cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A239660 Triangle read by rows in which row n lists two copies of the n-th row of triangle A237593.

Original entry on oeis.org

1, 1, 1, 1, 2, 2, 2, 2, 2, 1, 1, 2, 2, 1, 1, 2, 3, 1, 1, 3, 3, 1, 1, 3, 3, 2, 2, 3, 3, 2, 2, 3, 4, 1, 1, 1, 1, 4, 4, 1, 1, 1, 1, 4, 4, 2, 1, 1, 2, 4, 4, 2, 1, 1, 2, 4, 5, 2, 1, 1, 2, 5, 5, 2, 1, 1, 2, 5, 5, 2, 2, 2, 2, 5, 5, 2, 2, 2, 2, 5, 6, 2, 1, 1, 1, 1, 2, 6, 6, 2, 1, 1, 1, 1, 2, 6, 6, 3, 1, 1, 1, 1, 3, 6, 6, 3, 1, 1, 1, 1, 3, 6
Offset: 1

Views

Author

Omar E. Pol, Mar 24 2014

Keywords

Comments

For the construction of this sequence also we can start from A235791.
This sequence can be interpreted as an infinite Dyck path: UDUDUUDD...
Also we use this sequence for the construction of a spiral in which the arms in the quadrants give the symmetric representation of sigma, see example.
We can find the spiral (mentioned above) on the terraces of the stepped pyramid described in A244050. - Omar E. Pol, Dec 07 2016
The spiral has the property that the sum of the parts in the quadrants 1 and 3, divided by the sum of the parts in the quadrants 2 and 4, converges to 3/5. - Omar E. Pol, Jun 10 2019

