cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A027871 a(n) = Product_{i=1..n} (3^i - 1).

Original entry on oeis.org

1, 2, 16, 416, 33280, 8053760, 5863137280, 12816818094080, 84078326697164800, 1654829626053597593600, 97714379759212830706892800, 17309711516825516108403231948800
Offset: 0

Views

Author

Keywords

Comments

2*(10)^m|a(n) where 4*m <= n <= 4*m+3 for m >= 1. - G. C. Greubel, Nov 20 2015
Given probability p = 1/3^n that an outcome will occur at the n-th stage of an infinite process, then starting at n=1, 1-a(n)/A047656(n+1) is the probability that the outcome has occurred at or before the n-th iteration. The limiting ratio is 1-A100220 ~ 0.4398739. - Bob Selcoe, Mar 01 2016

Crossrefs

Cf. A005329 (q=2), A027637 (q=4), A027872 (q=5), A027873 (q=6), A027875 (q=7), A027876 (q=8), A027877 (q=9), A027878 (q=10), A027879 (q=11), A027880 (q=12).

Programs

Formula

a(n) ~ c * 3^(n*(n+1)/2), where c = A100220 = Product_{k>=1} (1-1/3^k) = 0.560126077927948944969792243314140014379736333798... . - Vaclav Kotesovec, Nov 21 2015
a(n) = 3^(binomial(n+1,2))*(1/3;1/3){n}, where (a;q){n} is the q-Pochhammer symbol. - G. C. Greubel, Dec 24 2015
a(n) = Product_{i=1..n} A024023(i). - Michel Marcus, Dec 27 2015
G.f.: Sum_{n>=0} 3^(n*(n+1)/2)*x^n / Product_{k=0..n} (1 + 3^k*x). - Ilya Gutkovskiy, May 22 2017
From Amiram Eldar, Feb 19 2022: (Start)
Sum_{n>=0} 1/a(n) = A132324.
Sum_{n>=0} (-1)^n/a(n) = A100220. (End)

A059379 Array of values of Jordan function J_k(n) read by antidiagonals (version 1).

Original entry on oeis.org

1, 1, 1, 2, 3, 1, 2, 8, 7, 1, 4, 12, 26, 15, 1, 2, 24, 56, 80, 31, 1, 6, 24, 124, 240, 242, 63, 1, 4, 48, 182, 624, 992, 728, 127, 1, 6, 48, 342, 1200, 3124, 4032, 2186, 255, 1, 4, 72, 448, 2400, 7502, 15624, 16256, 6560, 511, 1, 10, 72, 702, 3840
Offset: 1

Views

Author

N. J. A. Sloane, Jan 28 2001

Keywords

Examples

			Array begins:
  1,  1,  2,   2,   4,    2,    6,    4,   6,  4, 10, 4, ...
  1,  3,  8,  12,  24,   24,   48,   48,  72, 72, ...
  1,  7, 26,  56, 124,  182,  342,  448, 702, ...
  1, 15, 80, 240, 624, 1200, 2400, 3840, ...
		

References

  • Louis Comtet, Advanced Combinatorics, Reidel, 1974, p. 199, #3.
  • R. Sivaramakrishnan, "The many facets of Euler's totient. II. Generalizations and analogues", Nieuw Arch. Wisk. (4) 8 (1990), no. 2, 169-187.

Crossrefs

See A059379 and A059380 (triangle of values of J_k(n)), A000010 (J_1), A059376 (J_3), A059377 (J_4), A059378 (J_5). Columns give A000225, A024023, A020522, A024049, A059387, etc.
Main diagonal gives A067858.

