cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A014410 Elements in Pascal's triangle (by row) that are not 1.

Original entry on oeis.org

2, 3, 3, 4, 6, 4, 5, 10, 10, 5, 6, 15, 20, 15, 6, 7, 21, 35, 35, 21, 7, 8, 28, 56, 70, 56, 28, 8, 9, 36, 84, 126, 126, 84, 36, 9, 10, 45, 120, 210, 252, 210, 120, 45, 10, 11, 55, 165, 330, 462, 462, 330, 165, 55, 11, 12, 66, 220, 495, 792, 924, 792, 495, 220, 66, 12, 13, 78
Offset: 2

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Author

Keywords

Comments

Also, rows of triangle formed using Pascal's rule except begin and end n-th row with n+2. - Asher Auel.
Row sums are A000918. - Roger L. Bagula and Gary W. Adamson, Jan 15 2009
Given the triangle signed by rows (+ - + ...) = M, with V = a variant of the Bernoulli numbers starting [1/2, 1/6, 0, -1/30, 0, 1/42, ...]; M*V = [1, 1, 1, ...]. - Gary W. Adamson, Mar 05 2012
Also A014410 * [1/2, 1/6, 0, -1/30, 0, 1/42, 0, ...] = [1, 2, 3, 4, ...]. For an alternative way to derive the Bernoulli numbers from a modified version of Pascal's triangle see A135225. - Peter Bala, Dec 18 2014
T(n,k) mod n = A053201(n,k), k=1..n-1. - Reinhard Zumkeller, Aug 17 2013
From Wolfdieter Lang, May 22 2015: (Start)
This is Johannes Scheubel's (1494-1570) (also Scheybl, Schöblin) version of the arithmetical triangle from his 1545 book "De numeris et diversis rationibus". See the Kac reference, p. 396 and the Table 12.1 on p. 395.
The row sums give 2*A000225(n-1) = A000918(n) = 2*(2^n - 1), n >= 2. (See the second comment above).
The alternating row sums give repeat(2,0) = 2*A059841(n), n >= 2. (End)
T(n+1,k) is the number of k-facets of the n-simplex. - Jianing Song, Oct 22 2023

Examples

			The triangle T(n,k) begins:
n\k  1  2   3   4    5    6    7    8   9  10 11
2:   2
3:   3  3
4:   4  6   4
5:   5 10  10   5
6:   6 15  20  15    6
7:   7 21  35  35   21    7
8:   8 28  56  70   56   28    8
9:   9 36  84 126  126   84   36    9
10: 10 45 120 210  252  210  120   45  10
11: 11 55 165 330  462  462  330  165  55  11
12: 12 66 220 495  792  924  792  495 220  66 12
... reformatted. - _Wolfdieter Lang_, May 22 2015
		

References

  • Victor J. Kac, A History of Mathematics, third edition, Addison-Wesley, 2009, pp. 395, 396.

Crossrefs

A180986 is the same sequence but regarded as a square array.
Cf. A000225,A059841, A257241 (Stifel's version).

Programs

  • Haskell
    a014410 n k = a014410_tabl !! (n-2) !! (k-1)
    a014410_row n = a014410_tabl !! (n-2)
    a014410_tabl = map (init . tail) $ drop 2 a007318_tabl
    -- Reinhard Zumkeller, Mar 12 2012
  • Maple
    for i from 0 to 12 do seq(binomial(i, j)*1^(i-j), j = 1 .. i-1) od; # Zerinvary Lajos, Dec 02 2007
  • Mathematica
    Select[ Flatten[ Table[ Binomial[ n, i ], {n, 0, 13}, {i, 0, n} ] ], #>1& ]

Formula

T(n,k) = binomial(n,k) = A007318(n,k), n >= 2, k = 1, 2, ..., n-1.
a(n) = C(A003057(n),A002260(n)) = C(A003057(n),A004736(n)). - Lekraj Beedassy, Jul 29 2006
T(n,k) = A028263(n,k) - A007318(n,k). - Reinhard Zumkeller, Mar 12 2012
gcd_{k=1..n-1} T(n, k) = A014963(n), see Theorem 1 of McTague link. - Michel Marcus, Oct 23 2015

Extensions

More terms from Erich Friedman

A119741 A008279, with the first and last of each row removed.