Examples

			Triangle begins (first 15.5 rows):
1, 1, 1, 1;
2, 2, 2, 2;
2, 1, 1, 2, 2, 1, 1, 2;
3, 1, 1, 3, 3, 1, 1, 3;
3, 2, 2, 3, 3, 2, 2, 3;
4, 1, 1, 1, 1, 4, 4, 1, 1, 1, 1, 4;
4, 2, 1, 1, 2, 4, 4, 2, 1, 1, 2, 4;
5, 2, 1, 1, 2, 5, 5, 2, 1, 1, 2, 5;
5, 2, 2, 2, 2, 5, 5, 2, 2, 2, 2, 5;
6, 2, 1, 1, 1, 1, 2, 6, 6, 2, 1, 1, 1, 1, 2, 6;
6, 3, 1, 1, 1, 1, 3, 6, 6, 3, 1, 1, 1, 1, 3, 6;
7, 2, 2, 1, 1, 2, 2, 7, 7, 2, 2, 1, 1, 2, 2, 7;
7, 3, 2, 1, 1, 2, 3, 7, 7, 3, 2, 1, 1, 2, 3, 7;
8, 3, 1, 2, 2, 1, 3, 8, 8, 3, 1, 2, 2, 1, 3, 8;
8, 3, 2, 1, 1, 1, 1, 2, 3, 8, 8, 3, 2, 1, 1, 1, 1, 2, 3, 8;
9, 3, 2, 1, 1, 1, 1, 2, 3, 9, ...
.
Illustration of initial terms as an infinite Dyck path (row n = 1..4):
.
.                            /\/\    /\/\
.       /\  /\  /\/\  /\/\  /    \  /    \
.  /\/\/  \/  \/    \/    \/      \/      \
.
.
Illustration of initial terms for the construction of a spiral related to sigma:
.
.  row 1     row 2          row 3           row 4
.                                          _ _ _
.                                               |_
.             _ _                                 |
.   _ _      |                                    |
.  |   |     |                                    |
.            |         |           |              |
.            |_ _      |_         _|              |
.                        |_ _ _ _|               _|
.                                          _ _ _|
.
.[1,1,1,1] [2,2,2,2] [2,1,1,2,2,1,1,2] [3,1,1,3,3,1,1,3]
.
The first 2*A003056(n) terms of the n-th row are represented in the A010883(n-1) quadrant and the last 2*A003056(n) terms of the n-th row are represented in the A010883(n) quadrant.
.
Illustration of the spiral constructed with the first 15.5 rows of triangle:
.
.               12 _ _ _ _ _ _ _ _
.                 |  _ _ _ _ _ _ _|_ _ _ _ _ _ _ 7
.                 | |             |_ _ _ _ _ _ _|
.                _| |                           |
.               |_ _|9 _ _ _ _ _ _              |_ _
.         12 _ _|     |  _ _ _ _ _|_ _ _ _ _ 5      |_
.      _ _ _| |      _| |         |_ _ _ _ _|         |
.     |  _ _ _|  9 _|_ _|                   |_ _ 3    |_ _ _ 7
.     | |      _ _| |   12 _ _ _ _          |_  |         | |
.     | |     |  _ _|    _|  _ _ _|_ _ _ 3    |_|_ _ 5    | |
.     | |     | |      _|   |     |_ _ _|         | |     | |
.     | |     | |     |  _ _|           |_ _ 3    | |     | |
.     | |     | |     | |    3 _ _        | |     | |     | |
.     | |     | |     | |     |  _|_ 1    | |     | |     | |
.    _|_|    _|_|    _|_|    _|_| |_|    _|_|    _|_|    _|_|    _
.   | |     | |     | |     | |         | |     | |     | |     | |
.   | |     | |     | |     |_|_ _     _| |     | |     | |     | |
.   | |     | |     | |    2  |_ _|_ _|  _|     | |     | |     | |
.   | |     | |     |_|_     2    |_ _ _|    _ _| |     | |     | |
.   | |     | |    4    |_               7 _|  _ _|     | |     | |
.   | |     |_|_ _        |_ _ _ _        |  _|    _ _ _| |     | |
.   | |    6      |_      |_ _ _ _|_ _ _ _| |    _|    _ _|     | |
.   |_|_ _ _        |_   4        |_ _ _ _ _|  _|     |    _ _ _| |
.  8      | |_ _      |                     15|      _|   |  _ _ _|
.         |_    |     |_ _ _ _ _ _            |  _ _|    _| |
.        8  |_  |_    |_ _ _ _ _ _|_ _ _ _ _ _| |      _|  _|
.             |_ _|  6            |_ _ _ _ _ _ _|  _ _|  _|
.                 |                             28|  _ _|
.                 |_ _ _ _ _ _ _ _                | |
.                 |_ _ _ _ _ _ _ _|_ _ _ _ _ _ _ _| |
.                8                |_ _ _ _ _ _ _ _ _|
.                                                    31
.
The diagram contains A237590(16) = 27 parts.
The total area (also the total number of cells) in the n-th arm of the spiral is equal to sigma(n) = A000203(n), considering every quadrant and the axes x and y. (checked by hand up to row n = 128). The parts of the spiral are in A237270: 1, 3, 2, 2, 7...
Diagram extended by _Omar E. Pol_, Aug 23 2018
		

Crossrefs

Row n has length 4*A003056(n).
The sum of row n is equal to 4*n = A008586(n).
Row n is a palindromic composition of 4*n = A008586(n).
Both column 1 and right border are A008619, n >= 1.
The connection between A196020 and A237270 is as follows: A196020 --> A236104 --> A235791 --> A237591 --> A237593 --> this sequence --> A237270.

A239934 Triangle read by rows in which row n lists the parts of the symmetric representation of sigma(4n).