Programs

  • Maple
    J := proc(n,k) local i,p,t1,t2; t1 := n^k; for p from 1 to n do if isprime(p) and n mod p = 0 then t1 := t1*(1-p^(-k)); fi; od; t1; end;
    #alternative
    A059379 := proc(n,k)
        add(d^k*numtheory[mobius](n/d),d=numtheory[divisors](n)) ;
    end proc:
    seq(seq(A059379(d-k,k),k=1..d-1),d=2..12) ; # R. J. Mathar, Nov 23 2018
  • Mathematica
    JordanTotient[n_,k_:1]:=DivisorSum[n,#^k*MoebiusMu[n/#]&]/;(n>0)&&IntegerQ[n];
    A004736[n_]:=Binomial[Floor[3/2+Sqrt[2*n]],2]-n+1;
    A002260[n_]:=n-Binomial[Floor[1/2+Sqrt[2*n]],2];
    A059379[n_]:=JordanTotient[A004736[n],A002260[n]]; (* Enrique Pérez Herrero, Dec 19 2010 *)
  • PARI
    jordantot(n,k)=sumdiv(n,d,d^k*moebius(n/d));
    A002260(n)=n-binomial(floor(1/2+sqrt(2*n)),2);
    A004736(n)=binomial(floor(3/2+sqrt(2*n)),2)-n+1;
    A059379(n)=jordantot(A004736(n),A002260(n)); \\ Enrique Pérez Herrero, Jan 08 2011
    
  • Python
    from functools import cache
    def MoebiusTrans(a, i):
        @cache
        def mb(n, d = 1):
              return d % n and -mb(d, n % d < 1) + mb(n, d + 1) or 1 // n
        def mob(m, n): return mb(m // n) if m % n == 0 else 0
        return sum(mob(i, d) * a(d) for d in range(1, i + 1))
    def Jrow(n, size):
        return [MoebiusTrans(lambda m: m ** n, k) for k in range(1, size)]
    for n in range(1, 8): print(Jrow(n, 13))
    # Alternatively:
    from sympy import primefactors as prime_divisors
    from fractions import Fraction as QQ
    from math import prod as product
    def J(n: int, k: int) -> int:
        t = QQ(pow(k, n), 1)
        s = product(1 - QQ(1, pow(p, n)) for p in prime_divisors(k))
        return (t * s).numerator  # the denominator is always 1
    for n in range(1, 8): print([J(n, k) for k in range(1, 13)])
    # Peter Luschny, Dec 16 2023

Formula

J_k(n) = Sum_{d|n} d^k*mu(n/d). - Benoit Cloitre and Michael Orrison (orrison(AT)math.hmc.edu), Jun 07 2002
From Amiram Eldar, Jun 07 2025: (Start)
For a given k, J_k(n) is multiplicative with J_k(p^e) = p^(k*e) - p^(k*e-k).
For a given k, Dirichlet g.f. of J_k(n): zeta(s-k)/zeta(s).
Sum_{i=1..n} J_k(i) ~ n^(k+1) / ((k+1)*zeta(k+1)).
Sum_{n>=1} 1/J_k(n) = Product_{p prime} (1 + p^k/(p^k-1)^2) for k >= 2. (End)

A057958 Number of prime factors of 3^n - 1 (counted with multiplicity).

Original entry on oeis.org

1, 3, 2, 5, 3, 5, 2, 7, 3, 6, 3, 8, 2, 5, 5, 10, 3, 8, 3, 10, 4, 7, 3, 11, 5, 5, 6, 9, 4, 11, 4, 12, 5, 8, 6, 12, 3, 7, 7, 13, 4, 11, 3, 11, 9, 6, 5, 17, 7, 10, 6, 9, 4, 13, 8, 13, 7, 9, 3, 17, 3, 8, 6, 14, 7, 12, 4, 12, 6, 11, 2, 16, 5, 8, 10, 11, 7, 15, 4, 18, 9, 8, 5, 18, 7, 6, 8, 16, 4, 19, 5
Offset: 1

Views

Author

Patrick De Geest, Nov 15 2000

Keywords

Crossrefs

bigomega(b^n-1): A057951 (b=10), A057952 (b=9), A057953 (b=8), A057954 (b=7), A057955 (b=6), A057956 (b=5), A057957 (b=4), this sequence (b=3), A046051 (b=2).

Programs

Formula

Mobius transform of A085028. - T. D. Noe, Jun 19 2003
a(n) = A001222(A024023(n)). - Amiram Eldar, Feb 01 2020

Extensions

Offset corrected by Amiram Eldar, Feb 01 2020

A059380 Array of values of Jordan function J_k(n) read by antidiagonals (version 2).