Original entry on oeis.org

2, 3, 6, 4, 12, 24, 5, 20, 60, 120, 6, 30, 120, 360, 720, 7, 42, 210, 840, 2520, 5040, 8, 56, 336, 1680, 6720, 20160, 40320, 9, 72, 504, 3024, 15120, 60480, 181440, 362880, 10, 90, 720, 5040, 30240, 151200, 604800, 1814400, 3628800, 11, 110, 990, 7920, 55440, 332640, 1663200, 6652800, 19958400, 39916800
Offset: 2

Views

Author

Lekraj Beedassy, Jul 29 2006

Keywords

Comments

Triangle read by rows: T(n,k) (n>=2, k=1..n-1) is the number of topologies t on n points having exactly k+2 open sets such that t contains exactly one open set of size m for each m in {0,1,2,...,s,n} where s is the size of the largest proper open set in t. - N. J. A. Sloane, Jan 29 2016 [clarified by Geoffrey Critzer, Feb 19 2017]

Examples

			Triangle begins:
   2;
   3,  6;
   4, 12,  24;
   5, 20,  60,  120;
   6, 30, 120,  360,   720;
   7, 42, 210,  840,  2520,   5040;
   8, 56, 336, 1680,  6720,  20160,  40320;
   9, 72, 504, 3024, 15120,  60480, 181440,  362880;
  10, 90, 720, 5040, 30240, 151200, 604800, 1814400, 3628800;
  ...
		

Crossrefs

Row sums give A038156.
Triangles in this series: A268216, A268217, A268221, A268222, A268223.

Programs

  • Maple
    T:= (n, k)-> n!/(n-k)!:
    seq(seq(T(n,k), k=1..n-1), n=2..11);  # Alois P. Heinz, Aug 22 2025
  • Mathematica
    Table[FactorialPower[n, k], {n, 2, 11}, {k, 1, n-1}] // Flatten (* Jean-François Alcover, Feb 21 2020 *)

Formula

a(n) = (A003057(n))!/(A004736(n))! = (A002260(n))!*(A014410(n)).
T(n,k) = A173333(n+1,n-k+1), 1<=k<=n. - Reinhard Zumkeller, Feb 19 2010

Extensions

Edited by Don Reble, Aug 01 2006

A349082 The number of two-term Egyptian fractions of rational numbers, x/y, 0 < x/y < 1, ordered as below. The sequence is the number of (p,q) pairs such that x/y = 1/p + 1/q where p and q are integers with p < q.

Original entry on oeis.org

1, 1, 1, 2, 1, 1, 1, 1, 1, 0, 4, 1, 1, 1, 1, 1, 1, 0, 1, 0, 0, 3, 2, 2, 1, 1, 1, 0, 2, 2, 1, 1, 1, 1, 0, 0, 4, 1, 2, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 7, 4, 2, 1, 2, 1, 2, 1, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 4, 1, 3, 1, 1, 0, 1, 1, 1, 0, 0, 0, 0, 4, 4, 1, 3, 1, 1, 0, 2, 1, 1, 0, 0, 0, 0, 4, 3, 2, 2, 1, 2, 0, 1, 1, 1, 0, 1, 0, 0, 0
Offset: 1

Views

Author

Jud McCranie, Nov 07 2021

Keywords

Comments

The sequence are the terms in a triangle, where the rows correspond to the denominator of the rational number (starting with row 2, column 1) and the columns correspond to the numerators:
x=1 2 3 4 5 rationals x/y:
Row 1 (y=2): 1 1/2
Row 2 (y=3): 1, 1 1/3, 2/3
Row 3 (y=4): 2, 1, 1 1/4, 2/4, 3/4
Row 4 (y=5): 1, 1, 1, 0 1/5, 2/5, 3/5, 4/5
Row 5 (y=6): 4, 1, 1, 1, 1 1/6, 2/6, 3/6, 4/6, 5/6
Alternatively, order the rational numbers, x/y, 0 < x/y < 1, in this order: 1/2, 1/3, 2/3, 1/4, 2/4, 3/4, 1/5, 2/5, ... For example, in this ordering, the sixth rational number is 3/4. The numerators of the n-th rational number are A002260(n) and the denominators are A003057(n).
A018892 is a subsequence (for x/y = 1/n).