Original entry on oeis.org

7, 15, 28, 31, 42, 60, 56, 63, 91, 90, 42, 42, 124, 49, 49, 120, 168, 127, 63, 63, 195, 70, 70, 186, 224, 180, 84, 84, 252, 217, 210, 280, 248, 105, 105, 360, 112, 112, 255
Offset: 1

Views

Author

Omar E. Pol, Mar 29 2014

Keywords

Comments

Row n is a palindromic composition of sigma(4n).
Row n is also the row 4n of A237270.
Row n has length A237271(4n).
Row sums give A193553.
First differs from A193553 at a(11).
Also row n lists the parts of the symmetric representation of sigma in the n-th arm of the fourth quadrant of the spiral described in A239660, see example.
For the parts of the symmetric representation of sigma(4n-3), see A239931.
For the parts of the symmetric representation of sigma(4n-2), see A239932.
For the parts of the symmetric representation of sigma(4n-1), see A239933.
We can find the spiral (mentioned above) on the terraces of the pyramid described in A244050. - Omar E. Pol, Dec 06 2016

Examples

			The irregular triangle begins:
    7;
   15;
   28;
   31;
   42;
   60;
   56;
   63;
   91;
   90;
   42, 42;
  124;
   49, 49;
  120;
  168;
  ...
Illustration of initial terms in the fourth quadrant of the spiral described in A239660:
.
.           7       15      28      31      42      60      56      63
.           _       _       _       _       _       _       _       _
.          | |     | |     | |     | |     | |     | |     | |     | |
.         _| |     | |     | |     | |     | |     | |     | |     | |
.     _ _|  _|     | |     | |     | |     | |     | |     | |     | |
.    |_ _ _|    _ _| |     | |     | |     | |     | |     | |     | |
.             _|  _ _|     | |     | |     | |     | |     | |     | |
.            |  _|    _ _ _| |     | |     | |     | |     | |     | |
.     _ _ _ _| |    _|    _ _|     | |     | |     | |     | |     | |
.    |_ _ _ _ _|  _|     |    _ _ _| |     | |     | |     | |     | |
.                |      _|   |  _ _ _|     | |     | |     | |     | |
.                |  _ _|    _| |    _ _ _ _| |     | |     | |     | |
.     _ _ _ _ _ _| |      _|  _|   |  _ _ _ _|     | |     | |     | |
.    |_ _ _ _ _ _ _|  _ _|  _|  _ _| |    _ _ _ _ _| |     | |     | |
.                    |  _ _|  _|    _|   |    _ _ _ _|     | |     | |
.                    | |     |     |  _ _|   |    _ _ _ _ _| |     | |
.     _ _ _ _ _ _ _ _| |  _ _|  _ _|_|       |   |  _ _ _ _ _|     | |
.    |_ _ _ _ _ _ _ _ _| |  _ _|  _|      _ _|   | |    _ _ _ _ _ _| |
.                        | |     |      _|    _ _| |   |  _ _ _ _ _ _|
.                        | |  _ _|    _|  _ _|  _ _|   | |
.     _ _ _ _ _ _ _ _ _ _| | |       |   |    _|    _ _| |
.    |_ _ _ _ _ _ _ _ _ _ _| |  _ _ _|  _|  _|     |  _ _|
.                            | |       |  _|      _| |
.                            | |  _ _ _| |      _|  _|
.     _ _ _ _ _ _ _ _ _ _ _ _| | |  _ _ _|  _ _|  _|
.    |_ _ _ _ _ _ _ _ _ _ _ _ _| | |       |  _ _|
.                                | |  _ _ _| |
.                                | | |  _ _ _|
.     _ _ _ _ _ _ _ _ _ _ _ _ _ _| | | |
.    |_ _ _ _ _ _ _ _ _ _ _ _ _ _ _| | |
.                                    | |
.                                    | |
.     _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _| |
.    |_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _|
.
For n = 7 we have that 4*7 = 28 and the 28th row of A237593 is [15, 5, 3, 2, 1, 1, 1, 1, 1, 1, 2, 3, 5, 15] and the 27th row of A237593 is [14, 5, 3, 2, 1, 2, 2, 1, 2, 3, 5, 14] therefore between both Dyck paths there are only one region (or part) of size 56, so row 7 is 56.
The sum of divisors of 28 is 1 + 2 + 4 + 7 + 14 + 28 = A000203(28) = 56. On the other hand the sum of the parts of the symmetric representation of sigma(28) is 56, equaling the sum of divisors of 28.
For n = 11 we have that 4*11 = 44 and the 44th row of A237593 is [23, 8, 4, 3, 2, 1, 1, 2, 2, 1, 1, 2, 3, 4, 8, 23] and the 43rd row of A237593 is [22, 8, 4, 3, 2, 1, 2, 1, 1, 2, 1, 2, 3, 4, 8, 23] therefore between both Dyck paths there are two regions (or parts) of sizes [42, 42], so row 11 is [42, 42].
The sum of divisors of 44 is 1 + 2 + 4 + 11 + 22 + 44 = A000203(44) = 84. On the other hand the sum of the parts of the symmetric representation of sigma(44) is 42 + 42 = 84, equaling the sum of divisors of 44.
		

