossrefs

Cf. A000203 (sigma), A240976, A341748.

Programs

  • Mathematica
    $MaxExtraPrecision = 1500; m = 1500; c = LinearRecurrence[{0, -1, 2, 0, 2, -2}, {0, 2, -6, -2, 0, 2}, m]; Zeta[3] * Zeta[4] * Exp[NSum[Indexed[c, n]*PrimeZetaP[n]/n, {n, 2, m}, NSumTerms -> m, WorkingPrecision -> m]]
  • PARI
    zeta(3) * zeta(4) * prodeulerrat(1 + 1/p^2 - 2/p^3 - 2/p^5 + 2/p^6)

A341748 Decimal expansion of zeta(3) * Product_{p prime} (1 - 3/p^2 + 2/p^3 - 1/p^4 + 2/p^5 - 1/p^6).

Original entry on oeis.org

3, 3, 0, 9, 1, 8, 2, 9, 6, 2, 0, 8, 5, 0, 8, 8, 6, 5, 9, 7, 7, 0, 8, 9, 9, 7, 9, 9, 1, 3, 2, 2, 7, 8, 5, 4, 8, 9, 3, 5, 4, 3, 3, 4, 5, 4, 1, 0, 4, 8, 9, 4, 2, 7, 0, 5, 4, 3, 6, 0, 1, 4, 1, 8, 8, 5, 5, 4, 2, 4, 4, 1, 4, 1, 6, 5, 8, 7, 8, 3, 5, 2, 6, 0, 0, 0, 1
Offset: 0

Views

Author

Amiram Eldar, Feb 18 2021

Keywords

Comments

The constant c in the asymptotic formulas Sum_{n1, n2 <= x} phi(lcm(n1, n2)) = c * x^4/4 + O(x^(7/2 + eps)) and Sum_{n1, n2 <= x} phi(lcm(n1, n2))/(n1*n2) = c * x^2 + O(x^(3/2 + eps)).

Examples

			0.33091829620850886597708997991322785489354334541048...
		

Crossrefs

Cf. A000010 (phi), A240976, A341747.

Programs

  • Mathematica
    $MaxExtraPrecision = 1500; m = 1500; c = LinearRecurrence[{-1, 2, 0, 1, -1}, {0, -6, 6, -22, 40}, m]; f[x_] := 1 - 3 x^2 + 2 x^3 - x^4 + 2 x^5 - x^6; Zeta[3] * f[1/2] * f[1/3] * Exp[NSum[Indexed[c, n]*(PrimeZetaP[n] - 1/2^n - 1/3^n)/n, {n, 2, m}, NSumTerms -> m, WorkingPrecision -> m]]
  • PARI
    zeta(3) * prodeulerrat(1 - 3/p^2 + 2/p^3 - 1/p^4 + 2/p^5 - 1/p^6)
Showing 1-8 of 8 results.