Original entry on oeis.org

1, 1, 1, 1, 3, 2, 1, 7, 8, 2, 1, 15, 26, 12, 4, 1, 31, 80, 56, 24, 2, 1, 63, 242, 240, 124, 24, 6, 1, 127, 728, 992, 624, 182, 48, 4, 1, 255, 2186, 4032, 3124, 1200, 342, 48, 6, 1, 511, 6560, 16256, 15624, 7502, 2400, 448, 72, 4, 1, 1023, 19682
Offset: 1

Views

Author

N. J. A. Sloane, Jan 28 2001

Keywords

Examples

			Array begins:
1, 1, 2, 2, 4, 2, 6, 4, 6, 4, 10, 4, ...
1, 3, 8, 12, 24, 24, 48, 48, 72, 72, ...
1, 7, 26, 56, 124, 182, 342, 448, 702, ...
1, 15, 80, 240, 624, 1200, 2400, 3840, ...
		

References

  • L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 199, #3.
  • R. Sivaramakrishnan, The many facets of Euler's totient. II. Generalizations and analogues, Nieuw Arch. Wisk. (4) 8 (1990), no. 2, 169-187

Crossrefs

See A059379 and A059380 (triangle of values of J_k(n)), A000010 (J_1), A059376 (J_3), A059377 (J_4), A059378 (J_5). Columns give A000225, A024023, A020522, A024049, A059387, etc.
Main diagonal gives A067858.

Programs

  • Maple
    J := proc(n,k) local i,p,t1,t2; t1 := n^k; for p from 1 to n do if isprime(p) and n mod p = 0 then t1 := t1*(1-p^(-k)); fi; od; t1; end;
  • Mathematica
    JordanTotient[n_,k_:1]:=DivisorSum[n,#^k*MoebiusMu[n/#]&]/;(n>0)&&IntegerQ[n];
    A004736[n_]:=Binomial[Floor[3/2+Sqrt[2*n]],2]-n+1;
    A002260[n_]:=n-Binomial[Floor[1/2+Sqrt[2*n]],2];
    A059380[n_]:=JordanTotient[A002260[n],A004736[n]]; (* Enrique Pérez Herrero, Dec 19 2010 *)
  • PARI
    jordantot(n,k)=sumdiv(n,d,d^k*moebius(n/d));
    A002260(n)=n-binomial(floor(1/2+sqrt(2*n)),2);
    A004736(n)=binomial(floor(3/2+sqrt(2*n)),2)-n+1;
    A059380(n)=jordantot(A002260(n),A004736(n)); \\ Enrique Pérez Herrero, Jan 08 2011

A067771 Number of vertices in Sierpiński triangle of order n.

Original entry on oeis.org

3, 6, 15, 42, 123, 366, 1095, 3282, 9843, 29526, 88575, 265722, 797163, 2391486, 7174455, 21523362, 64570083, 193710246, 581130735, 1743392202, 5230176603, 15690529806, 47071589415, 141214768242, 423644304723, 1270932914166
Offset: 0

Views

Author

Martin Wessendorf (martinw(AT)mail.ahc.umn.edu), Feb 09 2002

Keywords

Comments

An order 0 Sierpiński triangle is a triangle. Order n+1 is formed from three copies of order n by identifying pairs of corner vertices of each pair of triangles. - Allan Bickle, Aug 03 2024
This sequence represents another link from the product factor space Q X Q / {(1,1), (-1, -1)} to Sierpiński's triangle. The first "link" found was to sequence A048473. - Creighton Dement, Aug 05 2004
a(n) equals the number of orbits of the finite group PSU(3,3^n) on subsets of size 3 of the 3^(3n)+1 isotropic points of a unitary 3 space. - Paul M. Bradley, Jan 31 2017
For n >= 1, number of edges in a planar Apollonian graph at iteration n. - Andrew D. Walker, Jul 08 2017
Also the total domination number of the (n+3)-Dorogovtsev-Goltsev-Mendes graph, using the convention DGM(0) = P_2. - Eric W. Weisstein, Jan 14 2024

Examples

			Order 0 is a triangle, so a(0) = 3.
Order 1 has three corners (degree 2) and three other vertices, so a(1) = 6.
3 example graphs:                        o
                                        / \
                                       o---o
                                      / \ / \
                        o            o---o---o
                       / \          / \     / \
             o        o---o        o---o   o---o
            / \      / \ / \      / \ / \ / \ / \
           o---o    o---o---o    o---o---o---o---o
Graph:      S_1        S_2              S_3
Vertices:    3          6                15
Edges:       3          9                27
		

References

  • Peter Wessendorf and Kristina Downing, personal communication.