Crossrefs

A062731 Sum of divisors of 2*n.

Original entry on oeis.org

3, 7, 12, 15, 18, 28, 24, 31, 39, 42, 36, 60, 42, 56, 72, 63, 54, 91, 60, 90, 96, 84, 72, 124, 93, 98, 120, 120, 90, 168, 96, 127, 144, 126, 144, 195, 114, 140, 168, 186, 126, 224, 132, 180, 234, 168, 144, 252, 171, 217, 216, 210, 162, 280, 216, 248, 240, 210
Offset: 1

Views

Author

Jason Earls, Jul 11 2001

Keywords

Comments

a(n) is also the total number of parts in all partitions of 2*n into equal parts. - Omar E. Pol, Feb 14 2021

Crossrefs

Sigma(k*n): A000203 (k=1), A144613 (k=3), A193553 (k=4, even bisection), A283118 (k=5), A224613 (k=6), A283078 (k=7), A283122 (k=8), A283123 (k=9).
Cf. A008438, A074400, A182818, A239052 (odd bisection), A326124 (partial sums), A054784, A215947, A336923, A346870, A346878, A346880, A355750.
Row 2 of A319526. Column & Row 2 of A216626. Row 1 of A355927.
Shallow diagonal (2n,n) of A265652. See also A244658.

Programs

Formula

a(n) = A000203(2*n). - R. J. Mathar, Apr 06 2011
a(n) = A000203(n) + A054785(n). - R. J. Mathar, May 19 2020
From Vaclav Kotesovec, Aug 07 2022: (Start)
Dirichlet g.f.: zeta(s) * zeta(s-1) * (3 - 2^(1-s)).
Sum_{k=1..n} a(k) ~ 5 * Pi^2 * n^2 / 24. (End)
From Miles Wilson, Sep 30 2024: (Start)
G.f.: Sum_{k>=1} k*x^(k/gcd(k, 2))/(1 - x^(k/gcd(k, 2))).
G.f.: Sum_{k>=1} k*x^(2*k/(3 + (-1)^k))/(1 - x^(2*k/(3 + (-1)^k))). (End)

Extensions

Zero removed and offset corrected by Omar E. Pol, Jul 17 2009

A224613 a(n) = sigma(6*n).

Original entry on oeis.org

12, 28, 39, 60, 72, 91, 96, 124, 120, 168, 144, 195, 168, 224, 234, 252, 216, 280, 240, 360, 312, 336, 288, 403, 372, 392, 363, 480, 360, 546, 384, 508, 468, 504, 576, 600, 456, 560, 546, 744, 504, 728, 528, 720, 720, 672, 576, 819, 684, 868, 702, 840, 648
Offset: 1