Examples

			The fourth rational number is 1/4, 1/4 = 1/5 + 1/20 = 1/6 + 1/12, so a(4)=2.
		

Crossrefs

Columns: A018892 (x=1), A046079 (x=2).

A350361 2-tone chromatic number of a tree with maximum degree n.

Original entry on oeis.org

4, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 15, 15, 15, 15, 15
Offset: 1

Views

Author

Allan Bickle, Dec 26 2021

Keywords

Comments

The 2-tone chromatic number of a graph G is the smallest number of colors for which G has a coloring where every vertex has two distinct colors, no adjacent vertices have a common color, and no pair of vertices at distance 2 have two common colors.
a(n) is also the 2-tone chromatic number of a star with n leaves.

Examples

			For a star with three leaves, label the leaves 12, 13, and 23.  Label the other vertex 45.  A total of 5 colors are used, so a(3)=5.
		

Crossrefs

Programs

  • Mathematica
    Table[Ceiling[(5 + Sqrt[1 + 8*n])/2],{n,71}] (* Stefano Spezia, Dec 27 2021 *)

Formula

a(n) = A003057(n-1) + 2.
a(n) = ceiling((5 + sqrt(1 + 8*n))/2).

A351120 Pair chromatic number of a cycle graph with n vertices.

Original entry on oeis.org

6, 6, 5, 5, 6, 5, 5, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 14, 14, 14, 14
Offset: 3

Views

Author

Allan Bickle, Feb 01 2022

Keywords

Comments

The pair chromatic number of a graph G is the smallest number of colors for which G has a coloring where every vertex has two distinct colors, no adjacent vertices have a common color, and no pair of colors is repeated.
There is no pair 5-coloring for cycles of length 3, 4, 7, or 10 since the Petersen graph does not contain cycles of these lengths.

Examples

			The colorings for (broken) cycles with orders 3 through 9 are shown below.
  -12-34-56-
  -12-34-15-36-
  -12-34-51-23-45-
  -12-34-15-32-14-35-
  -12-34-56-13-24-35-46-
  -12-34-15-23-14-25-13-45-
  -12-34-15-32-14-25-13-24-35-
		

Crossrefs

Programs

  • Mathematica
    A351120[n_]:=If[n<11,{6,6,5,5,6,5,5,6}[[n-2]],Ceiling[(1+Sqrt[1+8n])/2]];Array[A351120,100,3] (* Paolo Xausa, Nov 30 2023 *)

Formula

a(n) = ceiling((1 + sqrt(1 + 8*n))/2) for n > 10.

A349090 Where zeros occur in A349082. These correspond to rationals, 0 < p/q < 1, that have no solution p/q = 1/x + 1/y, 0 < x < y.

Original entry on oeis.org

10, 18, 20, 21, 28, 35, 36, 44, 45, 50, 52, 53, 54, 55, 66, 69, 70, 71, 72, 74, 75, 76, 77, 78, 84, 88, 89, 90, 91, 98, 102, 103, 104, 105, 112, 116, 118, 119, 120, 124, 125, 127, 128, 130, 131, 132, 133, 134, 135, 136, 149, 150, 152, 153, 156, 159, 160, 161
Offset: 1

Views

Author

Jud McCranie, Dec 12 2021

Keywords

Comments

For index k, p/q = A002260(k)/A003057(k).

Examples

			10 is a term because A349082(10)=0, indicating that 4/5 = 1/x + 1/y has no solution.
		

Crossrefs

A350715 2-tone chromatic number of a wheel graph with n vertices.