Crossrefs

Cf. A048473.
Cf. A007283, A029858, A067771, A193277, A233774, A233775, A246959 (Sierpiński triangle graphs).

Programs

  • Magma
    [(3/2)*(1+3^n): n in [0..30]]; // Vincenzo Librandi, Jun 20 2011
  • Mathematica
    LinearRecurrence[{4, -3}, {3, 6}, 26] (* or *)
    CoefficientList[Series[3 (1 - 2 x)/((1 - x) (1 - 3 x)), {x, 0, 25}], x] (* Michael De Vlieger, Feb 02 2017 *)
    Table[3/2 (3^n + 1), {n, 0, 20}] (* Eric W. Weisstein, Jan 14 2024 *)
    3/2 (3^Range[0, 20] + 1) (* Eric W. Weisstein, Jan 14 2024 *)

Formula

a(n) = (3/2)*(3^n + 1).
a(n) = 3 + 3^1 + 3^2 + 3^3 + 3^4 + ... + 3^n = 3 + Sum_{k=1..n} 3^n.
a(n) = 3*A007051(n).
a(0) = 3, a(n) = a(n-1) + 3^n. a(n) = (3/2)*(1+3^n). - Zak Seidov, Mar 19 2007
a(n) = 4*a(n-1) - 3*a(n-2).
G.f.: 3*(1-2*x)/((1-x)*(1-3*x)). - Colin Barker, Jan 10 2012
a(n) = A233774(2^n). - Omar E. Pol, Dec 16 2013
a(n) = 3*a(n-1) - 3. - Zak Seidov, Oct 26 2014
E.g.f.: 3*(exp(x) + exp(3*x))/2. - Stefano Spezia, Feb 09 2021
a(n) = A029858(n+1) + 3. - Allan Bickle, Aug 03 2024

Extensions

More terms from Benoit Cloitre, Feb 22 2002

A100774 a(n) = 2*(3^n - 1).

Original entry on oeis.org

0, 4, 16, 52, 160, 484, 1456, 4372, 13120, 39364, 118096, 354292, 1062880, 3188644, 9565936, 28697812, 86093440, 258280324, 774840976, 2324522932, 6973568800, 20920706404, 62762119216, 188286357652, 564859072960, 1694577218884
Offset: 0

Views

Author

Pawel P. Mazur (Pawel.Mazur(AT)pwr.wroc.pl), Apr 06 2005

Keywords

Comments

a(n) is the number of steps which are made when generating all n-step nonreversing random walks that begin in a fixed point P on a two-dimensional square lattice. To make one step means to move along one edge on the lattice.
These are also the first local maxima reached in the Collatz trajectories of 2^n - 1. - David Rabahy, Oct 30 2017
Also the graph diameter of the n-Sierpinski carpet graph. - Eric W. Weisstein, Mar 13 2018
a(n) is the number of edge covers of F_{n,2}, which has adjacent vertices u and w, and n vertices each adjacent to both u and w. An edge cover is a subset of the edges where each vertex is adjacent to at least one vertex. To cover each of the n vertices v_i, we need to have at least the edge uv_i or wv_i or both, giving us three choices for each. We can then add the edge uw or not, which is 2*3^n choices. But we need to remove the case where all uv_i's were chosen and uw not chosen, and all ww_i's were chosen and uw not chosen. - Feryal Alayont, Jun 17 2024

Crossrefs

Programs

Formula

a(n) = 2*(3^n - 1).
a(n) = 4*Sum_{i=0..n-1} 3^i.
a(n) = 4*A003462(n).
a(n) = A048473(n) - 1. - Paul Curtz, Jan 19 2009
G.f.: 4*x/((1-x)*(1-3*x)). - Eric W. Weisstein, Mar 13 2018
a(n) = 4*a(n-1) - 3*a(n-2). - Eric W. Weisstein, Mar 13 2018
From Elmo R. Oliveira, Dec 06 2023: (Start)
a(n) = 2*A024023(n).
a(n) = 3*a(n-1) + 4 for n>0.
E.g.f.: 2*(exp(3*x) - exp(x)). (End)

A133801 Number of distinct prime divisors of 3^n - 1.