Views

Author

Zak Seidov, Apr 22 2013

Keywords

Comments

Conjectures: sigma(6n) > sigma(6n - 1) and sigma(6n) > sigma(6n + 1).
Conjectures are false. Try prime 73961483429 for n. One finds sigma(6*73961483429) < sigma(6*73961483429+1). The number n = 105851369791 provides a counterexample for the other case. - T. D. Noe, Apr 22 2013
Sum of the divisors of the numbers k which have the property that the width associated to the vertex of the first (also the last) valley of the smallest Dyck path of the symmetric representation of sigma(k) is equal to 2 (see example). Other positive integers have width 0 or 1 associated to the mentioned valley. - Omar E. Pol, Aug 11 2021

Examples

			From _Omar E. Pol_, Aug 11 2021: (Start)
Illustration of initial terms:
----------------------------------------------------------------------
   n    6*n   a(n)    Diagram:  1           2           3           4
----------------------------------------------------------------------
                                _           _           _           _
                               | |         | |         | |         | |
                               | |         | |         | |         | |
                          * _ _| |         | |         | |         | |
                           |  _ _|         | |         | |         | |
                      _ _ _| |_|           | |         | |         | |
   1     6     12    |_ _ _ _|      * _ _ _| |         | |         | |
                                    _|  _ _ _|         | |         | |
                                * _|  _| |             | |         | |
                                 |  _|  _|    * _ _ _ _| |         | |
                                 | |_ _|       |  _ _ _ _|         | |
                      _ _ _ _ _ _| |          _| | |               | |
   2    12     28    |_ _ _ _ _ _ _|        _|  _|_|    * _ _ _ _ _| |
                                      * _ _|  _|         |  _ _ _ _ _|
                                       |  _ _|        _ _| | |
                                       | |_ _|      _|  _ _| |
                                       | |        _|  _|  _ _|
                      _ _ _ _ _ _ _ _ _| |       |  _|  _|
   3    18     39    |_ _ _ _ _ _ _ _ _ _|  * _ _| |  _|
                                             |  _ _| |
                                             | |_ _ _|
                                             | |
                                             | |
                      _ _ _ _ _ _ _ _ _ _ _ _| |
   4    24     60    |_ _ _ _ _ _ _ _ _ _ _ _ _|
.
Note that the mentioned vertices are aligned on two straight lines that meet at point (3,3).
a(n) equals the area (also the number of cells) in the n-th diagram. (End)
		

Crossrefs

Sigma(k*n): A000203 (k=1), A062731 (k=2), A144613 (k=3), A193553 (k=4), A283118 (k=5), this sequence (k=6), A283078 (k=7), A283122 (k=8), A283123 (k=9).
Cf. A000203 (sigma(n)), A053224 (n: sigma(n) < sigma(n+1)).
Cf. A067825 (even n: sigma(n)< sigma(n+1)).

Programs

  • Mathematica
    DivisorSigma[1,6*Range[60]] (* Harvey P. Dale, Apr 16 2016 *)
  • PARI
    a(n)=sigma(6*n) \\ Charles R Greathouse IV, Apr 22 2013
    
  • Python
    from sympy import divisor_sigma
    def a(n):  return divisor_sigma(6*n)
    print([a(n) for n in range(1, 54)]) # Michael S. Branicky, Dec 28 2021
    
  • Python
    from math import prod
    from collections import Counter
    from sympy import factorint
    def A224613(n): return prod((p**(e+1)-1)//(p-1) for p, e in (Counter(factorint(n))+Counter([2,3])).items()) # Chai Wah Wu, Sep 07 2023

Formula

a(n) = A000203(6n).
a(n) = A000203(A008588(n)). - Omar E. Pol, Aug 11 2021
Sum_{k=1..n} a(k) = (55*Pi^2/72) * n^2 + O(n*log(n)). - Amiram Eldar, Dec 16 2022

Extensions

Corrected by Harvey P. Dale, Apr 16 2016

A239050 a(n) = 4*sigma(n).