Original entry on oeis.org

8, 8, 7, 7, 8, 7, 7, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 15, 15, 15, 15, 15
Offset: 4

Views

Author

Allan Bickle, Feb 02 2022

Keywords

Comments

The 2-tone chromatic number of a graph G is the smallest number of colors for which G has a coloring where every vertex has two distinct colors, no adjacent vertices have a common color, and no pair of vertices at distance 2 have two common colors.

Examples

			The central vertex always requires two distinct colors.  All vertices on the cycle require distinct pairs.
The colorings for small (broken) cycles are shown below.
  -12-34-56-
  -12-34-15-36-
  -12-34-51-23-45-
  -12-34-15-32-14-35-
  -12-34-56-13-24-35-46-
  -12-34-15-23-14-25-13-45-
  -12-34-15-32-14-25-13-24-35-
		

Crossrefs

Cf. A003057, A351120 (pair coloring).
Cf. A350361 (trees), A350362 (cycles), A350715 (wheels), A366727 (outerplanar), A366728 (square of cycles), A381562 (maximal planar), A381563 (double wheels).

Programs

  • Mathematica
    A350715[n_]:=If[n<12,{8,8,7,7,8,7,7,8}[[n-3]],Ceiling[(5+Sqrt[8n-7])/2]];Array[A350715,100,4] (* Paolo Xausa, Nov 30 2023 *)

Formula

a(n) = A351120(n-1) + 2
a(n) = ceiling((5 + sqrt(8*n - 7))/2) for n > 11.

A385882 Values of v in the (1,3)-quartals (m,u,v,w) having m=1; i.e., values of v for solutions to m^1 + u^3 = v^1 + w^3, in positive integers, with m

Original entry on oeis.org

8, 20, 27, 38, 57, 64, 62, 99, 118, 125, 92, 153, 190, 209, 216, 128, 219, 280, 317, 336, 343, 170, 297, 388, 449, 486, 505, 512, 218, 387, 514, 605, 666, 703, 722, 729, 272, 489, 658, 785, 876, 937, 974, 993, 1000, 332, 603, 820, 989, 1116, 1207, 1268, 1305
Offset: 1

Views

Author

Clark Kimberling, Jul 21 2025

Keywords

Comments

A 4-tuple (m,u,v,w) is a (p,q)-quartal if m,u,v,w are positive integers such that m

Examples

			First thirty (1,3)-quartals (1,u,v,w):
  m   u    v   w
  1   2    8   1
  1   3   20   2
  1   3   27   1
  1   4   38   3
  1   4   57   2
  1   4   64   1
  1   5   62   4
  1   5   99   3
  1   5  118   2
  1   5  125   1
  1   6   92   5
  1   6  153   4
  1   6  190   3
  1   6  209   2
  1   6  216   1
  1   7  128   6
  1   7  219   5
  1   7  280   4
  1   7  317   3
  1   7  336   2
  1   7  343   1
  1   8  170   7
  1   8  297   6
  1   8  388   5
  1   8  449   4
  1   8  486   3
  1   8  505   2
  1   8  512   1
  1   9  218   8
  1   9  387   7
1^1 + 4^3 = 57^1 + 2^3, so (1,4,57,2) is in the list.
		

Crossrefs

Guide to related sequences:
m | u | v | w
--+---------+---------+--------
--+---------+---------+---------

Programs

  • Mathematica
    quartals[m_, p_, q_, max_] := Module[{ans = {}, lhsD = <||>, lhs, v, u, w, rhs},
       For[u = 1, u <= max, u++, lhs = m^p + u^q;
        AssociateTo[lhsD, lhs -> Append[Lookup[lhsD, lhs, {}], u]];];
       For[v = m + 1, v <= max, v++,
        For[w = 1, w <= max, w++, rhs = v^p + w^q; If[KeyExistsQ[lhsD, rhs],
           Do[AppendTo[ans, {m, u, v, w}], {u, lhsD[rhs]}];];];];
       ans = SortBy[ans, #[[2]] &];
       Do[Print["Solution ", i, ": ", ans[[i]], " (", m, "^", p, " + ",
         ans[[i, 2]], "^", q, " = ", ans[[i, 3]], "^", p, " + ",
         ans[[i, 4]], "^", q, " = ", m^p + ans[[i, 2]]^q, ")"], {i,
         Length[ans]}]; ans];
    solns = quartals[1, 1, 3, 2000] (* Solutions restricted to v<2000 *)
    Grid[solns]
    u1 = Map[#[[2]] &, solns]   (*u, A003057 *)
    v1 = Map[#[[3]] &, solns]   (*v, A385882 *)
    w1 = Map[#[[4]] &, solns]   (*w, A004736 *)
    (* Peter J. C. Moses, Jun 20 2025 *)