Original entry on oeis.org

1, 1, 2, 2, 2, 3, 2, 3, 3, 3, 3, 5, 2, 3, 4, 5, 3, 6, 3, 5, 4, 5, 3, 7, 4, 3, 6, 6, 4, 8, 4, 6, 5, 6, 5, 9, 3, 5, 6, 7, 4, 8, 3, 8, 8, 4, 5, 12, 7, 7, 6, 6, 4, 11, 6, 9, 7, 7, 3, 12, 3, 6, 6, 7, 6, 10, 4, 9, 6, 8, 2, 12, 5, 6, 9, 8, 7, 12, 4, 11, 9, 6, 5, 14, 6, 4, 8, 12, 4, 16, 5, 7, 7, 8, 6, 15, 4, 10, 8
Offset: 1

Views

Author

Ryan Propper, Jan 06 2008

Keywords

Examples

			a(4) = omega(3^4 - 1) = omega(80) = omega(2^4 * 5) = 2.
		

Crossrefs

Programs

  • Mathematica
    Table[PrimeNu[3^n - 1], {n, 1, 50}] (* G. C. Greubel, May 21 2017 *)
  • PARI
    for(n = 1, 100, print1(omega(3^n - 1), ", "))

Formula

a(n) = omega(3^n - 1) = A001221(3^n - 1).

Extensions

Terms to a(660) in b-file from Amiram Eldar, Feb 03 2020
a(661)-a(690) in b-file from Max Alekseyev, May 22 2022

A134931 a(n) = (5*3^n-3)/2.

Original entry on oeis.org

1, 6, 21, 66, 201, 606, 1821, 5466, 16401, 49206, 147621, 442866, 1328601, 3985806, 11957421, 35872266, 107616801, 322850406, 968551221, 2905653666, 8716961001, 26150883006, 78452649021, 235357947066, 706073841201, 2118221523606
Offset: 0

Views

Author

Rolf Pleisch, Jan 29 2008

Keywords

Comments

Numbers n where the recurrence s(0)=1, if s(n-1) >= n then s(n) = s(n-1) - n else s(n) = s(n-1) + n produces s(n)=0. - Hugo Pfoertner, Jan 05 2012
A046901(a(n)) = 1. - Reinhard Zumkeller, Jan 31 2013
Binomial transform of A146523: (1, 5, 10, 20, 40, ...) and double binomial transform of A010685: (1, 4, 1, 4, 1, 4, ...). - Gary W. Adamson, Aug 25 2016
Also the number of maximal cliques in the (n+1)-Hanoi graph. - Eric W. Weisstein, Dec 01 2017
a(n) is the least k such that f(a(n-1)+1) + ... + f(k) > f(a(n-2)+1) + ... + f(a(n-1)) for n > 1, where f(n) = 1/(n+1). Because Sum_{k=1..5*3^(n-1)} 1/(a(n)+3*k-1) + 1/(a(n)+3*k) + 1/(a(n)+3*k+1) - 1/((a(n)+1+5*3^n)*5*3^(n-1)) < Sum_{k=1..5*3^(n-1)} 1/(a(n-1)+k+1) < Sum_{k=1..5*3^(n-1)} 1/(a(n)+3*k-1) + 1/(a(n)+3*k) + 1/(a(n)+3*k+1), we have 1 < 1/3 + 1/4 + ... + 1/7 < 1/8 + 1/9 + ... + 1/22 < ... . - Jinyuan Wang, Jun 15 2020

Crossrefs

Programs

Formula

a(n) = 3*(a(n-1) + 1), with a(0)=1.
From R. J. Mathar, Jan 31 2008: (Start)
O.g.f.: (5/2)/(1-3*x) - (3/2)/(1-x).
a(n) = (A005030(n) - 3)/2. (End)
a(n) = A060816(n+1) - 1. - Philippe Deléham, Apr 14 2013
E.g.f.: exp(x)*(5*exp(2*x) - 3)/2. - Stefano Spezia, Aug 28 2023

Extensions

More terms from Vladimir Joseph Stephan Orlovsky, Dec 25 2008

A168607 a(n) = 3^n + 2.