Original entry on oeis.org

4, 12, 16, 28, 24, 48, 32, 60, 52, 72, 48, 112, 56, 96, 96, 124, 72, 156, 80, 168, 128, 144, 96, 240, 124, 168, 160, 224, 120, 288, 128, 252, 192, 216, 192, 364, 152, 240, 224, 360, 168, 384, 176, 336, 312, 288, 192, 496, 228, 372, 288, 392, 216, 480, 288, 480, 320, 360, 240, 672, 248, 384, 416, 508
Offset: 1

Views

Author

Omar E. Pol, Mar 09 2014

Keywords

Comments

4 times the sum of divisors of n.
a(n) is also the total number of horizontal cells in the terraces of the n-th level of an irregular stepped pyramid (starting from the top) where the structure of every three-dimensional quadrant arises after the 90-degree zig-zag folding of every row of the diagram of the isosceles triangle A237593. The top of the pyramid is a square formed by four cells (see links and examples). - Omar E. Pol, Jul 04 2016

Examples

			For n = 4 the sum of divisors of 4 is 1 + 2 + 4 = 7, so a(4) = 4*7 = 28.
For n = 5 the sum of divisors of 5 is 1 + 5 = 6, so a(5) = 4*6 = 24.
.
Illustration of initial terms:                                    _ _ _ _ _ _
.                                           _ _ _ _ _ _          |_|_|_|_|_|_|
.                           _ _ _ _       _|_|_|_|_|_|_|_     _ _|           |_ _
.             _ _ _ _     _|_|_|_|_|_    |_|_|       |_|_|   |_|               |_|
.     _ _    |_|_|_|_|   |_|       |_|   |_|           |_|   |_|               |_|
.    |_|_|   |_|   |_|   |_|       |_|   |_|           |_|   |_|               |_|
.    |_|_|   |_|_ _|_|   |_|       |_|   |_|           |_|   |_|               |_|
.            |_|_|_|_|   |_|_ _ _ _|_|   |_|_         _|_|   |_|               |_|
.                          |_|_|_|_|     |_|_|_ _ _ _|_|_|   |_|_             _|_|
.                                          |_|_|_|_|_|_|         |_ _ _ _ _ _|
.                                                                |_|_|_|_|_|_|
.
n:     1          2             3                4                     5
S(n):  1          3             4                7                     6
a(n):  4         12            16               28                    24
.
For n = 1..5, the figure n represents the reflection in the four quadrants of the symmetric representation of S(n) = sigma(n) = A000203(n). For more information see A237270 and A237593.
The diagram also represents the top view of the first four terraces of the stepped pyramid described in Comments section. - _Omar E. Pol_, Jul 04 2016
		

Crossrefs

Alternating row sums of A239662.
Partial sums give A243980.
k times sigma(n), k=1..6: A000203, A074400, A272027, this sequence, A274535, A274536.
k times sigma(n), k = 1..10: A000203, A074400, A272027, this sequence, A274535, A274536, A319527, A319528, A325299, A326122.

Programs

  • Magma
    [4*SumOfDivisors(n): n in [1..70]]; // Vincenzo Librandi, Jul 30 2019
  • Maple
    with(numtheory): seq(4*sigma(n), n=1..64); # Omar E. Pol, Jul 04 2016
  • Mathematica
    Array[4 DivisorSigma[1, #] &, 64] (* Michael De Vlieger, Nov 16 2017 *)
  • PARI
    a(n) = 4 * sigma(n); \\ Omar E. Pol, Jul 04 2016
    

Formula

a(n) = 4*A000203(n) = 2*A074400(n).
a(n) = A000203(n) + A272027(n). - Omar E. Pol, Jul 04 2016
Dirichlet g.f.: 4*zeta(s-1)*zeta(s). - Ilya Gutkovskiy, Jul 04 2016
Conjecture: a(n) = sigma(3*n) = A144613(n) iff n is not a multiple of 3. - Omar E. Pol, Oct 02 2018
The conjecture above is correct. Write n = 3^e*m, gcd(3, m) = 1, then sigma(3*n) = sigma(3^(e+1))*sigma(m) = ((3^(e+2) - 1)/2)*sigma(m) = ((3^(e+2) - 1)/(3^(e+1) - 1))*sigma(3^e*m), and (3^(e+2) - 1)/(3^(e+1) - 1) = 4 if and only if e = 0. - Jianing Song, Feb 03 2019

A144613 a(n) = sigma(3*n) = A000203(3*n).