A386215 Values of v in the (1,3)-quartals (m,u,v,w) having m=2; i.e., values of v for solutions to m + u^3 = v + w^3, in positive integers, with m

Original entry on oeis.org

9, 21, 28, 39, 58, 65, 63, 100, 119, 126, 93, 154, 191, 210, 217, 129, 220, 281, 318, 337, 344, 171, 298, 389, 450, 487, 506, 513, 219, 388, 515, 606, 667, 704, 723, 730, 273, 490, 659, 786, 877, 938, 975, 994, 1001, 333, 604, 821, 990, 1117, 1208, 1269
Offset: 1

Author

Clark Kimberling, Jul 22 2025

Keywords

Comments

A 4-tuple (m,u,v,w) is a (p,q)-quartal if m,u,v,w are positive integers such that m

Examples

			First thirty (1,3)-quartals (2,u,v,w):
  m     u      v     w
  2     2      9     1
  2     3     21     2
  2     3     28     1
  2     4     39     3
  2     4     58     2
  2     4     65     1
  2     5     63     4
  2     5    100     3
  2     5    119     2
  2     5    126     1
  2     6     93     5
  2     6    154     4
  2     6    191     3
  2     6    210     2
  2     6    217     1
  2     7    129     6
  2     7    220     5
  2     7    281     4
  2     7    318     3
  2     7    337     2
  2     7    344     1
  2     8    171     7
  2     8    298     6
  2     8    389     5
  2     8    450     4
  2     8    487     3
  2     8    506     2
  2     8    513     1
  2     9    219     8
  2     9    388     7
2^1 + 3^3 = 21^1 + 2^3, so (2,3,21,2) is in the list.
		

Crossrefs

Programs

  • Maple
    seq(seq(2 + u^3 - w^3, w = u-1 .. 1,-1),u=2..20); # Robert Israel, Jul 27 2025
  • Mathematica
    quartals[m_, p_, q_, max_] :=
      Module[{ans = {}, lhsD = <||>, lhs, v, u, w, rhs},
       For[u = 1, u <= max, u++, lhs = m^p + u^q;
        AssociateTo[lhsD, lhs -> Append[Lookup[lhsD, lhs, {}], u]];];
       For[v = m + 1, v <= max, v++,
        For[w = 1, w <= max, w++, rhs = v^p + w^q;
          If[KeyExistsQ[lhsD, rhs],
           Do[AppendTo[ans, {m, u, v, w}], {u, lhsD[rhs]}];];];];
       ans = SortBy[ans, #[[2]] &];
       Do[Print["Solution ", i, ": ", ans[[i]], " (", m, "^", p, " + ",
         ans[[i, 2]], "^", q, " = ", ans[[i, 3]], "^", p, " + ",
         ans[[i, 4]], "^", q, " = ", m^p + ans[[i, 2]]^q, ")"], {i,
         Length[ans]}]; ans];
    solns = quartals[2, 1, 3, 2000]  (* solutions restricted to v<2000 *)
    Grid[solns]
    u1 = Map[#[[2]] &, solns]  (*u, A003057 *)
    v1 = Map[#[[3]] &, solns]  (*v, A386215 *)
    w1 = Map[#[[4]] &, solns]  (*w, A004736 *)
    (* Peter J. C. Moses, Jun 20 2025 *)

Formula

a(n) = 2 + u^3 - (u*(u-1)/2 + 1 - n)^3 where u = floor((3+sqrt(8*n-7))/2). - Robert Israel, Jul 27 2025

A063929 Radius of A-excircle of Pythagorean triangle with a = (n+1)^2 - m^2, b = 2*(n+1)*m and c = (n+1)^2 + m^2.