Original entry on oeis.org

3, 5, 11, 29, 83, 245, 731, 2189, 6563, 19685, 59051, 177149, 531443, 1594325, 4782971, 14348909, 43046723, 129140165, 387420491, 1162261469, 3486784403, 10460353205, 31381059611, 94143178829, 282429536483, 847288609445
Offset: 0

Views

Author

Vincenzo Librandi, Dec 01 2009

Keywords

Comments

Second bisection is A134752.
It appears that if s(n) is a first order rational sequence of the form s(1)=5, s(n)= (2*s(n-1)+1)/(s(n-1)+2),n>1, then s(n)= a(n)/(a(n)-4), n>1. - Gary Detlefs, Nov 16 2010
Mahler exhibits this sequence with n>=1 as a proof that there exists an infinite number of x coprime to 3, such that x belongs to A125293 and x^2 belongs to A005836. - Michel Marcus, Nov 12 2012

Crossrefs

Cf. A008776 (2*3^n), A005051 (8*3^n), A034472 (3^n+1), A000244 (powers of 3), A024023 (3^n-1), A168609 (3^n+4), A168610 (3^n+5), A134752 (3^(2*n-1)+2).

Programs

Formula

a(n) = 3*a(n-1) - 4, a(0) = 3.
a(n+1) - a(n) = A008776(n).
a(n+2) - a(n) = A005051(n).
a(n) = A034472(n)+1 = A000244(n)+2 = A024023(n)+3 = A168609(n)-2 = A168610(n)-3.
G.f.: (3 - 7*x)/((1 - x)*(1 - 3*x)).
a(n) = 4*a(n-1) - 3*a(n-2), a(0) = 3, a(1) = 5. - Vincenzo Librandi, Feb 06 2013
E.g.f.: exp(3*x) + 2*exp(x). - Elmo R. Oliveira, Nov 09 2023

Extensions

Edited by Klaus Brockhaus, Apr 13 2010
Further edited by N. J. A. Sloane, Aug 10 2010

A214369 Decimal expansion of Sum_{n>=1} 1/(3^n-1).

Original entry on oeis.org

6, 8, 2, 1, 5, 3, 5, 0, 2, 6, 0, 5, 2, 3, 8, 0, 6, 6, 7, 6, 1, 2, 6, 3, 1, 8, 6, 2, 2, 6, 6, 2, 4, 0, 0, 9, 6, 4, 9, 1, 9, 0, 2, 4, 8, 3, 2, 6, 9, 0, 3, 4, 1, 9, 2, 2, 8, 2, 5, 7, 8, 4, 7, 1, 3, 6, 7, 7, 1, 8, 3, 4, 7, 7, 4, 1, 7, 8, 7, 3, 2, 9, 0, 0, 9, 6, 2, 1, 2, 6, 9, 0, 3, 0, 4, 5, 3, 3, 1, 3, 7, 5, 0, 3, 2
Offset: 0

Views

Author

R. J. Mathar, Jul 14 2012

Keywords

Examples

			Equals 0.6821535026052380667...
		

Crossrefs

Programs

  • Maple
    evalf(sum(1/(3^k-1), k=1..infinity), 120); # Vaclav Kotesovec, Oct 18 2014
    # second program with faster converging series
    evalf( add( (1/3)^(n^2)*(1 + 2/(3^n - 1)), n = 1..14 ), 105); # Peter Bala, Jan 30 2022
  • Mathematica
    RealDigits[ NSum[1/(3^n - 1), {n, 1, Infinity}, WorkingPrecision -> 110, NSumTerms -> 100], 10, 105] // First (* or *) 1 - (Log[2] + QPolyGamma[0, 1, 1/3])/Log[3] // RealDigits[#, 10, 105]& // First (* Jean-François Alcover, Jun 05 2013 *)
    x = 1/3; RealDigits[ Sum[ DivisorSigma[0, k] x^k, {k, 1000}], 10, 105][[1]] (* Robert G. Wilson v, Oct 12 2014 after an observation and the formula of Amarnath Murthy, see A073668 *)
  • PARI
    suminf(n=1, 1/(3^n-1)) \\ Michel Marcus, Mar 11 2017

Formula

Equals Sum_{n>=1} 1/A024023(n).
Equals Sum_{k>=1} d(k)/3^k, where d(k) is the number of divisors of k (A000005). - Amiram Eldar, May 17 2020

Extensions

More terms from Jean-François Alcover, Feb 12 2013
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