Original entry on oeis.org

4, 12, 13, 28, 24, 39, 32, 60, 40, 72, 48, 91, 56, 96, 78, 124, 72, 120, 80, 168, 104, 144, 96, 195, 124, 168, 121, 224, 120, 234, 128, 252, 156, 216, 192, 280, 152, 240, 182, 360, 168, 312, 176, 336, 240, 288, 192, 403, 228, 372, 234, 392, 216, 363, 288, 480, 260, 360
Offset: 1

Views

Author

N. J. A. Sloane, Jan 15 2009

Keywords

Crossrefs

Sigma(k*n): A000203 (k=1), A062731 (k=2), this sequence (k=3), A193553 (k=4), A283118 (k=5), A224613 (k=6), A283078 (k=7), A283122 (k=8), A283123 (k=9).

Programs

  • Mathematica
    a[n_] := DivisorSigma[1, 3*n]; Array[a, 60] (* Amiram Eldar, Dec 16 2022 *)
  • PARI
    vector(66, n, sigma(3*n, 1)) \\ Joerg Arndt, Jul 30 2011

Formula

a(n) = A000203(n) + 3*A078708(n). - R. J. Mathar, May 19 2020
Sum_{k=1..n} a(k) = (11*Pi^2/36) * n^2 + O(n*log(n)). - Amiram Eldar, Dec 16 2022

Extensions

Zero removed and offset corrected by Seiichi Manyama, Feb 28 2017

A112610 Number of representations of n as a sum of two squares and two triangular numbers.

Original entry on oeis.org

1, 6, 13, 14, 18, 32, 31, 30, 48, 38, 42, 78, 57, 54, 80, 62, 84, 96, 74, 96, 121, 108, 90, 128, 98, 102, 192, 110, 114, 182, 133, 156, 176, 160, 138, 192, 180, 150, 234, 158, 192, 288, 183, 174, 240, 182, 228, 320, 194, 198, 272, 252, 240, 288, 256, 252, 403, 230
Offset: 0

Views

Author

James Sellers, Dec 21 2005

Keywords

Comments

Also row sums of A239931, hence the sequence has a symmetric representation. - Omar E. Pol, Aug 30 2015

Examples

			a(1) = 6 since we can write 1 = 1^2 + 0^2 + 0 + 0 = (-1)^2 + 0^2 + 0 + 0 = 0^2 + 1^2 + 0 + 0 = 0^2 + (-1)^2 + 0 + 0 = 0^2 + 0^2 + 1 + 0 = 0^2 + 0^2 + 0 + 1
		

Crossrefs

Programs

  • Magma
    [DivisorSigma(1, 4*n+1): n in [0..60]]; // Vincenzo Librandi, Sep 18 2015
  • Mathematica
    Table[DivisorSigma[1, 4 n + 1], {n, 0, 57}] (* Michael De Vlieger, Aug 31 2015 *)
  • PARI
    {a(n)=local(A); if(n<0, 0, A=x*O(x^n); polcoeff( eta(x^2+A)^14/eta(x+A)^6/eta(x^4+A)^4, n))} /* Michael Somos, Jul 04 2006 */
    

Formula

a(n) = sigma(4n+1) where sigma(n) = A000203(n) is the sum of the divisors of n.
Euler transform of period 4 sequence [ 6, -8, 6, -4, ...]. - Michael Somos, Jul 04 2006
Expansion of q^(-1/4)eta^14(q^2)/(eta^6(q)eta^4(q^4)) in powers of q. - Michael Somos, Jul 04 2006
Expansion of psi(q)^2*phi(q)^2, i.e., convolution of A004018 and A008441 [Hirschhorn]. - R. J. Mathar, Mar 24 2011
Sum_{k=0..n} a(k) = (Pi^2/4) * n^2 + O(n*log(n)). - Amiram Eldar, Dec 17 2022

A283078 a(n) = sigma(7*n).

