A063079 Bisection of A001790.
1, 5, 63, 429, 12155, 88179, 1300075, 9694845, 583401555, 4418157975, 67282234305, 514589420475, 15801325804719, 121683714103007, 1879204156221315, 14544636039226909, 1804857108504066435
Offset: 1
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..200
- Petros Hadjicostas, Proof of the claim A334907(n)/n! = a(n+1)/A060818(n), 2020.
Programs
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Maple
seq(numer(binomial(2*n-3/2,-1/2)), n=1..20);
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Mathematica
Numerator[Binomial[2Range[20]-3/2,-(1/2)]] (* Harvey P. Dale, Feb 27 2012 *)
Formula
Numerators of binomial(2*n-3/2, -1/2).
Because A334907(n)/n! = a(n+1)/A060818(n) for n >= 0, the o.g.f. of a(n+1)/A060818(n), for n >= 0, is (sqrt(1 + sqrt(8*s)) - sqrt(1 - sqrt(8*s)))/sqrt(8*s * (1 - 8*s)), which is the e.g.f. of A334907 (see the link above for a proof). - Petros Hadjicostas, May 16 2020
Extensions
More terms from Vladeta Jovovic, Aug 07 2001
Comments