Original entry on oeis.org

2, 6, 3, 12, 8, 4, 20, 15, 10, 5, 30, 24, 18, 12, 6, 42, 35, 28, 21, 14, 7, 56, 48, 40, 32, 24, 16, 8, 72, 63, 54, 45, 36, 27, 18, 9, 90, 80, 70, 60, 50, 40, 30, 20, 10, 110, 99, 88, 77, 66, 55, 44, 33, 22, 11, 132, 120, 108, 96, 84, 72, 60, 48, 36, 24, 12, 156, 143, 130, 117
Offset: 1

Author

Floor van Lamoen, Aug 21 2001

Keywords

Comments

From Wolfdieter Lang, Dec 03 2014: (Start)
For excircles and their radii see the Eric W. Weisstein links. Here the circle radius with center J_A is considered.
Note that not all Pythagorean triangles are covered, e.g., the nonprimitive one (9, 12, 15) does not appear. However, the nonprimitive one (8, 6, 10) does appear as (n, m) = (2, 1). (End)
This triangle T appears also in the problem of finding all positive integer solutions for a and b of the general Fibonacci sequence F(a,b;k+1) = a*F(a,b;k) + b*F(a,b;k-1) (with some inputs F(a,b;0) and F(a,b;1)) such that the limit r = r(a,b) = F(a,b;k+1)/F(a,b;k) for k -> infinity becomes a positive integer r = (a + sqrt(a^2 + 4*b))/2. Namely, for any a = m >= 1 there are infinitely many b solutions b = T(n,m) = (n+1)*(n+1-m) for n >= m. The limit is r(a,b) = n+1 for a = m = 1..n, which is A003057 read as a triangle with offset 1. This entry was motivated by A249973 and A249974 by Kerry Mitchell concerned with real values of r. - Wolfdieter Lang, Jan 11 2015

Examples

			The triangle T(n, m) begins:
n\m   1   2   3   4   5   6   7   8   9 10 11 12 13 14 15 ...
1:    2
2:    6   3
3:   12   8   4
4:   20  15  10  5
5:   30  24  18  12   6
6:   42  35  28  21  14   7
7:   56  48  40  32  24  16   8
8:   72  63  54  45  36  27  18   9
9:   90  80  70  60  50  40  30  20  10
10: 110  99  88  77  66  55  44  33  22 11
11: 132 120 108  96  84  72  60  48  36 24 12
12: 156 143 130 117 104  91  78  65  52 39 26 13
13: 182 168 154 140 126 112  98  84  70 56 42 28 14
14: 210 195 180 165 150 135 120 105  90 75 60 45 30 15
15: 240 224 208 192 176 160 144 128 112 96 80 64 48 32  1
... Formatted and extended by _Wolfdieter Lang_, Dec 02 2014
--------------------------------------------------------------
Example of general (a,b)-Fibonacci sequence positive integer limits r(a,b) (see the Jan 11 2015 comment above):
T(3, 2) = 8, that is a = m = 2 has a solution b = T(3, 2) = 8 with r = r(2,8) = n+1 = 4 = (2 + sqrt(4 + 4*8))/2. The other two solutions with r = 4 appear for b = T(3, m) with m = a = 1 and 3. In general, row n has n times the value n+1 for r, namely r(a=m,b=T(n,m)) = n+1, for m = 1..n. - _Wolfdieter Lang_, Jan 11 2015
		

Crossrefs

Cf. A003991 (incircle radius), A063930 (B-excircle radius), A001283 (C-excircle radius), A055096 (circumcircle diameter).

Formula

T(n, m) = (n+1)(n-m+1), n >= m >= 1.
T(n, m) = rho_A = sqrt(s*(s-b)*(s-c)/(s-a)) with the semiperimeter s = (a + b + c)/2 and the substituted a, b, c values as given in the name. - Wolfdieter Lang, Dec 02 2014

Extensions

Edited: Crossreferences commented and A055096 added by Wolfdieter Lang, Dec 02 2014
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