Original entry on oeis.org

8, 24, 32, 56, 48, 96, 57, 120, 104, 144, 96, 224, 112, 171, 192, 248, 144, 312, 160, 336, 228, 288, 192, 480, 248, 336, 320, 399, 240, 576, 256, 504, 384, 432, 342, 728, 304, 480, 448, 720, 336, 684, 352, 672, 624, 576, 384, 992, 400, 744, 576, 784, 432, 960
Offset: 1

Views

Author

Seiichi Manyama, Feb 28 2017

Keywords

Examples

			For n = 3, the divisors of 3*7 are {1, 3, 7, 21}. Now, 1 + 3 + 7 + 21 = 32. So, a(3) = 32. - _Indranil Ghosh_, Feb 28 2017
		

Crossrefs

Sigma(k*n): A000203 (k=1), A062731 (k=2), A144613 (k=3), A193553 (k=4), A283118 (k=5), A224613 (k=6), this sequence (k=7), A283122 (k=8), A283123 (k=9).
Cf. A008589.

Programs

Formula

From Amiram Eldar, Dec 16 2022: (Start)
a(n) = A000203(7*n) = A000203(A008589(n)).
Sum_{k=1..n} a(k) = (55*Pi^2/84) * n^2 + O(n*log(n)). (End)

A283122 a(n) = sigma(8*n).

Original entry on oeis.org

15, 31, 60, 63, 90, 124, 120, 127, 195, 186, 180, 252, 210, 248, 360, 255, 270, 403, 300, 378, 480, 372, 360, 508, 465, 434, 600, 504, 450, 744, 480, 511, 720, 558, 720, 819, 570, 620, 840, 762, 630, 992, 660, 756, 1170, 744, 720, 1020, 855, 961
Offset: 1

Views

Author

Seiichi Manyama, Mar 01 2017

Keywords

Crossrefs

Sigma(k*n): A000203 (k=1), A062731 (k=2), A144613 (k=3), A193553 (k=4), A283118 (k=5), A224613 (k=6), A283078 (k=7), this sequence (k=8), A283123 (k=9).
Cf. A008590.

Programs

Formula

a(n) = A000203(8*n).
Sum_{k=1..n} a(k) = (23*Pi^2/24) * n^2 + O(n*log(n)). - Amiram Eldar, Dec 16 2022

A283123 a(n) = sigma(9*n).

Original entry on oeis.org

13, 39, 40, 91, 78, 120, 104, 195, 121, 234, 156, 280, 182, 312, 240, 403, 234, 363, 260, 546, 320, 468, 312, 600, 403, 546, 364, 728, 390, 720, 416, 819, 480, 702, 624, 847, 494, 780, 560, 1170, 546, 960, 572, 1092, 726, 936, 624, 1240, 741, 1209
Offset: 1

Views

Author

Seiichi Manyama, Mar 01 2017

Keywords

Comments

In general, for k>=1, Sum_{j=1..n} sigma(j*k) ~ A069097(k) * Pi^2 * n^2 / (12*k). - Vaclav Kotesovec, May 11 2024

Crossrefs

Sigma(k*n): A000203 (k=1), A062731 (k=2), A144613 (k=3), A193553 (k=4), A283118 (k=5), A224613 (k=6), A283078 (k=7), A283122 (k=8), this sequence (k=9).
Cf. A008591.

Programs

Formula

a(n) = A000203(9*n).
Sum_{k=1..n} a(k) = (35*Pi^2/36) * n^2 + O(n*log(n)). - Amiram Eldar, Dec 16 2022
Showing 1-10 of 21 results. Next